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3.4. PROBLEMS 51

3 Letgbe a compact simple Lie algebra. Prove that thead-invariant inner product ongis unique, up to a multiplicative constant. (Hint: Problem 12 in Chapter 1).

4 LetG be a Lie group equal to one ofSO(n)(n ≥ 3) orSU(n) (n ≥ 2), and denote its Lie algebra byg. Prove that for anyc >0

hX, Yi=−ctrace(XY),

whereX,Y ∈g, defines aAd-invariant positive definite inner product on g. Conclude that the Cartan-Killing form ofgis of this form for somec <0.

5 Explain whysl(2,R)is not a compact Lie algebra.

6 Prove that a complex Lie algebra whose realification is a compact Lie algebra must be Abelian.

7 Prove that a real Lie algebra with a positive-definite Cartan-Killing form must be zero-dimensional.

8 A Lie algebragis callednilpotentif thelower central seriesof ideals ofg C0g⊃ C1g⊃ · · · ⊃Cqg⊃ · · · ,

defined byC0g =gandCqg = [g,Cq1g]forq ≥ 1, terminates at zero, that is,Cpg= 0for somep≥1.

a. Show that the space of strictly upper triangular matrices ingl(n,R)is a nilpotent Lie algebra.

b. Check that ifgis nilpotent then, for allX ∈ g,adX is nilpotent as an endomorphism ofg(that is,admx = 0for somem >0); we say thatgis ad-nilpotent(Engel’s Theorem is the statement that everyad-nilpotent Lie algebra is nilpotent).

c. Prove that the Cartan-Killing form of a nilpotent Lie algebra is null.

9 Compute the Killing form ofgl(n,F) for F = R orC directly from the formulaadXY =XY −Y X.

10 Obtain the following expressions for the Cartan-Killing forms of the classical complex Lie algebras:

sl(n,C) :β(X, Y) = 2ntrace(XY);

so(n,C) :β(X, Y) = (n−2) trace(XY);

sp(n,C) :β(X, Y) = 2(n+ 1) trace(XY).

11 Let Gbe a compact connected Lie group of dimension at least3with Lie algebrag, and denote the Cartan-Killing form ofgbyβ.

3.A. EXISTENCE OF COMPACT REAL FORMS 53 a. Letωbe the left-invariant3-form onGwhose value at the identity is

ω1(X, Y, Z) =β([X, Y], Z)

forX,Y,Z ∈g. Prove thatωis skew-symmetric and right-invariant, so it defines a bi-invariant differential form of degree3onG.

b. In caseG=S3, show that 161 ωcoincides with the volume form, with respect to some orientation. Deduce that the bi-invariant integral on S3is given byR

S3f(g)dµ(g) =±32π12 R

S3f ωforf ∈C(S3).

3.A Existence of compact real forms

Proof of Theorem 3.3.7. (Sketch) A complex Lie algebra of dimensionncan be thought ofCnwith a skew-symmetric multiplication satisfying the Ja-cobi identity. In other words, the Lie bracket belongs to the space Vn = Λ2(Cn)⊗CCnand its coordinates satisfy quadratic polynomial equations corresponding to the Jacobi equation. Fix a basis(e1, . . . , en)ofCn. Then

µ(ei, ej) = Xn k=1

µkijek for someµkij ∈C. The Jacobi condition is

Xn m=1

mijµmkmjkµmimkiµmj) = 0

for all i, j, k, ℓ = 1, . . . , n. Now there is a closed subvariety Ln of Vn parametrizing all complexn-dimensional Lie algebras.

Consider the natural action ofG:=GL(n,C)onVn, namely, g·µ(x, y) :=g(µ(g1x, g1y))

forg ∈ G, µ ∈ Vn, x, y ∈ Cn. It amounts to “change of basis” in the Lie algebra. The idea of this proof is to find a suitable basis whose real span will be a compact real form. Thus we identify the given complex semisimple Lie algebra with (Cn, µ)and need to find g ∈ Gsuch that ν := g·µhas coordinatesνijk all real and a negative definite Cartan-Killing form on the real span of(e1, . . . , en).

Denote the Cartan-Killing form of ν ∈ Ln by Bν. By semisimplicity, may assume the basis ofCnhas been chosen so that Bµ(ei, ej) = −δij for all i, j. We shall restrict to changes of basis that preserve Bµ. This will ensure that a potential real form is compact. So let

H={g∈G|B =Bµ} and consider the orbitH(µ) =:Y.

CLAIM. Y is a closed subvariety ofLn. In order to prove the claim, let X:=G(µ)andZ ={ν∈ Ln|Bν =Bµ}. Note thatZis a closed subvariety ofLn. Plainly,Y =X∩Z. For allν ∈Z,(Cn, ν)is semisimple and

dimH(ν) = dimH−dimHν = dimH−n

is independent ofν, asHν = Aut(Cn, ν) = Der(Cn, ν)0 ∼= (Cn, ν)has di-mensionn. Now all orbits of H in Z have the same dimension. It is an elementary result of algebraic actions that the lowest dimensional orbit of HinZ is closed inZ. It follows that allH-orbits inZ are closed inZ, and hence inLn, includingY, as we wished.

EndowCnwith the Hermitian inner product such that(e1, . . . , en)is a unitary basis. This specifies a subgroupKofGisomorphic toU(n). Recall that its Lie algebrakis a real form ofg.

Consider ρµ : H → Rgiven byρµ(h) = ||hµ||2. Since H(µ) is closed inLn, there exists a point of minimum ofρµ, which we may assume to be 1∈H. Therefore

(3.A.1) 0 = (dρµ)1(A) = 2ℜ(Aµ, µ) for allA∈h. Note that

h∼=so(n,C) =so(n) +√

−1so(n)⊂u(n) +√

−1u(n) =g,

so thathis invariant under taking the transpose conjugate matrix. Now we can apply (3.A.1) to[A, A]and obtain

||Aµ||2− ||Aµ||2=ℜ([A, A]µ, µ) = 0.

This equation shows thatAµ = 0if and only ifAµ= 0, that is, alsohµis invariant under taking the transpose conjugate matrix. This means

hµ = hµ∩so(n) +hµ∩(√

−1so(n))

= hµ∩so(n) +√

−1(hµ∩so(n)).

We have shown that hµ ∩so(n) is a compact real form of hµ. But hµ = Der(Cn, µ)is isomorphic to(Cn, µ).

It remains to prove the uniqueness, up to conjugacy. We first observe that a real form of(Cn, µ)is equivalent to a critical point ofρµ. Indeed, we first compute:

µkij =−Bµ(µ(ei, ej), ek) =−Bµ(ei, µ(ej, ek)) =µijk and

δij =−Bµ(ei, ej) =−X

kℓ

µjkµkiℓ=−X

kℓ

µkiℓµkℓj =X

kℓ

µkiℓµkjℓ.

3.A. EXISTENCE OF COMPACT REAL FORMS 55 In particular,P

kℓikℓ)2=P

kℓkiℓ)2= 1for alli, and therefore X

ijk

ijk)2 =nfor allν ∈H(µ).

Hence

||ν||2=X

ijk

ijk|2 ≥X

ijk

ℜ(νijk)2 =n, and equality holds if and only if allνijk are real.

Now suppose(e1, . . . , en)is another basis ofCnwhose real span yields a compact real form ofµ. We may choose this basis so thatBµ(ei, ej) =−δij

for ali,j. Leth ∈ Gbe such thathei = ei for all i. Then ν := h1 ·µhas real coefficients in the basis(e1, . . . , ek)andBh1µ(ei, ej) = −1for alli,j.

It follows that h ∈ H. We have shown that a real form of(Cn, µ) indeed corresponds to a point of minimum ofρµonH.

Next, suppose1andh1are two points of minimumρµinH=SO(n,C).

Writeh1=kexpAfork∈SO(n)andA∈√

−1so(n).4Put f(t) =||h1·µ||2=||exp(tA)·µ||2 =X

i

e2cit||µi||2,

whereµi are the eigenvectors of Aandci the corresponding eigenvalues.

Then f is a strictly convex function unless, for each i, we have µi = 0 or ci = 0, that is, unless h1µ = kµ. Since f(0) and f(1) are points of minimum, we must haveh1µ=kµ∈(K∩H)(µ), whereK∩H=SO(n).

We have shown that the set of minima is theK∩H-orbit ofµ.

Finally,hkµ=µ, sohk∈Hµ= Aut(µ); moreover,k·spanR(e1, . . . , en) = spanR(e1, . . . , en), so

hk·spanR(e1, . . . , en) =h·spanR(e1, . . . , en) = spanR(e1, . . . , en),

as wished.

4Need to explain this Cartan decomposition.

C H A P T E R 4

Root theory

One says an endomorphismAof a real or complex vector spaceV is semisim-pleif every invariant subspace admits an invariant complement. It is easy to see that, overC, this is equivalent toAbeing diagonalizable. In this case, we can writeA=A1⊕ · · · ⊕ArandV =V1⊕ · · · ⊕Vr, whereAiis a scalar operator onVifor eachi.

In our case, for a given complex semisimple Lie algebrag(say the com-plexification of a compact Lie algebrau), we want to understand its fine structure, namely, describe its multiplication table in conceptual terms. It is very natural to look atad[g], the algebra of endomorphisms ofg gener-ated byadX, for allX∈g. We first observe thatadX :g→gis semisimple (not for allX ∈g, but) for allX ∈u, hence diagonalizable. This is already very good, but to be really useful we need a notion of simultaneous diag-onalization. A commuting family of semisimple endomorphisms can be diagonalized in the same basis. Sincead[X,Y]= [adX,adY]for allX,Y ∈g, we need to consider operatorsadX :g→gwhereXbelongs to an Abelian subalgebrah. Of course, the bigger theh, the better. This brings us to the notion of a Cartan subalgebra (CSA) of a semisimple Lie algebra.

The counterpart of a CSA on the group level is the notion of a maximal torus. IfU is a compact Lie group, there is an inner product on its Lie alge-brauwith respect to which all transformationsAdg :u→uare orthogonal and hence diagonalizable over C. In this chapter, we introduce maximal tori and CSA, but we will focus on the adjoint representation of a CSA. In later chapters, when we talk about the Weyl formulae and the Peter-Weyl theorem, we will come back to maximal tori.

4.1 Maximal tori

LetGbe a compact connected Lie group, letgdenote its Lie algebra and as-sumeGis not Abelian. We claimGcontains proper subgroups isomorphic to a torusTn = S1× · · · ×S1, withn ≥1factors. In fact, for any nonzero X ∈ g, the closure of the image of the one-parameter subgroup defined

57

byX,

{exptX |t∈R},

is a compact connected Abelian subgroup, hence isomorphic to a torus. A maximal torusofGis a torus subgroup which is not properly contained in a bigger torus. By dimensional reasons, maximal tori exist.

4.1.1 Examples





 eit1

...

eitn



t1, . . . , tn∈R





is a torusT in U(n). This is a maximal torus ofU(n) because an element g ∈ U(n) that commutes with all elements ofT must lie in T. Indeed g commutes with a diagonal matrix with all entries distinct, which implies thatgpreserves its eigenspaces inCn. Hencegis diagonal.

Similarly,



















cost1 −sint1 sint1 cost1

...

costn −sintn sintn costn







: t1, . . . , tn∈R











 is a torus inSO(2n),

























cost1 −sint1

sint1 cost1 ...

costn −sintn sintn costn

1









: t1, . . . , tn∈R

















is a torus inSO(2n+ 1), and one checks these are also maximal tori.

4.1.2 Lemma LetTn =Rn/Zn be ann-torus. ThenTn ismonogenic, that is, there isg∈Tnsuch that the cyclic grouphgigenerated bygis dense inTn.

Proof. Fix a countable basis{Ui}iNof open sets ofTn. Given any cube C0inTn(i.e. projection of a product of closed intervals inRn), we shall con-struct a descending chain of cubesC0 ⊃C1 ⊃C2 ⊃ · · · whose intersection contains a generatorgas desired.

We proceed by induction. Suppose we have already definedC0⊃C1

· · · ⊃Ci1 andCi1has sideǫ. Take an integerNi >1/ǫ. ThenCiNi1 =Tn.

4.1. MAXIMAL TORI 59 By continuity, we can find a cubeCi contained inCi1such thatCiNi ⊂Ui. Letg∈ ∩i=0Ci. ThengNi ∈Uifor alli, sohgiis dense inTn. LetT be a maximal torus ofG, and denote its Lie algebra byt. Thent is an Abelian Lie subalgebra ofg. Indeed it is amaximal Abelian subalgebra, for ifsis an Abelian subalgebra containingt, then the associated connected Lie subgroupSofGis Abelian, so its closureS¯is a torus containingT. By maximality ofT,S¯=T and thuss⊂t.

For later use, we introduce the following terminology. Let g be a Lie algebra and letΣbe a subset ofg. ThecentralizerofΣingis

Zg(Σ) ={X ∈g : [X, Y] = 0for allY ∈Σ}. ThenormalizerofΣingis

Ng(Σ) ={X ∈g : [X, Y]∈Σfor allY ∈Σ}. Note thatZg(Σ)andNg(Σ)are subalgebras ofg, by Jacobi.

Similarly, ifGis a Lie group with Lie algebrag, we can define the cen-tralizerand thenormalizerofΣinGrespectively as

ZG(Σ) ={g∈G|AdgY =Y for allY ∈Σ} and

NG(Σ) ={g∈G|AdgY ∈Σfor allY ∈Σ}. These are subgroups ofG(closed, ifΣis a closed subset ofg).

4.1.3 Theorem (É. Cartan’s Maximal Torus Theorem) Any two maximal tori in a compact connected Lie groupU are conjugate under an inner automorphism.

In particular, given a maximal torus T of G, every element of U is conjugate under an inner automorphism to an element inT; equivalently,Tintersects every conjugacy class ofG.

Proof. LetT andT be maximal tori inU. It suffices to show that their Lie algebrastandtare conjugate under the adjoint representation. Choose H ∈ t that generates a dense one-parameter subgroup ofT Thent is the centralizer ofHinu.

LetH ∈ube arbitrary and use the compactness ofU to choose a critical pointu0∈U of the smooth functionf(u) =β(H,AduH), whereβdenotes the Cartan-Killing form ofu. Then, forX∈u,

0 = d

dt

t=0β(H,Ad(exptX)u0H)

= β(H,[X,Adu0H])

= β(X,[Adu0H, H]).

Since X is arbitrary and β is negative definite, [Adk0H, H] = 0. Now Adu0H ∈t, and this proves the last assertion in the statement of the Theo-rem.

In particular, we apply the above reasoning to the caseH generates a dense one-parameter subgroup oft. Then Adu0H ∈ t implies that t ⊂ Zu(Adu0H) = Adu0Zu(H) = Adu0t. Nowdimt≤tand, by symmetry, we

obtain equality. Hencet= Adu0t.

We define the rank of a compact Lie group to be the dimension of a maximal torus. Since any two maximal tori are conjugate, they all have the same dimension.

4.1.4 Remark It follows from Theorem 4.1.3 that the exponential map of a compact connected Lie groupGis surjective. Indeed, it is explicitly surjec-tive in the case of a torus; any element ofGsits inside a maximal torusT;

sinceexpT is the restriction ofexpG, we are done (compare Remark 3.2.14).

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