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Published online December 1, 2016 c Springer International Publishing 2016

Journal of Fixed Point Theory and Applications

An iterative method for split inclusion problems without prior knowledge of operator norms

J. Y. Bello Cruz and Y. Shehu

Abstract. In this paper, we study the approximation of solution (as- suming existence) for the split inclusion problem in uniformly convex Banach spaces which are also uniformly smooth. We introduce an it- erative algorithm in which the stepsizes are selected without the need for any prior information about the bounded linear operator norm and strong convergence obtained. The novelty of our algorithm is that the bounded linear operator norm is not given a priori and stepsizes are constructed step by step in a natural way. Our results extend and im- prove many recent and important results obtained in the literature on the split inclusion problem and its variations.

Mathematics Subject Classification. 49J53, 65K10, 49M37, 90C25.

Keywords. Strong convergence, Split inclusion problem,p-uniformly convex Banach space, Uniformly smooth Banach space.

1. Introduction

LetH1 andH2 be two real Hilbert spaces,T1:H1H1 andT2: H2H2

be two set-valued maximal monotone mappings,A:H1→ H2be a bounded linear operator, andAbe the adjoint ofA. Many authors [5,10,15,17,37,38]

have studied the following split inclusion problem (SIP) in Hilbert spaces:

Findx∈ H1such that 0∈T1(x), and

0∈T2(Ax). (SIP)

The split inclusion problem has studied extensively by many authors and applied to solving many real life problems, such as in modelling intensity- modulated radiation therapy treatment planning [7,8], modelling of inverse problems arising from phase retrieval, and in sensor networks in computer- ized tomography and data compression [4,12].

Next, we give some examples which serve as motivations for studying the split inclusion problem and to understand its relationship with other problems in the literature. Byrne et al. [6] studied a split inverse problem (SInvP) formulated in Sect. 2 of [9] which concerns a model in which there

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are two given vector spacesX1andX2and a linear operatorA:X1→ X2. In this model, two Inverse Problems (IP) are involved. The first one, denoted by (IP1), is formulated in the spaceX1, and the second one, denoted by (IP2), is inX2. Given these data, the Split Inverse Problem (SInvP) is formulated

as follows:

Find x∈ X1 solving (IP1), and

Ax∈ X2 solves (IP2). (SInvP)

Now, recall the split variational inequality problem (SVIP) introduced in [9], which is an SIP with a variational inequality problem (VIP) in each one of the two spaces. LetH1andH2be two real Hilbert spaces, and assume that there are given two point-to-point operators F1:H1 → H1 and F2: H2 → H2, a bounded linear operator A: H1 → H2, and nonempty, closed, and convex subsets Ω1⊆ H1 and Ω2⊆ H2. The SVIP is then formulated as follows:

FindxΩ1 such that F1(x), x−x0, ∀x∈Ω1, and

y=AxΩ2 solves F2(y), y−y0, ∀y∈Ω2. (SVIP) The above problem (SVIP) can be structurally considered a special case of the split monotonic variational inclusion problem (SMVIP) when the operators F1 andF2are monotones. It is formulated as follows:

Findx SOL(F1,Ω1) such that

Ax SOL(F2,Ω2), (SMVIP)

where we denote by SOL(F1,Ω1) and SOL(F2,Ω2) the solution sets of the VIPs in (SVIP). Taking in (SMVIP), Ω1 =H1,Ω2=H2 and choosing x:=

x−F1(x)∈ H1 and y=Ax−F2(Ax)∈ H2, we obtain the Split Zeros Problem (SZP) for two operators F1:H1 → H1 and F2:H2 → H2, which were introduced in Sect. 7.3 of [9]. It is formulated as follows:

Findx∈ H1 such thatF1(x) = 0 and

F2(Ax) = 0. (SZP)

Furthermore, we can define the set-valued mappingT1: Ω1⊂ H1H1 by T1(x) :=

F1(x) +NΩ1(x), xΩ1

∅, Otherwise,

andT2: Ω2⊂ H2H2 by T2(y) :=

F2(y) +NΩ2(y), yΩ2

∅, Otherwise,

whereNΩ: HHis the normal cone of some nonempty, closed, and convex set Ω⊂ H, which is defined at a point u∈Ω as

NΩ(u) :={d∈ H:d, u−v ≤0, ∀u∈Ω},

and the empty set otherwise. Then, under maximal monotonicity assumption onF1andF2, Theorem 3 of [19] implies thatT1andT2are maximal monotone mappings and so x SOL(F1,Ω1) and Ax SOL(F2,Ω2) if and only if 0 ∈T1(x) and 0 ∈T2(Ax), respectively. Hence, we observe that problem (SMVIP) is a special case of Split Inclusion Problem defined in (SIP). Thus, SIP is a remalkable problem, which contains a large class of applications;

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for further discussions of this problem, the reader can see [10,17] and the references therein.

Some notations and definitions on uniformly convex Banach spaces

We start this part by recalling some definitions and notation used in this paper, which are standard and follows from [3,39]. Throughout this paper, we write S := R to indicate that S is defined to be equal to R. Let B be a real Banach space. The modulus of smoothness of B is the function ρB: [0,∞)→[0,∞) defined by

ρB(t) := sup 1

2(x+y+x−y)−1 :x ≤1,y ≤t

.

We assume that 1< p, q <∞such that 1p+1q = 1. Bisuniformly smoothif and only if

t→0lim ρB(t)

t = 0,

andq-uniformly smooth if there exists aCq >0, such that ρB(t)≤Cqtq for anyt >0.

Let dim B ≥ 2. The modulus of convexity of B is the function δB : (0,2][0,1] defined by

δB() := inf

1−x+y 2

:x=y= 1;=x−y

.

Bisuniformly convexif and only ifδB()>0 for all(0,2] andp-uniformly convexif there is aCp>0, so thatδB()≥Cppfor any(0,2]. The uniform convexity is a geometric property of the unit ball. In particular, the unit sphere must be round and cannot include any line segment. Surprisingly, this geometric property ensures a topological one. That is, it follows from Milman–

Pettis’ Theorem that every uniformly convex Banach space is reflexive; see Theorem 3.31 of [3].

It is well known thatB isp-uniformly convex and uniformly smooth if and only if its dualB is q-uniformly smooth and uniformly convex. Then, from now on, mainly in Sect.3, we assume thatBisp-uniformly convex and uniformly smooth with constantCpand we denoteCq with 1/p+ 1/q= 1 the associated constant toB. It is also a common knowledge that the duality mappingJpB is one-to-one, single valued and satisfiesJpB= (JqB)−1, where JqB is the duality mapping ofB (see [1,11]).

Definition 2.1. The duality mappingJpB:BB is defined by JpB(x) :=

x∈ B:x, x=xp,x=xp−1 .

We denote it asJ whenp= 1 and the domain spaceBis clear. The duality mappingJpB is said to be weak-to-weak star continuous if

xn x⇒ JpB(xn), y → JpB(x), y

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holds true for any y ∈ B. We note here that lp(p > 1) spaces have such a property, butLp(p >2) does not share this property.

LetB be a reflexive, strictly convex, and smooth Banach space and let T:BB be a maximal monotone operator. Then, for λ >0 and x∈ B, consider the metric resolvent ofT, forλ >0, as

JλT(x) :={z∈ B: 0∈ J(z−x) +λT(z)}

or equivalentlyJλT = (I+λJ−1T)−1:B → B, which is point-to-point, full domain, and nonexpansive operator. Then

0≤ JλT(x)−JλT(y),J(x−JλT(x))− J(y−JλT(y)) holds, for allx, y∈ B; see, for instance, Proposition 57.5(b) of [40].

In addition, we consider the relative resolvent ofT, forλ >0, as QλT(x) :={z∈ B:J x∈J z+λT(z)},

or equivalently QλT = (J +λT)−1J: B → B, which is point-to-point and relatively nonexpansive mapping. That is, forλ >0,

0≤ QλT(x)−QλT(y),J(x)− J(QλT(x))(Jy−QλT(y)) for allx, y∈ B; see, Theorem 5.2. of [27].

Previous related schemes and our proposal

In this part, we describe some previous schemes, which use the norm of the operatorA to find the stepsizes. In 2011, Byrne et al. [5] gave the following convergence theorem for the split inclusion problem (SIP) working in Hilbert spaces.

Theorem 1.1 (Theorem 3.2 of [5]). Let H1 and H2 be real Hilbert spaces, A: H1 → H2 be a linear and bounded operator, and A denote the adjoint ofA. LetT1:H1H1 and T2:H2H2 be set-valued maximal monotone mappings,λ >0andγ∈

0,A2A

. Suppose thatΓ=∅, the solution set of (SIP). The sequence(xn)n∈N defined as follows:

xn+1=JλT1 xn−γA

I−JλT2

Axn

converges weakly to an elementxΓ.

Furthermore, in 2013, Chuang [10] gave the following strong convergence theorem for problem (SIP).

Theorem 1.2 (Theorem 4.1 of [10]). Let H1 and H2 be real Hilbert spaces, A: H1 → H2 be a linear and bounded operator, and A denote the ad- joint of A. Let T1: H1H1 and T2: H2H2 be set-valued maximal monotone mappings. Letn)n∈N(0,1), (λn)n∈N be a sequence in(0,∞) andn)n∈N

0,2/(A2+ 2)

. Let Γ be the solution set of (SIP) and suppose thatΓ=∅. Let (xn)n∈N be defined by

xn+1=JλnT1 (1−αnγn)xn−γnA

I−JλnT2

Axn

, n≥1.

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Assume that

n→∞lim αn= 0, n=1

αnγn=∞, lim inf

n→∞γn>0, lim inf

n→∞λn>0.

Then, limn→∞xn = ¯x:= PΓ0, that is, ¯x is the minimal norm solution of (SIP).

Recently, Takahashi and Takahashi [29] considered the problem (SIP) in uniformly convex and smooth Banach spaces, which are higher spaces other than Hilbert spaces. In other words, let B1 and B2 be two real uniformly convex and smooth Banach spaces,T1: B1B1 and T2: B2B2 be two set-valued maximal monotone mappings,A: B1 → B2 be a bounded linear operator, and A:B2 → B1 be the adjoint ofA. Takahashi and Takahashi [29] studied the Split Inclusion Problem given in (SIP) in Banach spaces, that

is

Findx∈ B1 such that 0∈T1(x), and

0∈T2(Ax). (SIPB)

Let the set of solutions of the split inclusion problem (SIPB) be denoted by Γ.

Using the shrinking projection method, Takahashi and Takahashi [29] proved the following strong convergence theorem for finding a solution of (SIPB) in uniformly convex and smooth Banach spaces.

Theorem 1.3 (Theorem 6 of [29]). Let B1 and B2 be uniformly convex and smooth Banach spaces and let JB1 and JB2 be the duality mappings on B1 and B2, respectively. Let T1: B1B1 and T2: B2B2 be maximal monotone operators, such thatT1−1(0)=∅ andT2−1(0)=∅, respectively. Let QλT2 be the relative resolvent ofT2 forλ >0. Let A:B1→ B2 be a bounded linear operator, such that A = 0 and let A be the adjoint operator of A.

Suppose that Γ = ∅. Let x1 ∈ B1 and let C1 = T1−1(0). Let (xn)n∈N be a sequence generated by

⎧⎨

zn =xn−tn(JB1)−1AJB2(Axn−QλnT2(Axn)), Cn+1=

z∈Cn :zn−z,JB1(xn−zn) ≥0 xn+1 =PCn+1x1, ∀n≥1,

(1.1) where {tn},n)n∈N (0,∞) satisfy the conditions, such that for some a, b, c∈R

0< a≤tnA2≤b <1 and 0< c≤λn, ∀n≥1.

Then, the sequence(xn)n∈Nconverges strongly to a pointz0Γ, where z0= PΓx1.

Closely studying the result of Takahashi and Takahashi [29], we see that the choice of step-sizetn is operator norm dependent. This is a drawback in terms of efficiency and implementation of the iteration process (1.1). Further- more, the setCn has to be computed in each iteration step in the iteration process (1.1). This makes the iteration process (1.1), above, computationally expensive, because the complexity of the proposed iteration grows dramat- ically whenn is large. Note that the set where is doing the projection step can be written as

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Cn+1=Cn∩ {z∈ B1:zn−z,JB1(xn−zn) ≥0}

=n=2{z∈C1:z−z,JB1(x−z) ≥0}.

Moreover, it is worth mentioning that in most of the results on the split inclusion problem studied so far, the choice of the stepsize depends on the operator normA. This involves knowing a priori the norm (or at least an estimate of the norm) of the bounded linear operator, which is in general not an easy work in practice. Hence, it makes the implementation of the iteration process inefficient when the computation of the operator normA is not explicit (see [13,16]). Even in finite dimensions, computing the norm of bounded linear operator is a difficult task as shown by the following Theorem of Hendrickx and Olshevsky [14]:

Theorem 1.4 (Theorem 2.3 of [14]). For any rational p∈ [1,∞)except p= 1,2, unless P =N P, there is no algorithm which computes the p-norm of a matrix with entries in{−1,0,1} to relative error with running time poly- nomial in the dimensions.

These observations lead to the following natural question.

Question: Can we obtain strong convergence result for the split inclusion problem in higher spaces other than Hilbert spaces in which the iteration process is operator norm independent for solving the Split Inclusion Problem (SIP)? Moreover, could the proposed iteration process be more efficient and implementable than the iteration processes already obtained for the split inclusion problem in the literature?

Our main purpose, in this paper, is to give an affirmative answer to the above question. Thus, we propose an iterative scheme, which generated a sequence strongly convergent to some solution of the split inclusion problem inp-uniformly convex real Banach spaces which are also uniformly smooth.

The proposed iteration process is constructed in such a way that we do not need to know a priori the norm or an estimate of the norm of the bounded linear operator for approximating solution of the split inclusion problems and so it can be more efficiently implemented. Our results complement and extend many recent and important results on the split inclusion problems both in Hilbert spaces and Banach spaces.

Organization of the paper: The next subsection provides some preliminar- ies results that will be used in the remainder of this paper. In Sect. 3, the proposed algorithm and its strong convergence are analyzed by choosing step- sizes without norm dependence, and moreover, we remark some consequences.

Finally, Sect.4gives some concluding remarks.

2. Preliminaries

This section discusses some preliminary results which will be used throughout the paper.

Lemma 2.1 (Corollary 1 of [34]). Let x, y∈ B. If B isq-uniformly smooth Banach space, then there existsCq >0, such that

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x−yq≤ xq−qJq(x), y+Cqyq. (2.1) Definition 2.2. Let B be a p-uniformly convex real Banach spaces which is also uniformly smooth. Given a Gˆateaux differentiable convex function f:B →R, theBregman distancewith respect to f is defined as

Δf(x, y) =f(y)−f(x)− f(x), y−x, x, y∈ B.

We note here also that the duality mappingJpB is in fact the derivative of the functionfp(x) := 1pxp, for 2≤p <∞. Hence, the Bregman distance with respect tofp (see [24]) is given by

Δp(x, y) =1

qxp− JpB(x), y+1

pyp. (2.2)

In addition, the Bregman distance possesses the following important properties:

Δp(x, y) = Δp(x, z) + Δp(z, y) +

z−y,JpB(x)− JpB(y)

, ∀x, y, z∈ B. (2.3) Δp(x, y) + Δp(y, x) =

x−y,JpB(x)− JpB(y)

, ∀x, y∈ B. (2.4) When considering thep-uniformly convex space, the Bregman distance and the metric distance have the following relation (see (7) of [21]):

τx−ypΔp(x, y)

x−y,JpB(x)− JpB(y)

, (2.5)

whereτ >0 is some fixed number.

Let Ω be a nonempty, closed, and convex subset ofB. The metric pro- jection

PΩx:= arg min

y∈Ωx−y, x∈ B,

is the unique minimizer of the norm distance, which can be characterized by a variational inequality:

JpB(x−PΩx), z−PΩx ≤0, ∀z∈Ω. (2.6) Similar to the metric projection, the Bregman projection is defined as

ΠΩx= arg min

y∈ΩΔp(x, y), x∈ B,

the unique minimizer of the Bregman distance (see Proposition 1.25 of [20]).

The Bregman projection can also be characterized by a variational inequality:

JpB(x)− JpBΩx), z−ΠΩx ≤0, ∀z∈Ω, (2.7) from which one has

ΔpΩx, z)≤Δp(x, z)Δp(x,ΠΩx), ∀z∈Ω. (2.8) Following [1] [see equation (6.3), page 29], we make use of the functionVp : B× B →[0,+), which is defined by

Vp(x, y) := 1

qxq− x, y+1

pyp, ∀x∈ B, y∈ B.

Then, Vp is nonnegative and Vp(x, y) = Δp(JqB(x), y) for all x ∈ B and y∈ B. Moreover, by the subdifferential inequality

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f(x), y−x ≤f(y)−f(x),

withf(x) =1qxq, x∈ B, then f(x) =JqB. Then, we have JqB(x), y1

qx+yq1

qxq (2.9)

and from (2.9), we obtain (see [24])

Vp(x+y, x)≥Vp(x, x) +y,JqB(x)−x, (2.10) for all x∈ B and x, y ∈ B. In addition, since f = fp is a proper lower semi-continuous and convex function, we have f = fp is a proper weak lower semi-continuous and convex function; see [18]. Hence, Vp is convex in the second variable. Thus, for allz∈ B, we can show that (see [24])

Δp

JqBN

i=1

tiJpB(xi) , z

≤Vp N

i=1

tiJpB(xi), z

= N i=1

tiΔp(xi, z) (2.11) where (xi)i=1,...,N ⊂ Band (ti)i=1,...,N (0,1) with N

i=1ti = 1.For more details, see [22,23,25,26,32].

We need the following useful lemma in the sequel.

Lemma 2.2 (Lemma 2.5 of [35]). Let (an)n∈N be a sequence of nonnegative real numbers satisfying the following relation:

an+1(1−αn)an+αnσn+γn, n≥0,

wheren)n∈N,n)n∈Nandn)n∈Nare sequences of real numbers satisfying (i) (αn)n∈N[0,1],

αn =; (ii) lim supn→∞σn 0;

(iii) γn 0,

γn<∞.

Then,an0 asn→ ∞.

3. Main results

Using the ideas of [41], we introduce an iterative algorithm in which the step- size does not depend on the normAand then prove the strong convergence of the sequence generated by the algorithm inp-uniformly convex real Banach spaces which are also uniformly smooth.

AlgorithmLetB1andB2be twop-uniformly convex real Banach spaces which are also uniformly smooth. LetT1:B1B1 and T2:B2B2 be maximal monotone operators, such thatT1−1(0)=∅andT2−1(0)=∅, respectively. Let JλT1 andQλT2, forλ >0, be the metric and relative resolvents ofT1 andT2, respectively. LetA:B1→ B2 be a bounded linear operator, such thatA= 0 andA:B2 → B1 be the adjoint of A. For a fixedu∈ B1, choose an initial guessx1∈ B1 arbitrarily. Let (αn)n∈N [0,1]. Assume that the nth iterate xn ∈ B1has been constructed; then, we calculate the (n+ 1)th iteratexn+1 via the formula:

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un=JqB1

JpB1(xn)−tnAJpB2(I−QλT2)Axn , xn+1=JqB1 αnJpB1(u) + (1−αn)JpB1(JλT1(un))

. (3.1)

Let the stepsizetn be chosen in such a way that tq−1n

0,

q(I−QλT2)Axnp CqAJpB2(I−QλT2)Axnq

, n∈Ω, (3.2) where the index set Ω :={n∈N: (I−QλT2)Axn = 0} otherwisetn =t (t being any nonnegative value).

Before the formal analysis of the convergence properties of the algorithm (3.1)–(3.2), we note that the step-sizetn does need compute the norm of any operator, and also, it is possible to use a backtracking procedure to find it without multiple evaluations of the vector norm.

In the following, we present two lemmas establishing that the proposed algorithm is well-defined and the generated sequences are bounded.

Lemma 3.1. Suppose that the split inclusion problem (SIPB) has a nonempty solution setΓ. Then,tn defined by (3.2)is well defined.

Proof. First, we observe that in algorithm (3.1)–(3.2) the choice of the step- sizetn is independent of the normA. In addition, the value of tdoes not influence the considered algorithm, but it was introduced just for the sake of clarity. Furthermore, we show thattn is well defined. Now, letx∈Γ. Then, Ax=QλT2Ax. Hence

(I−QλT2)Axnp

=JpB2(I−QλT2)Axn,(I−QλT2)Axn

=JpB2(I−QλT2)Axn, Axn−Ax+QλT2Ax−QλT2Axn

=JpB2(I−QλT2)Axn, Axn−Ax

+JpB2(I−QλT2)Axn, QλT2Ax−QλT2Axn

=AJpB2(I−QλT2)Axn, xn−x

+JpB2(I−QλT2)Axn, QλT2Ax−QλT2Axn

≤ AJpB2(I−QλT2)Axnxn−x

+JpB2(I−QλT2)AxnQλT2Ax−QλT2Axn

=AJpB2(I−QλT2)Axnxn−x

+(I−QλT2)Axnp−1QλT2Ax−QλT2Axn.

Consequently, forn∈Ω, that is,(I−QλT2)Axn>0, we getAJpB2(I QλT2)Axnxn−x>0 and(I−QλT2)Axnp−1QλT2Ax−QλT2Axn>0.

SinceAJpB2(I−QλT2)Axnxn−x>0, then we obtain thatAJpB2(I QλT2)Axn = 0. This implies thattn is well defined.

Lemma 3.2. Let B1 and B2 be two p-uniformly convex real Banach spaces which are also uniformly smooth. Let T1: B1B1 and T2: B2B2 be

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maximal monotone operators, such thatT1−1(0)=∅andT2−1(0)=∅, respec- tively. LetQλT2 be the metric resolvent of T2 forλ >0. Let A:B1→ B2 be a bounded linear operator, such thatA= 0andA:B2 → B1 be the adjoint ofA. Suppose that Γ=∅ andn)n∈N(0,1). Let the sequence (xn)n∈N be generated by (3.1)–(3.2). Assume that for small enough >0,

tn

,

q(I−QλT2)Axnp

CqAJpB2(I−QλT2)Axnq q−11

, n∈Ω.

Then, the sequences(xn)n∈N and(un)n∈N are bounded.

Proof. It follows from (2.6) that for anyz∈Γ, where Γ is the solution set of problem (SIPB), we have

JpB2((I−QλT2)Axn), Axn−Az

=Axn−QλT2(Axn)p+JpB2((I−QλT2)Axn), QλT2(Axn)−Az

≥ Axn−QλT2(Axn)p. (3.3)

In addition, from (3.3) and Lemma2.1, we obtain that

Δp(un, z)≤Δp(JqB1[JpB1(xn)−tnAJpB2(I−QλT2)Axn], z)

=1

qJpB1(xn)−tnAJpB2((I−QλT2)Axn)q− JpB1(xn), z +tnJpB2((I−QλT2)Axn), Az+1

pzp

1

qJpB1(xn)q−tnAxn,JpB2((I−QλT2)Axn) +Cqtqn

q AJpB2(I−QλT2)Axnq

− JpB1(xn), z+tnAz,JpB2((I−QλT2)Axn)+1 pzp

=1

qxnp− JpB1(xn), z+1 pzp +tnJpB2((I−QλT2)Axn), Az−Axn +Cqtqn

q AJpB2(I−QλT2)Axnq

= Δp(xn, z) +tnJpB2(I−QλT2)Axn, Az−Axn +Cqtqn

q AJpB2(I−QλT2)Axnq. (3.4) Now, using (3.3) in (3.4), we obtain

Δp(un, z)≤Δ(xn, z)−tn(I−QλT2)Axnp+ Cqtqn

q AJpB2(I−QλT2)Axnq

= Δ(xn, z)−tn (I−QλT2)Axnp−Cqtq−1n

q AJpB2(I−QλT2)Axnq . (3.5)

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By the condition ontn, it follows from (3.5) that Δp(un, z)≤Δp(xn, z).

Furthermore, using (2.8) in (3.1), we get that Δp(xn+1, z)≤Δp

JqB1 αnJpB1(u) + (1−αn)JpB1(un)

, z

=αnΔp(u, z) + (1−αnp(un, z)

≤αnΔp(u, z) + (1−αnp(xn, z)

max{Δp(u, z),Δp(xn, z)} ...

max{Δp(u, z),Δp(x1, z)}. (3.6) Therefore, (Δp(xn, z))n∈N is bounded and consequently, the sequence (Δp(un, z))n∈N is bounded. Thus, the sequences (xn)n∈N and (un)n∈N are

bounded.

Now, we proceed by proving strong convergence of the sequence gener- ated by Algorithm (3.1)–(3.2).

Theorem 3.3. Let B1 and B2 be two p-uniformly convex real Banach spaces which are also uniformly smooth. Let T1: B1B1 and T2: B2B2 be maximal monotone operators, such thatT1−1(0)=∅andT2−1(0)=∅, respec- tively. LetQλT2 be the metric resolvent of T2 forλ >0. Let A:B1→ B2 be a bounded linear operator such that A= 0 andA:B2 → B1 be the adjoint ofA. Suppose that Γ=∅ andn)n∈N(0,1). Let the sequence (xn)n∈N be generated by (3.1)–(3.2). Assume that for small enough >0:

tn

,

q(I−QλT2)Axnp

CqAJpB2(I−QλT2)Axnq q−11

, n∈Ω.

Suppose the following conditions are satisfied:

(i) limn→∞αn = 0;

(ii)

n=1αn=∞.

Then,(un)n∈N and(xn)n∈N both converge strongly tox, where¯ x¯= ΠΓu.

Proof. Let ¯x= ΠΓuand let us setvn :=JqB1 αnJpB1(u) + (1−αn)JpB1(un)

, n≥1. Then, using (2.10) and (2.11), we obtain

Δp(xn+1,x¯)Δp(JqB1 αnJpB1(u) + (1−αn)JpB1(un) ,x¯)

=VpnJpB1(u) + (1−αn)JpB1(un),x)¯

≤Vp(αnJpB1(u) + (1−αn)JpB1(un)−αn(JpB1(u)− JpB1x)),x¯)

− −αn(JpB1(u)− JpB1x)),JqB1 αnJpB1(u) + (1−αn)JpB1(un) −x¯

=Vp(αnJpB1x) + (1−αn)JpB1(un),¯x) +αnJpB1(u)− JpB1x), vn¯x

= Δp(JqB1 αnJpB1x) + (1−αn)JpB1(un)

,x¯) +αnJpB1(u)− JpB1x), vn−x¯

≤αnΔpx,x) + (1¯ −αnp(un,x) +¯ αnJpB1(u)− JpB1x), vn−x¯

Referências

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