arXiv:1601.03218v1 [math.CV] 13 Jan 2016
(will be inserted by the editor)
Constructive description of Hardy-Sobolev spaces in C
nAlexander Rotkevich
Received: date / Accepted: date
Abstract In this paper we study the polynomial approximations in Hardy- Sobolev spaces on for convex domains. We use the method of pseudoanalytical continuation to obtain the characterization of these spaces in terms of poly- nomial approximations.
Keywords Hardy-Sobolev Spaces·polynomial approximations, pseudoana- lytical continuation·Cauchy-Leray-Fantappi`e integral.
Mathematics Subject Classification (2010) 32E30·41A10
1 Introduction
The purpose of this paper is to give an alternative characterizations of Hardy- Sobolev (see. [1]) spaces
Hpl(Ω) ={f ∈H(Ω) :kfkHp(Ω)+ X
|α|≤l
k∂αfkHp(Ω)<∞} (1) on strongly convex domainΩ⊂Cn.
We continue the research started in [14] and devoted to description of basic spaces of holomorphic functions of several variables in terms of polynomial approximations and pseudoanalytical continuation. In particular, we show that for 1 < p < ∞ and l ≥ 1 a holomorphic on a strongly convex domain Ω function f is in the Hardy-Sobolev spaceHpl(Ω) if and only if there exist a polynomial sequenceP2k such that
Z
∂Ω
dσ(z)
∞
X
k=1
|f(z)−P2k(z)|222lk
!p/2
<∞. (2)
Alexander Rotkevich
Mathematics and Mechanics Faculty, St.Petersburg State University, Universitetsky pr., 28, Peterhof, St. Petersburg, Russia.
E-mail: [email protected]
In the one variable case this condition follows from the characterization ob- tained by E.M. Dynkin [5] for Radon domains.
The paper is divided into five sections with one appendix. In section 2we give main definitions and preliminaries of this work. Section3is devoted to the Cauchy-Leray-Fantappi`e integral formula, the polynomial approximations and estimates of its kernel. We also define internal and external Kor´anyi regions, the multidimensional analog of Lusin regions. In section 4 we introduce the method of pseudoanalytical continuation and three constructions of the con- tinuation with different estimates. We use these constructions to obtain the characterization of Hardy-Sobolev spaces in terms of estimates of the pseudo- analytical continuation. To prove this result we use the special analog of the Krantz-Li area-integral inequality [7] for external Kor´anyi regions established in appendixA. Finally, section5 contains the proof of characteristics (2).
2 Main notations and definitions
Let Cn be the space of n complex variables, n ≥ 2, z = (z1, . . . , zn), zj = xj+iyj;
∂jf = ∂f
∂zj
= 1 2
∂f
∂xj −i∂f
∂yj
, ∂¯jf = ∂f
∂z¯j
= 1 2
∂f
∂xj
+i∂f
∂yj
,
∂f =
n
X
k=1
∂f
∂zk
dzk, ∂f¯ =
n
X
k=1
∂f
∂¯zk
d¯zk, df=∂f+ ¯∂f.
The notation
h∂f(z), wi=
n
X
k=1
∂f(z)
∂zk
wk.
is used to indicate the action of∂f on the vectorw∈Cn,and
|∂f¯ |=
∂f
∂z1
+. . .+
∂f
∂zn
.
The euclidian distance form the pointz∈Cn to the setD⊂Cn we denote as dist(z, D) = inf{|z−w| :w∈D}. Lebesgue measure inCn we denote as dµ.
For a multiindexα= (α1, . . . , αn)∈Nn we set|α| = α1 + . . . + αn
andα! =α1!. . . α2!,alsozα=z1α1. . . zαnn and∂αf = ∂z¯α1∂|α|f 1 ...∂¯zαnn .
Let Ω = {z∈Cn:ρ(z)<0} be a strongly convex domain with a C3- smooth defining function. We need to consider a family of domains Ωt = {z∈Cn:ρ(z)< t}that are also strongly convex for each|t|< ε,whereε >0 is small enough. The projection ofz∈Ωε\Ω−ε to the∂Ω we define asπ(z).
Forξ∈∂Ωtwe define the complex tangent space Tξ={z∈Cn :h∂ρ(ξ), ξ−zi= 0}.
The space of holomorphic functions we denote asH(Ω) and consider the Hardy space (see [17], [6])
Hp(Ω) :=
f ∈H(Ω) : sup
−ε<t<0
Z
∂Ωt
|f(z)|pdσt(z)<∞
,
wheredσtis induced Lebesgue measure on the boundary ofΩt.We also denote dσ=dσ0.Hardy-Sobolev spacesHpl(Ω) are defined by (1).
Throughout this paper we use notations., ≍.We letf .g iff ≤cgfor some constant c >0, that doesn’t depend on main arguments of functionsf andg and usually depend only on dimension nand domainΩ.Alsof ≍g if c−1g≤f ≤cgfor somec >1.
3 Cauchy-Leray-Fantappi`e formula
In the context of theory of several complex variables there is no unique repro- ducing formula formula, however we could use the Leray theorem, that allows us to construct holomorphic reproducing kernels ([2], [11], [12]). For convex do- mainΩ={z∈Cn:ρ(z)<0}this theorem brings us Cauchy-Leray-Fantappi`e formula, and forf ∈H1(Ω) andz∈Ω we have
f(z) =KΩf(z) = 1 (2πi)n
Z
∂Ω
f(ξ)∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1 h∂ρ(ξ), ξ−zin =
Z
∂Ω
f(ξ)K(ξ, z)ω(ξ), (3) whereω(ξ) = (2πi)1 n∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1,andK(ξ, z) =h∂ρ(ξ), ξ−zi−n.
The (2n−1)-formωdefines on∂ΩtLeray-Levy measuredS,that is equiv- alent to Lebesgue surface measuredσt(for details see [2], [9], [10]). This allows us to identify Lebesgue, Hardy and Hardy-Sobolev spaces defined with respect to measuresdσt anddS. Also note, that measuredV defined by the 2n-form dω= (∂∂ρ)¯ n is equivalent to Lebesgue measure dµin Cn.
By [13] the integral operatorKΩ defines a bounded mapping onLp(∂Ω) toHp(Ω) for 1< p <∞.
The function d(w, z) = |h∂ρ(w), w−zi| defines on ∂Ω quasimetric, and if B(z, δ) = {w ∈ ∂Ω : d(w, z) < δ} is a quasiball with respect to d then σ(B(z, δ))≍ δn, see for example [13]. Therefore{∂Ω, d, σ} is a space of ho- mogeneous type.
Note also the crucial role in the forthcoming considerations of the following estimate that is proved in [14].
Lemma 3.1 Let Ω be strongly convex, then
d(w, z)≍ρ(w) +d(π(w), z), w∈Cn\Ω, z∈∂Ω.
3.1 The polynomial approximation of Cauchy-Leray-Fantappi´e kernel
In lemma 3.3 here we construct a polynomial approximations of Cauchy- Leray-Fantappi´e kernel based on theorem by V.K. Dzyadyk about estimates of Cauchy kernel on domains on complex plane (theorem 1 in part 1 of sec- tion 7 in [3]). The approximation is choosed similarly to [16] and [15]. This construction allows us in theorem 5.1 to get polynomials that approximate holomorphic function with desired speed.
Lemma 3.2 Let Ω be a strongly convex domain with 0 ∈ Ω, then for every ξ∈Ωε\Ωthe value of λ= h∂ρ(ξ), zih∂ρ(ξ), ξi for z∈Ω lies in domain L(t), bounded by the bigger arc of the circle |λ|= R =R(Ω) and the chord {λ∈ C: λ = 1 +eits, s∈R, |λ| ≤R}, wheret= π2−arg(h∂ρ(ξ), ξi).
Proof Forξ∈∂Ω define Λ(ξ) =
λ∈C:λ=h∂ρ(ξ), zi
h∂ρ(ξ), ξi, z ∈Ω
. The convexity ofΩwith 0∈Ωimplies that
|h∂ρ(ξ), ξi|&|∂ρ(ξ)| |ξ|&1, (4) Reh∂ρ(ξ), z−ξi ≤0, z∈Ω, ξ¯ ∈Ωε\Ω. (5) The domainL(ξ)⊂Cis also convex and contains 0, thus the equality
h∂ρ(ξ), zi
h∂ρ(ξ), ξi = 1 +h∂ρ(ξ), z−ξi h∂ρ(ξ), ξi with estimates (4), (5) completes the proof of the lemma.
Lemma 3.3 Let Ω be a strongly convex domain and r > 0. Then for every k∈N there exist functionKk(ξ, z) defined for ξ∈Ωε\Ωand polynomial in z∈Ω withdegKk(ξ,·)≤kand following properties:
K(ξ, z)−Kkglob(ξ, z) . 1
kr 1
d(ξ, z)d+r, d(ξ, z)≥ 1
k; (6)
Kkglob(ξ, z)
.kn, d(ξ, z)≤ 1
k. (7)
Proof Due to [3] and [16] for anyj∈Nthere exists function Tj(t, λ) polyno- mial inλwith degTj(t,·)≤j such that
1
1−λ−Tj(t, λ)
. 1 jr
1
|1−λ|1+r (8) forλ∈L(t)\n
λ:|1−λ|< 1jo
and coefficients of polynomialsTj(t, λ) contin- uously depend ont.Note also that by maximum principle
Tj(t, λ).j−1, λ∈L(t)\
λ:|1−λ|<1 j
. (9)
Forj∈Nand (j−1)< k≤jndefine Kkglob(ξ, z) =Kjnglob(ξ, z) = 1
h∂ρ(ξ), ξinTjn
t(ξ),h∂ρ(ξ), zi h∂ρ(ξ), ξi
. Due to definition ofTj polynomialsKkglob(ξ,·) satisfy relations (6) - (7).
3.2 Kor´anyi regions
Forξ∈∂Ω andε >0 we define the inner Kor´anyi regionas Di(ξ, η) ={τ∈Ω:π(τ)∈B(ξ,−ηρ(τ)), ρ(τ)>−ε}.
The strong convexity ofΩimplies that area-integral inequality by S. Krantz and S.Y. Li [7] forf ∈Hp(Ω), 0< p <∞,could be expressed as
Z
∂Ω
dσ(z)
Z
Di(z,η)
|∂f(τ)|2 dµ(τ) (−ρ(τ))n−1
p/2
≤c(Ω, p) Z
∂Ω
|f|pdσ. (10)
Consider the decomposition of vectorτ−ξ∈Cn asτ =w+tn(ξ),where w∈Tξ, t∈C,and n(z) = |∂ρ(ξ)|∂ρ(ξ) is a complex normal vector atz. We define theexternal Kor´anyi region as
De(ξ, η) ={τ∈Cn\Ω:τ =w+tn(z),
w∈Tz, t∈C, |w|< ηρ(τ), |Re(t)|< ηρ(τ), ρ(τ)< ε}. In appendix A we will proof the area-integral inequality similar to 10 for external regionsDe.
We point out two rules for integration over regionsDe(ξ, η).First, for every function F we have
Z
Ωε\Ω
|F(z)|dµ(z)≍ Z
∂Ω
dσ(ξ) Z
De(ξ,η)
|F(τ)|dµ(τ) ρ(τ)n. Second, if F(w) = ˜F(ρ(w)) then
Z
De(ξ,η)
|F(τ)|dµ(τ)≍
ε
Z
0
F(t)˜
tndt.
Similar rules are valid for regionsDi.
We could clarify the estimate ofd(τ, w) in lemma3.1forτ ∈De(z, η).
Lemma 3.4 Let Ω be a strongly convex domain andη >0, then
d(τ, w)≍ρ(τ) +d(z, w), z, w∈∂Ω, τ ∈De(z, η). (11)
Proof Forτ∈De(z, η) we haved(π(τ), z).ηρ(τ) and
d(τ, w).ρ(τ) +d(π(τ), w).ρ(τ) +d(π(τ), z) +d(z, w).ρ(τ) +d(z, w).
On the other hand,
ρ(τ) +d(z, w).ρ(τ) + (d(z, π(τ)) +d(π(τ), w)).(1 +η)ρ(τ) +d(π(τ), w) .ρ(τ) +d(π(τ), w).d(τ, w).
4 The method of pseudoanalytical continuation 4.1 Definition of pseudoanalytical continuation
The main tool of this paper is the method of continuation of function f ∈ H(Ω) outside the domain Ω. Let f ∈ H1(Ω) and let the boundary values of f almost everywhere coincide with the boundary values of some function f ∈ Cloc1 (Cn\Ω) such that
∂f¯
∈ L1(Cn \Ω). Then by Stokes formula for z∈Ωwe have
f(z) = lim
r→0+
1 (2πi)n
Z
∂Ωr
f(ξ)∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1 h∂ρ(ξ), ξ−zin =
r→0+lim 1 (2πi)n
Z
Cn\Ωr
∂f(ξ)¯ ∧∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1 h∂ρ(ξ), ξ−zin
= 1
(2πi)n Z
Cn\Ω
∂f¯ (ξ)∧∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1 h∂ρ(ξ), ξ−zin , (12) since (for details see [12])
dξ
∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1 h∂ρ(ξ), ξ−zin
= 0, z∈Ω, ξ ∈Cn\Ω.
This formula allows us to study properties of function f ∈H(Ω) relying on estimates of its continuation. Note that it is not necessary for the function f to be a continuation in terms of coincidence of boundary values. We call the function f ∈ Cloc1 (Cn\Ω) satisfying (12) the pseudoanalytic continuation of the functionf.
4.2 Continuation by symmetry
Theorem 4.1 Let f ∈Hp1(Ω)and1< p <∞, m∈N.There exist a pseudo- analytical continuation f ∈Cloc1 (Cn\Ω)of functionf such thatsuppf ⊂Ωε,
∂f¯ (z)
∈Lp(Ωε\Ω)and
∂f¯ (z)
. max
|α|=m|∂αf(z∗)|ρ(z)m−1, z∈Ωε\Ω, (13) wherez∗ is a symmetric to z with respect to∂Ω.
Proof Define
f0(z) = X
|α|≤m−1
∂αf(z∗)(z−z∗)α
α! , z∈Ωε\Ω. (14) Let α±ek = (α1, . . . , αk±1, αn) and define (z−z∗)α−ek = 0 if αk = 0.In these notations we have
∂¯jf0=
∞
X
k=1
X
|α|≤m−1
∂α+ekf(z∗)(z−z∗)α
α! −∂αf(z∗)(z−z∗)α−ek (α−ek)!
∂¯jz∗k
=
∞
X
k=1
X
|α|=m−1
∂α+ekf(z∗)(z−z∗)α
α! ∂¯jzk∗, (15) hence,
∂f¯0(z)
. max
|α|=m|∂αf(z∗)|ρ(z)m−1, z∈Cn\Ω.
Consider functionχ∈C∞(0,∞) such thatχ(t) = 1 fort≤ε/2 andχ(t) = 0 for t ≥ ε. The function f(z) = f0(z)χ(ρ(z)) satisfies the condition (14) and suppf ⊂ Ωε.
Letd= dist(z∗, ∂Ω)/10,then for every mutiindexαsuch that|α|=mby Cauchy maximal inequality we have
|∂αf(z∗)|.d−m+1 sup
|τ−z∗|<d|∂f(τ)|.ρ(z)−m+1 sup
τ∈Di(π(z),c0d)|∂f(τ)|, for somec0>0.Finally, by theorem 2.1 from [7] we get
Z
Ωε\Ω
∂f¯ (z)
pdµ(z). Z
Ω\Ω−ε
dµ(z) sup
τ∈Di(π(z),c0d)|∂f(τ)|
!p
.k∂fkpHp(Ω).
4.3 Continuation by global approximations.
Letf ∈ H1(Ω) and consider a polynomial sequenceP1, P2, . . . converging to f inL1(∂Ω).Define
λ(z) =ρ(z)−1|P2k+1(z)−P2k(z)|, 2−k< ρ(z)<2−k+1.
Theorem 4.2 Assume thatλ∈Lp(Cn\Ω)for somep≥1.Then there exist a pseudoanalytical continuationf of function f such that
∂f(z)¯
.λ(z), z∈Cn\Ω. (16)
Proof Consider function χ ∈ C∞(0,∞) such that χ(t) = 1 for t ≤ 1 and χ(t) = 0 fort≥2.We define continuation of functionf by formula
f(z) =P2k(z) +χ(2kρ(z))(P2k+1(z)−P2k(z)), 2−k< ρ(z)<2−k+1. Nowf isC1-function onCn\Ω¯ and
∂f¯ (z)
.λ(z). We define a function Fk(z) asFk(z) =f(z) forρ(z)>2−k and asFk(z) =P2k+1(z) forρ(z)<2−k. The the functionFk is smooth and holomorphic inΩ2−k,and
∂F¯ k(z) .λ(z) forz∈Cn\Ω2−k.Thus similarly to12we get
P2k+1(z) =Fk(z) = 1 (2πi)n
Z
Cn\Ω
∂F¯ k(ξ)∧∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1
h∂ρ(ξ), ξ−zin , z∈Ω,
We can pass to the limit in this formula by the dominated convergence the- orem; hence, function f satisfies the formula (12) and is a pseudoanalytical continuation of functionf.
4.4 Pseudoanalytical continuation of Hardy-Sobolev spaces
Theorem 4.3 Let Ω be a strongly convex domain, 1 < p < ∞, l ∈ N and f ∈Hp(Ω). Then f ∈Hpl(Ω) if and only if there exists such pseudoanalytical continuation f that
Z
∂Ω
dσ(z)
Z
De(z,α)
∂f¯ (τ)ρ(τ)−l
2dν(τ)
p/2
<∞, (17)
wheredν(τ) = ρ(τ)dµ(τ)n−1.
Proof Let f ∈ Hpl(Ω). By theorem 4.3 we could construct pseudoanalytical continuationf such that
∂f(z)¯
. max
|α|=m+1|∂αf(z∗)|ρ(z)m, z∈Cn\Ω.
Note that the symmetry with respect to ∂Ω maps the external sector De(z, η) into some internal Kor´anyi sector. Indeed, for every α > 0 there existsη1=η1(η)>0 such that
{τ∗:τ∈De(z, η)} ⊆Di(z, η1).
Applying area-integral inequality (10) we obtain
Z
∂Ω
dσ(z)
Z
De(z,η)
∂f¯ (τ)ρ(τ)−l
2dν(τ)
p/2
. max
|α|=m
Z
∂Ω
dσ(z)
Z
De(z,η)
|∂αf(τ∗)|2dν(τ)
p/2
. max
|α|=m
Z
∂Ω
dσ(z)
Z
Di(z,η1)
|∂αf(τ)|2 dµ(τ) (−ρ(τ))n−1
p/2
<∞
To prove the sufficiency, assume that functionf ∈H1(Ω) admits the pseu- doanalytical continuationf with estimate (17.) We will prove that for every function g∈Lp′(∂Ω), 1p+p1′ = 1,and every multiindex α, |α| ≤l,
Z
∂Ω
g(z)∂αf(z)dS(z)
≤c(f)kgkLp′(∂Ω).
Assume, without loss of generality, that α = (l,0, . . . ,0). By representa- tion (12) we have
f(z) = Z
Cn\Ω
∂f¯ (ξ)∧ω(ξ) h∂ρ(ξ), ξ−zin
and withCnl=(n+l−1)!(n−1)!
Z
∂Ω
g(z)∂αf(z)dS(z) =Cnl
Z
∂Ω
g(z)
Z
Cn\Ω
∂ρ(ξ)
∂ξ1
l ∂f(ξ)¯ ∧ω(ξ) h∂ρ(ξ), ξ−zin+l
dS(z)
=Cnl
Z
Cn\Ω
∂ρ(ξ)
∂ξ1
l
∂f¯ (ξ)∧ω(ξ) Z
∂Ω
g(z)dS(z) h∂ρ(ξ), ξ−zin+l.
DefineΦl(ξ) = R
∂Ω
g(z)dS(z)
h∂ρ(ξ), ξ−zin+l.Applying H¨older inequality twice we have
Z
∂Ω
g(z)∂αf(z)dS(z)
. Z
Cn\Ω
∂f¯ (ξ)
|Φl(ξ)|dµ(ξ) .
Z
∂Ω
dS(ξ) Z
De(ξ,α)
∂F¯ (τ)
|Φl(τ)|dµ(τ) ρ(τ)n
. Z
∂Ω
dσ(ξ)
Z
De(ξ,α)
∂F¯ (τ)
2ρ(τ)−2l dµ(τ) ρ(τ)n−1
1/2
×
×
Z
De(ξ,α)
|Φl(τ)|2ρ(τ)2l−2 dµ(τ) ρ(τ)n−1
1/2
.
Z
∂Ω
dS(ξ)
Z
De(ξ,α)
∂F¯ (τ)
2ρ(τ)−2ldν(τ)
p/2
1/p
×
×
Z
∂Ω
dS(ξ)
Z
De(ξ,α)
|Φl(τ)|2ρ(τ)2l−2dν(τ)
p′/2
1/p′
.
The first product term is bounded by (17), and the second one by the area- integral inequality (30), that we will prove in the appendixAin theoremA.1.
5 Constructive description of Hardy-Sobolev spaces
Theorem 5.1 Let f ∈H1(Ω) and1 < p < ∞, l ∈N. Then f ∈Hpl(Ω)iff there exists a polynomial sequenceP2k such that
Z
∂Ω
dσ(z)
∞
X
k=1
|f(z)−P2k(z)|222lk
!p/2
<∞. (18)
Proof Assume that condition (18) holds, then polynomials P2k converge to function f inLp(∂Ω) and by the theorem 4.2we could construct pseudoana- lytical continuationf such that
∂f¯ (z)
.|P2k+1(z)−P2k(z)|ρ(z)−1, z∈Cn\Ω, 2−k ≤ρ(z)<2−k+1.
Consider the decomposition of region De(z, η) to sets Dk(z) = {τ ∈ De(z, η) : 2−k ≤ρ(τ)<2−k+1},and define functions
ak(z) =|P2k+1(z)−P2k(z)|2−kl,
bk(z) =
Z
Dk(z)
∂f¯ (τ)ρ(τ)−l
2dν(τ)
1/2
.
Lemma 5.1 bk(z).M ak(z)
Assume, that this lemma holds, then by Fefferman-Stein maximal theorem we have
Z
∂Ω
∞
X
k=1
bk(z)2
!p/2
dσ(z). Z
∂Ω
∞
X
k=1
ak(z)2
!p/2
dσ(z).
The right-hand side of this inequality is finite by the condition 18, also we have
∞
X
k=1
bk(z)2≍ Z
S(z)
∂f(ξ)ρ(ξ)¯ −l
2dν(ξ),
which completes the proof of the sufficiency in the theorem..
Prove the necessity. Now f ∈Hpl(Ω) with 1< p <∞andl∈N.By theo- rem4.3we could construct continuationfof functionfwith estimate (17). Ap- plying the approximation of Cauchy-Leray-Fantappi`e kernel from lemma 3.3 to functionf we define polynomials
P2k(z) = Z
Cn\Ω
∂f¯ (ξ)∧ω(ξ)K2globk (ξ, z).
We will prove that these polynomials satisfy the condition (18). From lemma3.3 we obtain
|f(z)−P2k(z)|. Z
Cn\Ω
∂f(ξ)¯
1
h∂ρ(ξ), ξ−zid −K2globk (ξ, z)
dµ(ξ)
=U(z) +V(z) +W1(z) +W2(z),
where
U(z) = Z
d(τ,z)<2−k
∂f¯ (τ)
|h∂ρ(τ), τ−zi|ndµ(τ), V(z) = 2kn
Z
d(τ,z)<2−k
∂f¯ (τ)
dµ(τ),
W1(z) = 2−kr Z
d(τ,z)>2−k ρ(τ)<2−k
∂f¯ (τ)
|h∂ρ(τ), τ−zi|n+rdµ(τ),
W2(z) = 2−kr Z
ρ(τ)>2−k
∂f¯ (τ)
|h∂ρ(τ), τ−zi|n+rdµ(τ).
The parameterr >0 will be chosen later.
Note thatV(z).cU(z) and estimate the contribution ofU(z) to the sum.
For somec1, c2>0 we have
U(z)≤ Z
d(w,z)<c12−k w∈∂Ω
dσ(w) X
j>c2k
Z
Dj(w)
∂f¯ (τ)
|h∂ρ(τ), τ−zi|n dν(τ)
ρ(τ)
≤ Z
d(w,z)<c12−k w∈∂Ω
dσ(w) X
j>c2k
Z
Dj(w)
∂f¯ (τ)ρ(τ)−l
2dν(τ)
1/2
×
×
Z
Dj(w)
ρ(τ)2(l−1)dν(τ)
|h∂ρ(τ), τ−zi|n
1/2
= X
j>c2k
Z
d(w,z)<c12−j
bj(w)mj(w)dσ(w)
Consider the integralmj(w).Sinceτ ∈Dj(w) then by estimates from lemma3.4 d(τ, z)≍ρ(τ) +d(w, z)>2−j and
mj(w) =
Z
Dj(w)
ρ(τ)2(l−1)dν(τ)
|h∂ρ(τ), τ−zi|n
1/2
.2−j(l−1)
2−jn 2−j= 2jn−jl. (19) Thus
2klU(z). X
j>c1k
2−(j−k)l2jn Z
d(w,z)<c22j
bj(w)dσ(w). X
j>c1k
2−(j−k)lM bj(z) (20)
Now estimate the valueW1(z).Similarly to the previous we have W1(z)≤2−krX
j>k
Z
d(w,z)≥c12−k
bj(w)mrj(w)dσ(w),
where
mrj(w) =
Z
Dj(w)
ρ(τ)2(l−1)dν(τ)
|h∂ρ(τ), τ−zi|2(n+r)
1/2
. (21)
Applying the estimated(τ, z)≍ρ(τ) +d(w, z)&2−j,we obtain
mrj(w).2j(n+r−l). (22)
Finally
2klW1(z).2kl−krX
j>k
2j(r−l)+jn Z
d(w,z)≤2−j
bj(w)dσ(w)
.X
j>k
2−(j−k)(r−l)M bj(z). (23) Similarly, estimating the contribution of W2(z),we obtain
2klW2(z).2−k(r−l)
k
X
j=0
Z
∂Ω
bj(w)mrj(w)dσ(w). (24)
Sinced(τ, z)&2−j+d(w, z) forτ∈∂Ω, τ ∈Dj(z) then mrj(w). 2−jl
(2−j+d(w, z))n+r ≤min
2j(n+r−l),2−jld(w, z)−n−r . Thus
Z
∂Ω
bj(w)mrj(w)dσ(w). Z
d(w,z)≤2−j
2−jl
2−j(n+r)bj(w)dσ(w)
+
j−1
X
t=1
Z
2−t−1≤d(w,z)≤2−t
2−jl
2−t(n+r)bj(w)dσ(w)
.
j
X
t=1
2−jl2trM bj(z).2−jl2jrM bj(z).
Choosingr=l+ 1,we have W2(z)2kl.
k
X
j=1
2−(k−j)(r−l)M bj(z)≤
k
X
j=1
2−(k−j)M bj(z). (25)
Combining the estimates (20,23,25) we finally obtain
|f(z)−P2k(z)|.
k
X
j=1
2−(k−j)M bj(z) +X
j>k
2−(j−k)lM bj(z),
which similarly to [5] implies
∞
X
k=1
|f(z)−P2k(z)|2.
∞
X
k=1
(M bk(z))2= Z
De(z,η)
∂f¯ (τ)
2ρ(τ)−2ldµ(τ)<∞.
This completes the proof of the theorem and it remains to prove lemma5.1.
Proof (of the lemma 5.1). Define gk(z) := 2−kl(P2k+1(z)−P2k(z)).
Letz∈∂Ω andτ∈Sk(z).Consider complex normal vectorn(z) =|∂ρ(z)|∂ρ(z) at z, complex tangent hyperplaneTz ={w ∈Cn :h∂ρ(z), w−zi= 0} and complex planeTz,τ⊥ , orthogonal toTz and containing the pointτ
Tz,τ⊥ :={τ+sn(z) :s∈C}. Projection of vectorτ∈Cto∂ΩT
Tz,τ⊥ we will denote asπz(τ).
Define Ωz,τ =ΩTTz,τ⊥ andγz,τ =∂Ωz,τ.There exist a conformal map ϕz,τ :Tz,τ⊥ \Ωz,τ →C\{w∈C:|w|= 1}such that ϕz,τ(∞) =∞, ϕ′z,τ(∞)>
0,and we could consider analytical inTz,τ⊥ \Ωz,τ function Gk(s) := gk(s)
ϕ2k+1z,τ (s). Applying to function Gk Dyn’kin maximal estimate from [4] for domain Tz,τ⊥ \ Ω(z, τ) we obtain the estimate
|Gk(τ)|. 1 ρ(τ)
Z
s∈Iz,τ
|Gk(s)| |ds|+ Z
∂Ωz,τ\Iz,τ
|Gk(s)| ρ(τ)m
|s−πz(τ)|m+1|ds|, whereIz,τ ={s∈γz,τ :|s−πz(τ)|<dist(τ, ∂Ωz,τ)/2},andm >0 could be chosen arbitrary large.
Note that |ϕz,τ(s)| −1≍dist(s, ∂Ωz,τ)≍2−k,thus|gk(s)| ≍ |Gk(s)|for s∈Dk(z)T
Tz,τ⊥. Hence,
|gk(τ)|.
∞
X
j=1
2−jm 1 2jρ(τ)
Z
s∈∂Ωz,τ
|s−πz(τ)|<2jρ(τ)
|gk(s)| |ds|. (26)
Since the boundary of the domainΩisC3-smooth, we can assume that the constant in this inequality (26) does not depend onz∈∂Ω andτ∈Ωε\Ω.
Note that functiongk(τ+z−w) is holomorphic inw∈Tz,then estimating the mean we obtain
|gk(τ)| ≤ 1 ρ(τ)n−1
Z
|w−z|<√
ρ(τ)
|gk(τ+z−w)|dµ2n−2(w)
.
∞
X
j=1
2−jm 1 ρ(τ)n−1
Z
|w−z|<√
ρ(τ)
dµ2n−2(w) 2jρ(τ)
Z
s∈∂Ωz,τ
|s−πz(τ+z−w)|<2jρ(τ)
|gk(s)| |ds|
.
∞
X
j=1
2−j(m−n+1) Z
B(z,2jρ(τ))
|gk(w)|dσ(w), (27)
wheredµ2n−2is Lebesgue measure in Tz
Assume that m > n−1, then |gk(τ)| . M gk(z), z ∈ ∂Ω, τ ∈ Dk(z).
Finally,
bk(z) =
Z
Dk(z)
∂f¯ (τ)ρ(τ)−l
2dν(τ)
1/2
.
Z
Dk(z)
gk(τ)ρ(τ)−l−1
2dν(τ)
1/2
.M ak(z)
Z
Dk(z)
dν(τ) ρ(τ)2
1/2
.M ak(z) (28)
and the lemma is proved.
A Area-integral inequality for external Kor´anyi region
LetΩ⊂Cnbe a strongly convex domain and η >0. For functiong∈L1(∂Ω) andl∈N we define a function
Il(g, z) =
Z
De(z,η)
Z
∂Ω
g(w)dS(w) h∂ρ(τ), τ−win+l
2
dνl(τ)
1/2
, (29)
wheredνl(τ) =ρ(τ)dµn−2l−12n(τ) .
Theorem A.1 LetΩbe strongly convex domain andg∈Lp(∂Ω), 1< p <∞,Then Z
∂Ω
Il(g, z)pdσ(z). Z
∂Ω
|g(z)|pdσ(z). (30)
Note that in the one-variable case the integral29gives the holomorphic function and the result of the theorem follows from [5].
Definition 1 Assume, that defining functionρfor strongly convex domainΩhas the fol- lowing form nearz0∈∂Ω
ρ(z) = Im(zn) +
n
X
j,k=1
Ajkzjz¯k+O(|z|3). (31)
Define a set
D0(η, ε) ={τ∈Cn\Ω:|τ1|2+. . .+|τn−1|2< ηIm(τn),
|Re(τn)|< ηIm(τn), |Im(τn)|< ε1}. (32) Theorem A.2 There exists such covering of the setΩε\Ω−ε by open setsΓj such that for everyξ∈Γj we can find a holomorphic change of coordinatesϕj(ξ,·) :Cn→Cn such that
1. The mappingϕj(ξ,·)transforms functionρto the type (31) and could be expressed as follows
ϕj(ξ, z) =Φj(ξ)(z−ξ) +i(z−ξ)⊥Bj(ξ)(z−ξ)en, (33) where matricesΦj(ξ), Bj(ξ)depend smooth onξ∈Γj,anden= (0, . . . ,0,1).
2. Letψj(ξ,·)be an inverse map of ϕj(ξ,·),and letJj(ξ,·)be a complex Jacobian ofψ.
Note that real Jacobian is then equal to|Jj(ξ,·)|2=Jj(ξ,·)Jj(ξ,·), Then sup
τ∈Ωε\Ωε
Jj(ξ,·)−Jj(ξ′,·) .
ξ−ξ′
, (34) sup
τ∈Ωε\Ωε
ψj(ξ,·)−ψj(ξ′,·) .
ξ−ξ′
. (35) 3. There exist constants c >0, 0< η0, ε1<1such that
ϕj(ξ, De(ξ, η))⊆D0(cη, cε), ψj(ξ, D0η)⊆De(ξ, cη), for0< η < η0. (36) Proof Let ξ∈ ∂Ω,by linear change of coordinates z′ = (z−ξ)Φ(ξ) we could obtain the following form for functionρ
ρ(z) =ρ(ξ+Φ−1(ξ)z′) = Im(zn′) +
n
X
j,k=1
A1jk(ξ)z′j¯z′k+ Re
n
X
j,k=1
A2jk(ξ)zj′zk′ +O(
z′ 3).
Settingz′′n=zn′ +iA2jkzj′zk′ andz′′j =zj′, 1≤j≤n−1,we have
ρ(z′′) = Im(z′n) +
n
X
j,k=1
A1jk(ξ)zj′′z¯k′′+O(
z′′
3).
DenoteB(ξ) =Φ(ξ)⊥A1(ξ)Φ(ξ),then
ϕ(ξ, z) =Φ(ξ)(z−ξ) +i(z−ξ)⊥B(ξ)(z−ξ)en.
We choose Γj such that the matrixΦ(ξ) could be defined onΓj smoothly, this choice we denote asΦj,and the change corresponding to this matrix asϕj
ϕj(ξ, z) =Φj(ξ)(z−ξ) +i(z−ξ)⊥Bj(ξ)(z−ξ)en.
Thus mappingsϕjsatisfy the first condition. Easily, the second condition also holds.
To prove the last condition (36) it is sufficient to show, that if function ρ has the form (31), then for somec, η0>0 we have
De(0, η)⊆D0(cη), D0(η)⊆De(0, cη),for0< η < η0.
Indeed, for the functionρof the form (31) the Kor´anyi sector could be expressed as follows De(0, η) ={τ∈Cn\Ω:|τ1|2+. . .+|τn−1|2≤(ηρ(τ))2, |Re(τn)| ≤ηρ(τ), ρ(τ)< ε}
Assumeτ∈De(0, η),then
ρ(τ) = Im(τn) +
n
X
j,k=1
Ajkτjτ¯k≤Im(τn) +c0|Im(τn)|2
+c0(|τ1|2+. . .+|τn−1|+|Re(τn)|2)≤Im(τn) +c0|Im(τn)|2+c0ηρ(τ) +c0(ηρ(τ))2. (37) By choosingη0<1/(4c0) we haveρ(τ)≤cIm(τn) forτ∈De(0, η) and 0< η < η0.Hence, De(0, η)⊆D0(cη) for 0< η < η0 andε1=cε.Note, that
ρ(τ) = Im(τn) +
n
X
j,k=1
Ajkτj¯τk>Im(τn) forτ∈D0(η),
since matrix (Ajk) is strictly positive definite. Hence,D0(η)⊆De(0, η).This ends the proof of the theorem.
Further we will assume, that the coveringΩε\Ω−ε⊂ SN
j=1
Γjand mapsϕj, ψjare chosen by the theoremA.2. For covering{Γj}we consider a smooth decomposition of identity on
∂Ω:
χj∈C∞(Γj), 0≤χj≤1, suppχj⊂Γj,
N
X
j=1
χj(z) = 1, z∈∂Ω.
Fix the parameterη < η0and denoteD0=D0(η).Then by (36) Il(g, z)2
=
N
X
j=1
χj(z) Z
ϕj(z,De(z,η/c))
Z
∂Ω
g(w)Jj(z, τ)dS(w) h∂ρ(ψj(z, τ)), ψj(z, τ)−win+l
2
dµ(τ) Im(τn)n−2l+1
.
N
X
j=1
Z
D0
Z
∂Ω
g(w)χ1/2j (z)Jj(z, τ)dS(w) h∂ρ(ψj(z, τ)), ψj(z, τ)−win+l
2
dµ(τ)
Im(τn)n−2l+1. (38) We will consider the function
Kj(z, w)(τ) = χ1/2j (z)Jj(z, τ)
h∂ρ(ψj(z, τ)), ψj(z, τ)−win+1 (39) as a map∂Ω×∂Ω →L(C, L2(D0, dνl)),such that its values are operator of multiplica- tion fromCto L2(D0, dνl),where dνl(τ) = Im(τdµ(τ)
n)n−2l+1 is a measure on the regionD0. Throughout the proof of the theoremA.1j, lwill be fixed integers and the norm of function F in the spaceL2(D0, dνl) will be denoted askFk.
We will show that integral operator defined by kernel Kj is bounded onLp.To prove this we applyT1-theorem for transformations with operator-valued kernels formulated by Hyt¨onen and Weis in [8], taking in account that in our case concerned spaces are Hilbert.
Some details of the proof are similar to the proof of the boundedness of operator Cauchy- Leray-Fantappi`eKΩfor lineally convex domains introduced in [13]. Below we formulate the T1-theorem, adapted to our context.