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arXiv:1601.03218v1 [math.CV] 13 Jan 2016

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Constructive description of Hardy-Sobolev spaces in C

n

Alexander Rotkevich

Received: date / Accepted: date

Abstract In this paper we study the polynomial approximations in Hardy- Sobolev spaces on for convex domains. We use the method of pseudoanalytical continuation to obtain the characterization of these spaces in terms of poly- nomial approximations.

Keywords Hardy-Sobolev Spaces·polynomial approximations, pseudoana- lytical continuation·Cauchy-Leray-Fantappi`e integral.

Mathematics Subject Classification (2010) 32E30·41A10

1 Introduction

The purpose of this paper is to give an alternative characterizations of Hardy- Sobolev (see. [1]) spaces

Hpl(Ω) ={f ∈H(Ω) :kfkHp(Ω)+ X

|α|≤l

k∂αfkHp(Ω)<∞} (1) on strongly convex domainΩ⊂Cn.

We continue the research started in [14] and devoted to description of basic spaces of holomorphic functions of several variables in terms of polynomial approximations and pseudoanalytical continuation. In particular, we show that for 1 < p < ∞ and l ≥ 1 a holomorphic on a strongly convex domain Ω function f is in the Hardy-Sobolev spaceHpl(Ω) if and only if there exist a polynomial sequenceP2k such that

Z

∂Ω

dσ(z)

X

k=1

|f(z)−P2k(z)|222lk

!p/2

<∞. (2)

Alexander Rotkevich

Mathematics and Mechanics Faculty, St.Petersburg State University, Universitetsky pr., 28, Peterhof, St. Petersburg, Russia.

E-mail: [email protected]

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In the one variable case this condition follows from the characterization ob- tained by E.M. Dynkin [5] for Radon domains.

The paper is divided into five sections with one appendix. In section 2we give main definitions and preliminaries of this work. Section3is devoted to the Cauchy-Leray-Fantappi`e integral formula, the polynomial approximations and estimates of its kernel. We also define internal and external Kor´anyi regions, the multidimensional analog of Lusin regions. In section 4 we introduce the method of pseudoanalytical continuation and three constructions of the con- tinuation with different estimates. We use these constructions to obtain the characterization of Hardy-Sobolev spaces in terms of estimates of the pseudo- analytical continuation. To prove this result we use the special analog of the Krantz-Li area-integral inequality [7] for external Kor´anyi regions established in appendixA. Finally, section5 contains the proof of characteristics (2).

2 Main notations and definitions

Let Cn be the space of n complex variables, n ≥ 2, z = (z1, . . . , zn), zj = xj+iyj;

jf = ∂f

∂zj

= 1 2

∂f

∂xj −i∂f

∂yj

, ∂¯jf = ∂f

∂z¯j

= 1 2

∂f

∂xj

+i∂f

∂yj

,

∂f =

n

X

k=1

∂f

∂zk

dzk, ∂f¯ =

n

X

k=1

∂f

∂¯zk

d¯zk, df=∂f+ ¯∂f.

The notation

h∂f(z), wi=

n

X

k=1

∂f(z)

∂zk

wk.

is used to indicate the action of∂f on the vectorw∈Cn,and

|∂f¯ |=

∂f

∂z1

+. . .+

∂f

∂zn

.

The euclidian distance form the pointz∈Cn to the setD⊂Cn we denote as dist(z, D) = inf{|z−w| :w∈D}. Lebesgue measure inCn we denote as dµ.

For a multiindexα= (α1, . . . , αn)∈Nn we set|α| = α1 + . . . + αn

andα! =α1!. . . α2!,alsozα=z1α1. . . zαnn and∂αf = z¯α1|α|f 1 ...∂¯zαnn .

Let Ω = {z∈Cn:ρ(z)<0} be a strongly convex domain with a C3- smooth defining function. We need to consider a family of domains Ωt = {z∈Cn:ρ(z)< t}that are also strongly convex for each|t|< ε,whereε >0 is small enough. The projection ofz∈Ωε\Ω−ε to the∂Ω we define asπ(z).

Forξ∈∂Ωtwe define the complex tangent space Tξ={z∈Cn :h∂ρ(ξ), ξ−zi= 0}.

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The space of holomorphic functions we denote asH(Ω) and consider the Hardy space (see [17], [6])

Hp(Ω) :=

f ∈H(Ω) : sup

−ε<t<0

Z

∂Ωt

|f(z)|pt(z)<∞

 ,

wheredσtis induced Lebesgue measure on the boundary ofΩt.We also denote dσ=dσ0.Hardy-Sobolev spacesHpl(Ω) are defined by (1).

Throughout this paper we use notations., ≍.We letf .g iff ≤cgfor some constant c >0, that doesn’t depend on main arguments of functionsf andg and usually depend only on dimension nand domainΩ.Alsof ≍g if c−1g≤f ≤cgfor somec >1.

3 Cauchy-Leray-Fantappi`e formula

In the context of theory of several complex variables there is no unique repro- ducing formula formula, however we could use the Leray theorem, that allows us to construct holomorphic reproducing kernels ([2], [11], [12]). For convex do- mainΩ={z∈Cn:ρ(z)<0}this theorem brings us Cauchy-Leray-Fantappi`e formula, and forf ∈H1(Ω) andz∈Ω we have

f(z) =Kf(z) = 1 (2πi)n

Z

∂Ω

f(ξ)∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1 h∂ρ(ξ), ξ−zin =

Z

∂Ω

f(ξ)K(ξ, z)ω(ξ), (3) whereω(ξ) = (2πi)1 n∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1,andK(ξ, z) =h∂ρ(ξ), ξ−zi−n.

The (2n−1)-formωdefines on∂ΩtLeray-Levy measuredS,that is equiv- alent to Lebesgue surface measuredσt(for details see [2], [9], [10]). This allows us to identify Lebesgue, Hardy and Hardy-Sobolev spaces defined with respect to measuresdσt anddS. Also note, that measuredV defined by the 2n-form dω= (∂∂ρ)¯ n is equivalent to Lebesgue measure dµin Cn.

By [13] the integral operatorK defines a bounded mapping onLp(∂Ω) toHp(Ω) for 1< p <∞.

The function d(w, z) = |h∂ρ(w), w−zi| defines on ∂Ω quasimetric, and if B(z, δ) = {w ∈ ∂Ω : d(w, z) < δ} is a quasiball with respect to d then σ(B(z, δ))≍ δn, see for example [13]. Therefore{∂Ω, d, σ} is a space of ho- mogeneous type.

Note also the crucial role in the forthcoming considerations of the following estimate that is proved in [14].

Lemma 3.1 Let Ω be strongly convex, then

d(w, z)≍ρ(w) +d(π(w), z), w∈Cn\Ω, z∈∂Ω.

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3.1 The polynomial approximation of Cauchy-Leray-Fantappi´e kernel

In lemma 3.3 here we construct a polynomial approximations of Cauchy- Leray-Fantappi´e kernel based on theorem by V.K. Dzyadyk about estimates of Cauchy kernel on domains on complex plane (theorem 1 in part 1 of sec- tion 7 in [3]). The approximation is choosed similarly to [16] and [15]. This construction allows us in theorem 5.1 to get polynomials that approximate holomorphic function with desired speed.

Lemma 3.2 Let Ω be a strongly convex domain with 0 ∈ Ω, then for every ξ∈Ωε\Ωthe value of λ= h∂ρ(ξ), zih∂ρ(ξ), ξi for z∈Ω lies in domain L(t), bounded by the bigger arc of the circle |λ|= R =R(Ω) and the chord {λ∈ C: λ = 1 +eits, s∈R, |λ| ≤R}, wheret= π2−arg(h∂ρ(ξ), ξi).

Proof Forξ∈∂Ω define Λ(ξ) =

λ∈C:λ=h∂ρ(ξ), zi

h∂ρ(ξ), ξi, z ∈Ω

. The convexity ofΩwith 0∈Ωimplies that

|h∂ρ(ξ), ξi|&|∂ρ(ξ)| |ξ|&1, (4) Reh∂ρ(ξ), z−ξi ≤0, z∈Ω, ξ¯ ∈Ωε\Ω. (5) The domainL(ξ)⊂Cis also convex and contains 0, thus the equality

h∂ρ(ξ), zi

h∂ρ(ξ), ξi = 1 +h∂ρ(ξ), z−ξi h∂ρ(ξ), ξi with estimates (4), (5) completes the proof of the lemma.

Lemma 3.3 Let Ω be a strongly convex domain and r > 0. Then for every k∈N there exist functionKk(ξ, z) defined for ξ∈Ωε\Ωand polynomial in z∈Ω withdegKk(ξ,·)≤kand following properties:

K(ξ, z)−Kkglob(ξ, z) . 1

kr 1

d(ξ, z)d+r, d(ξ, z)≥ 1

k; (6)

Kkglob(ξ, z)

.kn, d(ξ, z)≤ 1

k. (7)

Proof Due to [3] and [16] for anyj∈Nthere exists function Tj(t, λ) polyno- mial inλwith degTj(t,·)≤j such that

1

1−λ−Tj(t, λ)

. 1 jr

1

|1−λ|1+r (8) forλ∈L(t)\n

λ:|1−λ|< 1jo

and coefficients of polynomialsTj(t, λ) contin- uously depend ont.Note also that by maximum principle

Tj(t, λ).j−1, λ∈L(t)\

λ:|1−λ|<1 j

. (9)

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Forj∈Nand (j−1)< k≤jndefine Kkglob(ξ, z) =Kjnglob(ξ, z) = 1

h∂ρ(ξ), ξinTjn

t(ξ),h∂ρ(ξ), zi h∂ρ(ξ), ξi

. Due to definition ofTj polynomialsKkglob(ξ,·) satisfy relations (6) - (7).

3.2 Kor´anyi regions

Forξ∈∂Ω andε >0 we define the inner Kor´anyi regionas Di(ξ, η) ={τ∈Ω:π(τ)∈B(ξ,−ηρ(τ)), ρ(τ)>−ε}.

The strong convexity ofΩimplies that area-integral inequality by S. Krantz and S.Y. Li [7] forf ∈Hp(Ω), 0< p <∞,could be expressed as

Z

∂Ω

dσ(z)

 Z

Di(z,η)

|∂f(τ)|2 dµ(τ) (−ρ(τ))n−1

p/2

≤c(Ω, p) Z

∂Ω

|f|pdσ. (10)

Consider the decomposition of vectorτ−ξ∈Cn asτ =w+tn(ξ),where w∈Tξ, t∈C,and n(z) = |∂ρ(ξ)|∂ρ(ξ) is a complex normal vector atz. We define theexternal Kor´anyi region as

De(ξ, η) ={τ∈Cn\Ω:τ =w+tn(z),

w∈Tz, t∈C, |w|< ηρ(τ), |Re(t)|< ηρ(τ), ρ(τ)< ε}. In appendix A we will proof the area-integral inequality similar to 10 for external regionsDe.

We point out two rules for integration over regionsDe(ξ, η).First, for every function F we have

Z

ε\Ω

|F(z)|dµ(z)≍ Z

∂Ω

dσ(ξ) Z

De(ξ,η)

|F(τ)|dµ(τ) ρ(τ)n. Second, if F(w) = ˜F(ρ(w)) then

Z

De(ξ,η)

|F(τ)|dµ(τ)≍

ε

Z

0

F(t)˜

tndt.

Similar rules are valid for regionsDi.

We could clarify the estimate ofd(τ, w) in lemma3.1forτ ∈De(z, η).

Lemma 3.4 Let Ω be a strongly convex domain andη >0, then

d(τ, w)≍ρ(τ) +d(z, w), z, w∈∂Ω, τ ∈De(z, η). (11)

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Proof Forτ∈De(z, η) we haved(π(τ), z).ηρ(τ) and

d(τ, w).ρ(τ) +d(π(τ), w).ρ(τ) +d(π(τ), z) +d(z, w).ρ(τ) +d(z, w).

On the other hand,

ρ(τ) +d(z, w).ρ(τ) + (d(z, π(τ)) +d(π(τ), w)).(1 +η)ρ(τ) +d(π(τ), w) .ρ(τ) +d(π(τ), w).d(τ, w).

4 The method of pseudoanalytical continuation 4.1 Definition of pseudoanalytical continuation

The main tool of this paper is the method of continuation of function f ∈ H(Ω) outside the domain Ω. Let f ∈ H1(Ω) and let the boundary values of f almost everywhere coincide with the boundary values of some function f ∈ Cloc1 (Cn\Ω) such that

∂f¯

∈ L1(Cn \Ω). Then by Stokes formula for z∈Ωwe have

f(z) = lim

r→0+

1 (2πi)n

Z

∂Ωr

f(ξ)∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1 h∂ρ(ξ), ξ−zin =

r→0+lim 1 (2πi)n

Z

Cn\Ωr

∂f(ξ)¯ ∧∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1 h∂ρ(ξ), ξ−zin

= 1

(2πi)n Z

Cn\Ω

∂f¯ (ξ)∧∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1 h∂ρ(ξ), ξ−zin , (12) since (for details see [12])

dξ

∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1 h∂ρ(ξ), ξ−zin

= 0, z∈Ω, ξ ∈Cn\Ω.

This formula allows us to study properties of function f ∈H(Ω) relying on estimates of its continuation. Note that it is not necessary for the function f to be a continuation in terms of coincidence of boundary values. We call the function f ∈ Cloc1 (Cn\Ω) satisfying (12) the pseudoanalytic continuation of the functionf.

4.2 Continuation by symmetry

Theorem 4.1 Let f ∈Hp1(Ω)and1< p <∞, m∈N.There exist a pseudo- analytical continuation f ∈Cloc1 (Cn\Ω)of functionf such thatsuppf ⊂Ωε,

∂f¯ (z)

∈Lp(Ωε\Ω)and

∂f¯ (z)

. max

|α|=m|∂αf(z)|ρ(z)m−1, z∈Ωε\Ω, (13) wherez is a symmetric to z with respect to∂Ω.

(7)

Proof Define

f0(z) = X

|α|≤m−1

αf(z)(z−z)α

α! , z∈Ωε\Ω. (14) Let α±ek = (α1, . . . , αk±1, αn) and define (z−z)α−ek = 0 if αk = 0.In these notations we have

∂¯jf0=

X

k=1

X

|α|≤m−1

α+ekf(z)(z−z)α

α! −∂αf(z)(z−z)α−ek (α−ek)!

∂¯jzk

=

X

k=1

X

|α|=m−1

α+ekf(z)(z−z)α

α! ∂¯jzk, (15) hence,

∂f¯0(z)

. max

|α|=m|∂αf(z)|ρ(z)m−1, z∈Cn\Ω.

Consider functionχ∈C(0,∞) such thatχ(t) = 1 fort≤ε/2 andχ(t) = 0 for t ≥ ε. The function f(z) = f0(z)χ(ρ(z)) satisfies the condition (14) and suppf ⊂ Ωε.

Letd= dist(z, ∂Ω)/10,then for every mutiindexαsuch that|α|=mby Cauchy maximal inequality we have

|∂αf(z)|.d−m+1 sup

|τ−z|<d|∂f(τ)|.ρ(z)−m+1 sup

τ∈Di(π(z),c0d)|∂f(τ)|, for somec0>0.Finally, by theorem 2.1 from [7] we get

Z

ε\Ω

∂f¯ (z)

pdµ(z). Z

Ω\Ω−ε

dµ(z) sup

τ∈Di(π(z),c0d)|∂f(τ)|

!p

.k∂fkpHp(Ω).

4.3 Continuation by global approximations.

Letf ∈ H1(Ω) and consider a polynomial sequenceP1, P2, . . . converging to f inL1(∂Ω).Define

λ(z) =ρ(z)−1|P2k+1(z)−P2k(z)|, 2−k< ρ(z)<2−k+1.

Theorem 4.2 Assume thatλ∈Lp(Cn\Ω)for somep≥1.Then there exist a pseudoanalytical continuationf of function f such that

∂f(z)¯

.λ(z), z∈Cn\Ω. (16)

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Proof Consider function χ ∈ C(0,∞) such that χ(t) = 1 for t ≤ 1 and χ(t) = 0 fort≥2.We define continuation of functionf by formula

f(z) =P2k(z) +χ(2kρ(z))(P2k+1(z)−P2k(z)), 2−k< ρ(z)<2−k+1. Nowf isC1-function onCn\Ω¯ and

∂f¯ (z)

.λ(z). We define a function Fk(z) asFk(z) =f(z) forρ(z)>2−k and asFk(z) =P2k+1(z) forρ(z)<2−k. The the functionFk is smooth and holomorphic inΩ2−k,and

∂F¯ k(z) .λ(z) forz∈Cn\Ω2−k.Thus similarly to12we get

P2k+1(z) =Fk(z) = 1 (2πi)n

Z

Cn\Ω

∂F¯ k(ξ)∧∂ρ(ξ)∧( ¯∂∂ρ(ξ))n−1

h∂ρ(ξ), ξ−zin , z∈Ω,

We can pass to the limit in this formula by the dominated convergence the- orem; hence, function f satisfies the formula (12) and is a pseudoanalytical continuation of functionf.

4.4 Pseudoanalytical continuation of Hardy-Sobolev spaces

Theorem 4.3 Let Ω be a strongly convex domain, 1 < p < ∞, l ∈ N and f ∈Hp(Ω). Then f ∈Hpl(Ω) if and only if there exists such pseudoanalytical continuation f that

Z

∂Ω

dσ(z)

 Z

De(z,α)

∂f¯ (τ)ρ(τ)−l

2dν(τ)

p/2

<∞, (17)

wheredν(τ) = ρ(τ)dµ(τ)n−1.

Proof Let f ∈ Hpl(Ω). By theorem 4.3 we could construct pseudoanalytical continuationf such that

∂f(z)¯

. max

|α|=m+1|∂αf(z)|ρ(z)m, z∈Cn\Ω.

Note that the symmetry with respect to ∂Ω maps the external sector De(z, η) into some internal Kor´anyi sector. Indeed, for every α > 0 there existsη11(η)>0 such that

:τ∈De(z, η)} ⊆Di(z, η1).

(9)

Applying area-integral inequality (10) we obtain

Z

∂Ω

dσ(z)

 Z

De(z,η)

∂f¯ (τ)ρ(τ)−l

2dν(τ)

p/2

. max

|α|=m

Z

∂Ω

dσ(z)

 Z

De(z,η)

|∂αf(τ)|2dν(τ)

p/2

. max

|α|=m

Z

∂Ω

dσ(z)

 Z

Di(z,η1)

|∂αf(τ)|2 dµ(τ) (−ρ(τ))n−1

p/2

<∞

To prove the sufficiency, assume that functionf ∈H1(Ω) admits the pseu- doanalytical continuationf with estimate (17.) We will prove that for every function g∈Lp(∂Ω), 1p+p1 = 1,and every multiindex α, |α| ≤l,

Z

∂Ω

g(z)∂αf(z)dS(z)

≤c(f)kgkLp(∂Ω).

Assume, without loss of generality, that α = (l,0, . . . ,0). By representa- tion (12) we have

f(z) = Z

Cn\Ω

∂f¯ (ξ)∧ω(ξ) h∂ρ(ξ), ξ−zin

and withCnl=(n+l−1)!(n−1)!

Z

∂Ω

g(z)∂αf(z)dS(z) =Cnl

Z

∂Ω

g(z)

 Z

Cn\Ω

∂ρ(ξ)

∂ξ1

l ∂f(ξ)¯ ∧ω(ξ) h∂ρ(ξ), ξ−zin+l

dS(z)

=Cnl

Z

Cn\Ω

∂ρ(ξ)

∂ξ1

l

∂f¯ (ξ)∧ω(ξ) Z

∂Ω

g(z)dS(z) h∂ρ(ξ), ξ−zin+l.

(10)

DefineΦl(ξ) = R

∂Ω

g(z)dS(z)

h∂ρ(ξ), ξ−zin+l.Applying H¨older inequality twice we have

Z

∂Ω

g(z)∂αf(z)dS(z)

. Z

Cn\Ω

∂f¯ (ξ)

l(ξ)|dµ(ξ) .

Z

∂Ω

dS(ξ) Z

De(ξ,α)

∂F¯ (τ)

l(τ)|dµ(τ) ρ(τ)n

. Z

∂Ω

dσ(ξ)

 Z

De(ξ,α)

∂F¯ (τ)

2ρ(τ)−2l dµ(τ) ρ(τ)n−1

1/2

×

×

 Z

De(ξ,α)

l(τ)|2ρ(τ)2l−2 dµ(τ) ρ(τ)n−1

1/2

.

 Z

∂Ω

dS(ξ)

 Z

De(ξ,α)

∂F¯ (τ)

2ρ(τ)−2ldν(τ)

p/2

1/p

×

×

 Z

∂Ω

dS(ξ)

 Z

De(ξ,α)

l(τ)|2ρ(τ)2l−2dν(τ)

p/2

1/p

.

The first product term is bounded by (17), and the second one by the area- integral inequality (30), that we will prove in the appendixAin theoremA.1.

5 Constructive description of Hardy-Sobolev spaces

Theorem 5.1 Let f ∈H1(Ω) and1 < p < ∞, l ∈N. Then f ∈Hpl(Ω)iff there exists a polynomial sequenceP2k such that

Z

∂Ω

dσ(z)

X

k=1

|f(z)−P2k(z)|222lk

!p/2

<∞. (18)

Proof Assume that condition (18) holds, then polynomials P2k converge to function f inLp(∂Ω) and by the theorem 4.2we could construct pseudoana- lytical continuationf such that

∂f¯ (z)

.|P2k+1(z)−P2k(z)|ρ(z)−1, z∈Cn\Ω, 2−k ≤ρ(z)<2−k+1.

(11)

Consider the decomposition of region De(z, η) to sets Dk(z) = {τ ∈ De(z, η) : 2−k ≤ρ(τ)<2−k+1},and define functions

ak(z) =|P2k+1(z)−P2k(z)|2−kl,

bk(z) =

 Z

Dk(z)

∂f¯ (τ)ρ(τ)−l

2dν(τ)

1/2

.

Lemma 5.1 bk(z).M ak(z)

Assume, that this lemma holds, then by Fefferman-Stein maximal theorem we have

Z

∂Ω

X

k=1

bk(z)2

!p/2

dσ(z). Z

∂Ω

X

k=1

ak(z)2

!p/2

dσ(z).

The right-hand side of this inequality is finite by the condition 18, also we have

X

k=1

bk(z)2≍ Z

S(z)

∂f(ξ)ρ(ξ)¯ −l

2dν(ξ),

which completes the proof of the sufficiency in the theorem..

Prove the necessity. Now f ∈Hpl(Ω) with 1< p <∞andl∈N.By theo- rem4.3we could construct continuationfof functionfwith estimate (17). Ap- plying the approximation of Cauchy-Leray-Fantappi`e kernel from lemma 3.3 to functionf we define polynomials

P2k(z) = Z

Cn\Ω

∂f¯ (ξ)∧ω(ξ)K2globk (ξ, z).

We will prove that these polynomials satisfy the condition (18). From lemma3.3 we obtain

|f(z)−P2k(z)|. Z

Cn\Ω

∂f(ξ)¯

1

h∂ρ(ξ), ξ−zid −K2globk (ξ, z)

dµ(ξ)

=U(z) +V(z) +W1(z) +W2(z),

(12)

where

U(z) = Z

d(τ,z)<2−k

∂f¯ (τ)

|h∂ρ(τ), τ−zi|ndµ(τ), V(z) = 2kn

Z

d(τ,z)<2−k

∂f¯ (τ)

dµ(τ),

W1(z) = 2−kr Z

d(τ,z)>2−k ρ(τ)<2−k

∂f¯ (τ)

|h∂ρ(τ), τ−zi|n+rdµ(τ),

W2(z) = 2−kr Z

ρ(τ)>2−k

∂f¯ (τ)

|h∂ρ(τ), τ−zi|n+rdµ(τ).

The parameterr >0 will be chosen later.

Note thatV(z).cU(z) and estimate the contribution ofU(z) to the sum.

For somec1, c2>0 we have

U(z)≤ Z

d(w,z)<c12−k w∈∂Ω

dσ(w) X

j>c2k

Z

Dj(w)

∂f¯ (τ)

|h∂ρ(τ), τ−zi|n dν(τ)

ρ(τ)

≤ Z

d(w,z)<c12−k w∈∂Ω

dσ(w) X

j>c2k

 Z

Dj(w)

∂f¯ (τ)ρ(τ)−l

2dν(τ)

1/2

×

×

 Z

Dj(w)

ρ(τ)2(l−1)dν(τ)

|h∂ρ(τ), τ−zi|n

1/2

= X

j>c2k

Z

d(w,z)<c12−j

bj(w)mj(w)dσ(w)

Consider the integralmj(w).Sinceτ ∈Dj(w) then by estimates from lemma3.4 d(τ, z)≍ρ(τ) +d(w, z)>2−j and

mj(w) =

 Z

Dj(w)

ρ(τ)2(l−1)dν(τ)

|h∂ρ(τ), τ−zi|n

1/2

.2−j(l−1)

2−jn 2−j= 2jn−jl. (19) Thus

2klU(z). X

j>c1k

2−(j−k)l2jn Z

d(w,z)<c22j

bj(w)dσ(w). X

j>c1k

2−(j−k)lM bj(z) (20)

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Now estimate the valueW1(z).Similarly to the previous we have W1(z)≤2−krX

j>k

Z

d(w,z)≥c12−k

bj(w)mrj(w)dσ(w),

where

mrj(w) =

 Z

Dj(w)

ρ(τ)2(l−1)dν(τ)

|h∂ρ(τ), τ−zi|2(n+r)

1/2

. (21)

Applying the estimated(τ, z)≍ρ(τ) +d(w, z)&2−j,we obtain

mrj(w).2j(n+r−l). (22)

Finally

2klW1(z).2kl−krX

j>k

2j(r−l)+jn Z

d(w,z)≤2−j

bj(w)dσ(w)

.X

j>k

2−(j−k)(r−l)M bj(z). (23) Similarly, estimating the contribution of W2(z),we obtain

2klW2(z).2−k(r−l)

k

X

j=0

Z

∂Ω

bj(w)mrj(w)dσ(w). (24)

Sinced(τ, z)&2−j+d(w, z) forτ∈∂Ω, τ ∈Dj(z) then mrj(w). 2−jl

(2−j+d(w, z))n+r ≤min

2j(n+r−l),2−jld(w, z)−n−r . Thus

Z

∂Ω

bj(w)mrj(w)dσ(w). Z

d(w,z)≤2−j

2−jl

2−j(n+r)bj(w)dσ(w)

+

j−1

X

t=1

Z

2−t−1≤d(w,z)≤2−t

2−jl

2−t(n+r)bj(w)dσ(w)

.

j

X

t=1

2−jl2trM bj(z).2−jl2jrM bj(z).

Choosingr=l+ 1,we have W2(z)2kl.

k

X

j=1

2−(k−j)(r−l)M bj(z)≤

k

X

j=1

2−(k−j)M bj(z). (25)

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Combining the estimates (20,23,25) we finally obtain

|f(z)−P2k(z)|.

k

X

j=1

2−(k−j)M bj(z) +X

j>k

2−(j−k)lM bj(z),

which similarly to [5] implies

X

k=1

|f(z)−P2k(z)|2.

X

k=1

(M bk(z))2= Z

De(z,η)

∂f¯ (τ)

2ρ(τ)−2ldµ(τ)<∞.

This completes the proof of the theorem and it remains to prove lemma5.1.

Proof (of the lemma 5.1). Define gk(z) := 2−kl(P2k+1(z)−P2k(z)).

Letz∈∂Ω andτ∈Sk(z).Consider complex normal vectorn(z) =|∂ρ(z)|∂ρ(z) at z, complex tangent hyperplaneTz ={w ∈Cn :h∂ρ(z), w−zi= 0} and complex planeTz,τ , orthogonal toTz and containing the pointτ

Tz,τ :={τ+sn(z) :s∈C}. Projection of vectorτ∈Cto∂ΩT

Tz,τ we will denote asπz(τ).

Define Ωz,τ =ΩTTz,τ andγz,τ =∂Ωz,τ.There exist a conformal map ϕz,τ :Tz,τ \Ωz,τ →C\{w∈C:|w|= 1}such that ϕz,τ(∞) =∞, ϕz,τ(∞)>

0,and we could consider analytical inTz,τ \Ωz,τ function Gk(s) := gk(s)

ϕ2k+1z,τ (s). Applying to function Gk Dyn’kin maximal estimate from [4] for domain Tz,τ \ Ω(z, τ) we obtain the estimate

|Gk(τ)|. 1 ρ(τ)

Z

s∈Iz,τ

|Gk(s)| |ds|+ Z

∂Ωz,τ\Iz,τ

|Gk(s)| ρ(τ)m

|s−πz(τ)|m+1|ds|, whereIz,τ ={s∈γz,τ :|s−πz(τ)|<dist(τ, ∂Ωz,τ)/2},andm >0 could be chosen arbitrary large.

Note that |ϕz,τ(s)| −1≍dist(s, ∂Ωz,τ)≍2−k,thus|gk(s)| ≍ |Gk(s)|for s∈Dk(z)T

Tz,τ. Hence,

|gk(τ)|.

X

j=1

2−jm 1 2jρ(τ)

Z

s∈∂Ωz,τ

|s−πz(τ)|<2jρ(τ)

|gk(s)| |ds|. (26)

Since the boundary of the domainΩisC3-smooth, we can assume that the constant in this inequality (26) does not depend onz∈∂Ω andτ∈Ωε\Ω.

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Note that functiongk(τ+z−w) is holomorphic inw∈Tz,then estimating the mean we obtain

|gk(τ)| ≤ 1 ρ(τ)n−1

Z

|w−z|<

ρ(τ)

|gk(τ+z−w)|dµ2n−2(w)

.

X

j=1

2−jm 1 ρ(τ)n−1

Z

|w−z|<

ρ(τ)

2n−2(w) 2jρ(τ)

Z

s∈∂Ωz,τ

|s−πz(τ+z−w)|<2jρ(τ)

|gk(s)| |ds|

.

X

j=1

2−j(m−n+1) Z

B(z,2jρ(τ))

|gk(w)|dσ(w), (27)

wheredµ2n−2is Lebesgue measure in Tz

Assume that m > n−1, then |gk(τ)| . M gk(z), z ∈ ∂Ω, τ ∈ Dk(z).

Finally,

bk(z) =

 Z

Dk(z)

∂f¯ (τ)ρ(τ)−l

2dν(τ)

1/2

.

 Z

Dk(z)

gk(τ)ρ(τ)−l−1

2dν(τ)

1/2

.M ak(z)

 Z

Dk(z)

dν(τ) ρ(τ)2

1/2

.M ak(z) (28)

and the lemma is proved.

A Area-integral inequality for external Kor´anyi region

LetCnbe a strongly convex domain and η >0. For functiongL1(∂Ω) andlN we define a function

Il(g, z) =

Z

De(z,η)

Z

∂Ω

g(w)dS(w) h∂ρ(τ), τwin+l

2

l(τ)

1/2

, (29)

wherel(τ) =ρ(τ)n−2l−12n(τ) .

Theorem A.1 Letbe strongly convex domain andgLp(∂Ω), 1< p <,Then Z

∂Ω

Il(g, z)pdσ(z). Z

∂Ω

|g(z)|pdσ(z). (30)

Note that in the one-variable case the integral29gives the holomorphic function and the result of the theorem follows from [5].

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Definition 1 Assume, that defining functionρfor strongly convex domainhas the fol- lowing form nearz0∂Ω

ρ(z) = Im(zn) +

n

X

j,k=1

Ajkzjz¯k+O(|z|3). (31)

Define a set

D0(η, ε) ={τCn\:|τ1|2+. . .+|τn−1|2< ηIm(τn),

|Re(τn)|< ηIm(τn), |Im(τn)|< ε1}. (32) Theorem A.2 There exists such covering of the setε\−ε by open setsΓj such that for everyξΓj we can find a holomorphic change of coordinatesϕj(ξ,·) :CnCn such that

1. The mappingϕj(ξ,·)transforms functionρto the type (31) and could be expressed as follows

ϕj(ξ, z) =Φj(ξ)(zξ) +i(zξ)Bj(ξ)(zξ)en, (33) where matricesΦj(ξ), Bj(ξ)depend smooth onξΓj,anden= (0, . . . ,0,1).

2. Letψj(ξ,·)be an inverse map of ϕj(ξ,·),and letJj(ξ,·)be a complex Jacobian ofψ.

Note that real Jacobian is then equal to|Jj(ξ,·)|2=Jj(ξ,·)Jj(ξ,·), Then sup

τ∈Ωε\Ωε

Jj(ξ,·)Jj,·) .

ξξ

, (34) sup

τ∈Ωε\Ωε

ψj(ξ,·)ψj,·) .

ξξ

. (35) 3. There exist constants c >0, 0< η0, ε1<1such that

ϕj(ξ, De(ξ, η))D0(cη, cε), ψj(ξ, D0η)De(ξ, cη), for0< η < η0. (36) Proof Let ξ ∂Ω,by linear change of coordinates z = (zξ)Φ(ξ) we could obtain the following form for functionρ

ρ(z) =ρ(ξ+Φ−1(ξ)z) = Im(zn) +

n

X

j,k=1

A1jk(ξ)zj¯zk+ Re

n

X

j,k=1

A2jk(ξ)zjzk +O(

z 3).

Settingz′′n=zn +iA2jkzjzk andz′′j =zj, 1jn1,we have

ρ(z′′) = Im(zn) +

n

X

j,k=1

A1jk(ξ)zj′′z¯k′′+O(

z′′

3).

DenoteB(ξ) =Φ(ξ)A1(ξ)Φ(ξ),then

ϕ(ξ, z) =Φ(ξ)(zξ) +i(zξ)B(ξ)(zξ)en.

We choose Γj such that the matrixΦ(ξ) could be defined onΓj smoothly, this choice we denote asΦj,and the change corresponding to this matrix asϕj

ϕj(ξ, z) =Φj(ξ)(zξ) +i(zξ)Bj(ξ)(zξ)en.

Thus mappingsϕjsatisfy the first condition. Easily, the second condition also holds.

To prove the last condition (36) it is sufficient to show, that if function ρ has the form (31), then for somec, η0>0 we have

De(0, η)D0(cη), D0(η)De(0, cη),for0< η < η0.

(17)

Indeed, for the functionρof the form (31) the Kor´anyi sector could be expressed as follows De(0, η) ={τCn\:|τ1|2+. . .+|τn−1|2(ηρ(τ))2, |Re(τn)| ≤ηρ(τ), ρ(τ)< ε}

AssumeτDe(0, η),then

ρ(τ) = Im(τn) +

n

X

j,k=1

Ajkτjτ¯kIm(τn) +c0|Im(τn)|2

+c0(|τ1|2+. . .+|τn−1|+|Re(τn)|2)Im(τn) +c0|Im(τn)|2+c0ηρ(τ) +c0(ηρ(τ))2. (37) By choosingη0<1/(4c0) we haveρ(τ)cIm(τn) forτDe(0, η) and 0< η < η0.Hence, De(0, η)D0(cη) for 0< η < η0 andε1=cε.Note, that

ρ(τ) = Im(τn) +

n

X

j,k=1

Ajkτj¯τk>Im(τn) forτD0(η),

since matrix (Ajk) is strictly positive definite. Hence,D0(η)De(0, η).This ends the proof of the theorem.

Further we will assume, that the coveringε\−ε SN

j=1

Γjand mapsϕj, ψjare chosen by the theoremA.2. For covering{Γj}we consider a smooth decomposition of identity on

∂Ω:

χjCj), 0χj1, suppχjΓj,

N

X

j=1

χj(z) = 1, z∂Ω.

Fix the parameterη < η0and denoteD0=D0(η).Then by (36) Il(g, z)2

=

N

X

j=1

χj(z) Z

ϕj(z,De(z,η/c))

Z

∂Ω

g(w)Jj(z, τ)dS(w) h∂ρ(ψj(z, τ)), ψj(z, τ)win+l

2

dµ(τ) Im(τn)n−2l+1

.

N

X

j=1

Z

D0

Z

∂Ω

g(w)χ1/2j (z)Jj(z, τ)dS(w) h∂ρ(ψj(z, τ)), ψj(z, τ)win+l

2

dµ(τ)

Im(τn)n−2l+1. (38) We will consider the function

Kj(z, w)(τ) = χ1/2j (z)Jj(z, τ)

h∂ρ(ψj(z, τ)), ψj(z, τ)win+1 (39) as a map∂Ω×∂Ω L(C, L2(D0, dνl)),such that its values are operator of multiplica- tion fromCto L2(D0, dνl),where l(τ) = Im(τdµ(τ)

n)n−2l+1 is a measure on the regionD0. Throughout the proof of the theoremA.1j, lwill be fixed integers and the norm of function F in the spaceL2(D0, dνl) will be denoted askFk.

We will show that integral operator defined by kernel Kj is bounded onLp.To prove this we applyT1-theorem for transformations with operator-valued kernels formulated by Hyt¨onen and Weis in [8], taking in account that in our case concerned spaces are Hilbert.

Some details of the proof are similar to the proof of the boundedness of operator Cauchy- Leray-Fantappi`eKfor lineally convex domains introduced in [13]. Below we formulate the T1-theorem, adapted to our context.

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