■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲
■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲
❇➪❘❇❆❘❆
❉❊◆■❈❖▲
❉❖
❆▼❆❘❆▲
❘
❖❉❘■●❯❊❩
❈■◆❚❍❨
❆
▼❆❘■❆
❙❈❍◆❊■❉❊❘
▼❊◆❊●❍❊❚❚■
❈❘■❙❚■❆◆❆
❆◆❉❘❆❉❊
P❖❋❋
❆▲
❉■❋❊❘❊◆❈■❆■❙
❊
❖
❈➪▲❈❯▲❖
❆P❘
❖
❳■▼❆❉❖
✶ ❛
❊❞✐çã♦
❘✐♦
●r❛♥❞❡
❊❞✐t♦r❛
❞❛
❋❯❘
●
■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲
■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲ ■▼❊❋ ✲ ❋❯❘● ✲
❯♥✐✈
❡rs✐❞❛❞❡
❋❡❞❡r❛❧
❞♦
❘✐♦
●r❛♥❞❡
✲
❋❯❘
●
◆❖❚
❆❙
❉❊
❆
❯▲❆
❉❊
❈➪▲❈❯▲❖
■♥st✐t✉t♦
❞❡
▼❛t❡♠át✐❝❛✱
❊st❛tíst✐❝❛
❡
❋ís✐❝❛
✲
■▼❊❋
❇ár❜❛r❛
❘♦
❞r✐❣✉❡③
❈✐♥
t❤
②❛
▼❡♥❡❣❤❡tt✐
❈r✐st✐❛♥❛
P♦✛❛❧
s✐t❡s✳❣♦
♦❣❧❡✳❝
♦♠✴s✐t❡✴❝❛❧❝✉❧♦❢✉r❣
✷
◆♦t❛s
❞❡
❛✉❧❛
❞❡
❈á❧❝✉❧♦
✲
❋❯❘
■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼
❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲
■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯
❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■
▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊
❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲
❙✉♠ár✐♦
✶ ❉✐❢❡r❡♥❝✐❛✐s ❡ ♦ ❈á❧❝✉❧♦ ❆♣r♦①✐♠❛❞♦ ✹
✶✳✶ ❆❝rés❝✐♠♦s ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✹ ✶✳✷ ❉✐❢❡r❡♥❝✐❛❧ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✺ ✶✳✸ ■♥t❡r♣r❡t❛çã♦ ●❡♦♠étr✐❝❛ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✻ ✶✳✹ ❆♣❧✐❝❛çã♦ ❞❡ ❉✐❢❡r❡♥❝✐❛✐s ♥❛ ❋ís✐❝❛ ✲ P❡rí♦❞♦ ❞❡ ✉♠ Pê♥❞✉❧♦ ❙✐♠♣❧❡s ✶✸ ✶✳✺ ❆♣❧✐❝❛çã♦ ❞❡ ❉✐❢❡r❡♥❝✐❛✐s ✲ ❈á❧❝✉❧♦ ❞❡ ❊rr♦s ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✶✸ ✶✳✺✳✶ EM ax ✲ ❊rr♦ ▼á①✐♠♦ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✶✹
✶✳✺✳✷ ERel ✲ ❊rr♦ ❘❡❧❛t✐✈♦ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✶✹
✶✳✺✳✸ EP c ✲ ❊rr♦ P❡r❝❡♥t✉❛❧ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✶✹
✶✳✻ ▲✐st❛ ❞❡ ❊①❡r❝í❝✐♦s ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✳ ✶✼
■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼
❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
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✲
■▼❊❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯
❘
●
✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■
▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲❋❯❘
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✲❋❯❘
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✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊❋
✲❋❯❘
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✲■▼❊
❋
✲❋❯❘
●
✲■▼❊❋
✲❋❯❘
●
✲
❈❛♣ít✉❧♦ ✶
❉✐❢❡r❡♥❝✐❛✐s ❡ ♦ ❈á❧❝✉❧♦ ❆♣r♦①✐♠❛❞♦
❉✐✈❡rs♦s ♣r♦❜❧❡♠❛s ♥❛s ár❡❛s ❞❡ ▼❛t❡♠át✐❝❛✱ ◗✉í♠✐❝❛ ♦✉ ❊♥❣❡♥❤❛r✐❛ ❡stã♦ ♣r❡♦❝✉♣❛❞♦s ❝♦♠ ❛s ✐♥t❡r✲r❡❧❛çõ❡s ❡♥tr❡ ❛s ♠✉❞❛♥ç❛s ♥❛s ♣r♦♣r✐❡❞❛❞❡s ❢ís✐❝❛s ♦✉ ❣❡♦♠étr✐❝❛s✱ ❞❡❝♦rr❡♥t❡s ❞❛s ✈❛r✐❛çõ❡s ❡♠ ✉♠ ♦✉ ♠❛✐s ♣❛râ♠❡tr♦s q✉❡ ❞❡✜♥❡♠ ♦ ❡st❛❞♦ ✐♥✐❝✐❛❧ ❞❡ ✉♠ s✐st❡♠❛✳ ❊st❛s ♠✉❞❛♥ç❛s ♣♦❞❡♠ s❡r ❣r❛♥❞❡s ♦✉ ♣❡q✉❡♥❛s✳ P❛rt✐❝✉❧❛r♠❡♥t❡✱ ♥❡st❡ ❧✐✈r♦✱ s❡rã♦ ❛❜♦r❞❛❞❛s ❛s ♣❡q✉❡♥❛s ✈❛r✐❛çõ❡s✳
❉✉r❛♥t❡ ♦ ❡st✉❞♦ ❞❛s ❞❡r✐✈❛❞❛s✱ dy
dx ❢♦✐ ✐♥t❡r♣r❡t❛❞♦ ❝♦♠♦ ✉♠❛ ú♥✐❝❛
❡♥t✐❞❛❞❡ r❡♣r❡s❡♥t❛♥❞♦ ❛ ❞❡r✐✈❛❞❛ ❞❡y❡♠ r❡❧❛çã♦ ❛ x✳ ◆❡st❡ ❧✐✈r♦ sã♦ ✐♥tr♦❞✉③✐❞♦s
s✐❣♥✐✜❝❛❞♦s ❞✐❢❡r❡♥t❡s ♣❛r❛ dy ❡ dx✱ ♦ q✉❡ ♣❡r♠✐t✐rá tr❛t❛r dy
dx ❝♦♠♦ ✉♠❛ r❛③ã♦✳
❚❛♠❜é♠ s❡rá ❞✐s❝✉t✐❞♦ ❝♦♠♦ ❛s ❞❡r✐✈❛❞❛s ♣♦❞❡♠ s❡r ✉s❛❞❛s ♣❛r❛ ❛♣r♦✲ ①✐♠❛r ❢✉♥çõ❡s ❝♦♠♣❧✐❝❛❞❛s ♣♦r ❢✉♥çõ❡s ❧✐♥❡❛r❡s ♠❛✐s s✐♠♣❧❡s✳ ❚❛✐s ❢✉♥çõ❡s sã♦ ❞❡♥♦♠✐♥❛❞❛s ❧✐♥❡❛r✐③❛çõ❡s ❡ s❡ ❜❛s❡✐❛♠ ❡♠ r❡t❛s t❛♥❣❡♥t❡s✳
✶✳✶ ❆❝rés❝✐♠♦s
❙❡❥❛y=f(x)✉♠❛ ❢✉♥çã♦✳ ❉❡✜♥❡✲s❡ ♦ ❛❝rés❝✐♠♦ ❞❡x✱ ❞❡♥♦t❛❞♦ ♣♦r∆x✱
❝♦♠♦✿
∆x=x2−x1,
♦♥❞❡ x1, x2 ∈D(f)✳
❆ ✈❛r✐❛çã♦ ❞❡ x♦r✐❣✐♥❛ ✉♠❛ ❝♦rr❡s♣♦♥❞❡♥t❡ ✈❛r✐❛çã♦ ❞❡y✱ ❞❡♥♦t❛❞❛ ♣♦r
∆y✱ ❞❛❞❛ ♣♦r✿
∆y =f(x2)−f(x1),
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✶✳✷✳ ❉■❋❊❘❊◆❈■❆▲
♦✉
∆y=f(x1 + ∆x)−f(x1).
◆❛ ❋✐❣✉r❛ ✶✳✶✱ ♣♦❞❡✲s❡ ♦❜s❡r✈❛r ❣r❛✜❝❛♠❡♥t❡ ♦ s✐❣♥✐✜❝❛❞♦ ❞❡∆x ❡∆y✳
❋✐❣✉r❛ ✶✳✶✿ ❘❡♣r❡s❡♥t❛çã♦ ❣rá✜❝❛ ❞♦s ✐♥❝r❡♠❡♥t♦s∆x❡ ∆y✳
✶✳✷ ❉✐❢❡r❡♥❝✐❛❧
❉❡✜♥✐çã♦ ✶✳✷✳✶✳ ❉✐❢❡r❡♥❝✐❛❧ ❞❡ ✉♠❛ ❢✉♥çã♦ é ♦ ❛❝rés❝✐♠♦ s♦❢r✐❞♦ ♣❡❧❛ ♦r❞❡♥❛❞❛ ❞❛
r❡t❛ t❛♥❣❡♥t❡ ❝♦rr❡s♣♦♥❞❡♥t❡ ❛ ✉♠ ❛❝rés❝✐♠♦ ∆xs♦❢r✐❞♦ ♣♦r x✳
❉❡✜♥✐çã♦ ✶✳✷✳✷✳ ❙❡❥❛♠ y = f(x) ✉♠❛ ❢✉♥çã♦ ❞❡r✐✈á✈❡❧ ❡ ∆x ✉♠ ❛❝rés❝✐♠♦ ❞❡ x✳
❉❡✜♥❡✲s❡✿
❛✮ ❛ ❞✐❢❡r❡♥❝✐❛❧ ❞❛ ✈❛r✐á✈❡❧ ✐♥❞❡♣❡♥❞❡♥t❡ x✱ ❞❡♥♦t❛❞❛ ♣♦rdx✱ ❝♦♠♦ ∆x=dx✳
❜✮ ❛ ❞✐❢❡r❡♥❝✐❛❧ ❞❛ ✈❛r✐á✈❡❧ ❞❡♣❡♥❞❡♥t❡ y✱ ❞❡♥♦t❛❞❛ ♣♦r dy✱ ❝♦♠♦ dy=f′(x)·∆x✳
❉❡ ❛❝♦r❞♦ ❝♦♠ ❛ ❉❡✜♥✐çã♦ ✶✳✷✳✷✱ é ♣♦ssí✈❡❧ ❡s❝r❡✈❡r dy = f′(x)·dx ♦✉ dy
dx =f ′(x)✳
❆ ♥♦t❛çã♦ dy
dx✱ ❥á ✉s❛❞❛ ♣❛r❛ f
′(x)✱ ♣♦❞❡ ❛❣♦r❛ s❡r ❝♦♥s✐❞❡r❛❞❛ ✉♠ q✉♦✲
❝✐❡♥t❡ ❡♥tr❡ ❞✉❛s ❞✐❢❡r❡♥❝✐❛✐s✳
❖❜s❡r✈❛çã♦ ✶✳✷✳✶✳ ◗✉❛♥❞♦ ◆❡✇t♦♥ ❡ ▲❡✐❜♥✐③ ♣✉❜❧✐❝❛r❛♠ ✐♥❞❡♣❡♥❞❡♥t❡♠❡♥t❡ s❡✉s
❡st✉❞♦s r❡❧❛❝✐♦♥❛❞♦s ❛♦ ❈á❧❝✉❧♦✱ ❝❛❞❛ ✉♠ ✉s♦✉ ✉♠❛ ♥♦t❛çã♦ ♣❛r❛ ❛ ❞❡r✐✈❛❞❛✳ ◆❡st❡
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✶✳✸✳ ■◆❚❊❘P❘❊❚❆➬➹❖ ●❊❖▼➱❚❘■❈❆
❝✉rs♦✱ ❛❞♦t❛♠✲s❡ ❛s ♥♦t❛çõ❡s ❧✐♥❤❛ ✭❞❡ ▲❛❣r❛♥❣❡✮✱ y′✱ ❡ ❞❡ ♦♣❡r❛❞♦r ❞✐❢❡r❡♥❝✐❛❧ ✭❞❡
▲❡✐❜♥✐③✮✱ dy
dx✳ ❆ ♥♦t❛çã♦ ❞♦ ♣♦♥t♦✱ ❞❡s❡♥✈♦❧✈✐❞❛ ♣♦r ◆❡✇t♦♥✱ ♥ã♦ s❡rá ❡①♣❧♦r❛❞❛
♥❡st❡ ♠❛t❡r✐❛❧✳
❊①❡♠♣❧♦ ✶✳✷✳✶✳ ❙❡ f(x) = 3x2
−2x+ 1✱ ❞❡t❡r♠✐♥❡ dy✳
❙♦❧✉çã♦✿
❚❡♠✲s❡ q✉❡ dy =f′(x)dx✳ P❛r❛ f(x) = 3x2
−2x+ 1✱ ❛♣❧✐❝❛♥❞♦ ❛s r❡❣r❛s
❞❡ ❞❡r✐✈❛❞❛ ❞❛ s✉❜tr❛çã♦✱ ❞❡r✐✈❛❞❛ ❞❛ ♣♦tê♥❝✐❛ ❞❡x❡ ❞❛ ❞❡r✐✈❛❞❛ ❞❡ ✉♠❛ ❝♦♥st❛♥t❡✱ f′(x) = 6x−2✳ ▲♦❣♦✱dy = (6x−2)dx✳
❊①❡♠♣❧♦ ✶✳✷✳✷✳ ❈❛❧❝✉❧❛r ❛ ❞✐❢❡r❡♥❝✐❛❧ ❞❛s ❢✉♥çõ❡s✿
❛✮ y=√1 +x2
❜✮ y= 1 3tg
3
(x) + tg(x)✳
❙♦❧✉çã♦✿
❛✮ ❈♦♠♦ dy =f′(x)dx ❡y=f(x) =√1 +x2✱ t❡♠✲s❡✱ ❛♣❧✐❝❛♥❞♦ ❛ r❡❣r❛ ❞❛ ❝❛❞❡✐❛✿
f′(x) = √ x
1 +x2✳ ▲♦❣♦✱dy =f
′(x)dx= √ x
1 +x2dx✳
❜✮ ❆♣❧✐❝❛♥❞♦ ❛s r❡❣r❛s ❞❡ ❞❡r✐✈❛❞❛ ❞❛ ♣♦tê♥❝✐❛✱ ❞❛ ❝❛❞❡✐❛ ❡ ❞❛ ❞❡r✐✈❛❞❛ ❞❛ t❛♥❣❡♥t❡✱ t❡♠✲s❡✿
f′(x) = 1
3 ·3tg
2
(x)·sec2
(x) + sec2
(x)
= sec2
(x)[tg2
(x) + 1]
f′(x) = sec4
(x).
P♦rt❛♥t♦✱ dy= sec4
(x)dx✳
✶✳✸ ■♥t❡r♣r❡t❛çã♦ ●❡♦♠étr✐❝❛
❙❡❥❛ y = f(x) ✉♠❛ ❢✉♥çã♦ ❞❡r✐✈á✈❡❧✱ ❝✉❥♦ ❣rá✜❝♦ é ✐❧✉str❛❞♦ ♥❛ ❋✐❣✉r❛
✶✳✸✳
❈♦♥s✐❞❡r❡ ♦s ♣♦♥t♦sP(x1, f(x1))✱M(x2, f(x1))❡Q(x2, f(x2))✳ ❖ ❛❝rés✲
❝✐♠♦∆xq✉❡ ❞❡✜♥❡ ❛ ❞✐❢❡r❡♥❝✐❛❧dx❡stá ❣❡♦♠❡tr✐❝❛♠❡♥t❡ r❡♣r❡s❡♥t❛❞♦ ♣❡❧❛ ♠❡❞✐❞❛
❞♦ s❡❣♠❡♥t♦ P M✳
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✶✳✸✳ ■◆❚❊❘P❘❊❚❆➬➹❖ ●❊❖▼➱❚❘■❈❆
❋✐❣✉r❛ ✶✳✷✿ ■♥t❡r♣r❡t❛çã♦ ❣❡♦♠étr✐❝❛ ❞❛ ❞✐❢❡r❡♥❝✐❛❧✳
❖ ❛❝rés❝✐♠♦ ∆y ❡stá r❡♣r❡s❡♥t❛❞♦ ♣❡❧❛ ♠❡❞✐❞❛ ❞♦ s❡❣♠❡♥t♦ M Q✳
❙❡❥❛ t ❛ r❡t❛ t❛♥❣❡♥t❡ à ❝✉r✈❛ y =f(x) ♥♦ ♣♦♥t♦ P✳ ❊st❛ r❡t❛ ❝♦rt❛ ❛
r❡t❛ ✈❡rt✐❝❛❧x=x2♥♦ ♣♦♥t♦R✱ ❢♦r♠❛♥❞♦ ♦ tr✐â♥❣✉❧♦ r❡tâ♥❣✉❧♦P M R✳ ❆ ✐♥❝❧✐♥❛çã♦
✭❝♦❡✜❝✐❡♥t❡ ❛♥❣✉❧❛r✮ ❞❡st❛ r❡t❛ é ❞❛❞❛ ♣♦r f′(x1) = tg(α)✳
❖❜s❡r✈❛♥❞♦ ♦ tr✐â♥❣✉❧♦ P M R✱ é ♣♦ssí✈❡❧ ❡s❝r❡✈❡r✿
f′(x
1) = tg(α) =
M R P M.
♦♥❞❡M R❡P M sã♦ r❡s♣❡❝t✐✈❛♠❡♥t❡ ❛s ♠❡❞✐❞❛s ❞♦s s❡❣♠❡♥t♦sM R❡P M✳ ❯s❛♥❞♦
♦ ❢❛t♦ ❞❡ q✉❡ f′(x) = dy
dx ❝♦♥❝❧✉✐✲s❡ q✉❡ dy=M R✱ ❥á q✉❡ dx=P M✳
P❡❧❛ s✉❜st✐t✉✐çã♦ ❞❡ ∆y ♣♦r dy ❝♦♠❡t❡✲s❡ ✉♠ ❡rr♦ q✉❡ é ❝❛❧❝✉❧❛❞♦ ♣❡❧♦
♠ó❞✉❧♦ ❞❛ ❞✐❢❡r❡♥ç❛ ❡♥tr❡ ♦ ✈❛❧♦r ❡①❛t♦ ❞❛ ✈❛r✐❛çã♦ ❞❡ y✭∆y✮ ❡ ♦ ✈❛❧♦r ❛♣r♦①✐♠❛❞♦
❞❛ ✈❛r✐❛çã♦ ❞❡ y ✭dy✮✱ ✐st♦ é✱
e=|∆y−dy|.
❖ q✉❡ ❛❝♦♥t❡❝❡ ❝♦♠ ∆y−dy q✉❛♥❞♦ ∆x t♦r♥❛✲s❡ ♠✉✐t♦ ♣❡q✉❡♥♦❄
❖❜s❡r✈❛✲s❡ q✉❡✱ q✉❛♥❞♦ ∆x t♦r♥❛✲s❡ ♠✉✐t♦ ♣❡q✉❡♥♦✱ ♦ ♠❡s♠♦ ♦❝♦rr❡
❝♦♠ ❛ ❞✐❢❡r❡♥ç❛ ∆y−dy✳
❊♠ ❡①❡♠♣❧♦s ♣rát✐❝♦s✱ ❝♦♥s✐❞❡r❛✲s❡ ∆y ≈ dy ✭❧ê✲s❡✿ ∆y ❛♣r♦①✐♠❛❞❛✲
♠❡♥t❡ ✐❣✉❛❧ ❛ dy✮✱ ❞❡s❞❡ q✉❡ ♦ ∆x ❝♦♥s✐❞❡r❛❞♦ s❡❥❛ ✉♠ ✈❛❧♦r ♣❡q✉❡♥♦✳
❊♠ ♦✉tr❛s ♣❛❧❛✈r❛s✱ ♣❛r❛ ✈❛❧♦r❡s ♣❡q✉❡♥♦s ❞❡ ∆x✱
∆y≈dy.
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✶✳✸✳ ■◆❚❊❘P❘❊❚❆➬➹❖ ●❊❖▼➱❚❘■❈❆
❙❛❜❡♥❞♦✲s❡ q✉❡ dy =f′(x)∆x✱ t❡♠✲s❡✿
∆y≈f′(x)∆x.
P❡❧❛ ❉❡✜♥✐çã♦ ✶✳✷✳✷✿
∆y =f(x+ ∆x)−f(x),
❧♦❣♦✱
f(x+ ∆x)−f(x)≈f′(x)∆x,
♦✉ ❛✐♥❞❛✱
f(x+ ∆x)≈f′(x)∆x+f(x). ✭✶✳✸✳✶✮
❆ ❡st❡ ♣r♦❝❡ss♦ ❝❤❛♠❛✲s❡ ❞❡ ❧✐♥❡❛r✐③❛çã♦ ❞❡ ❢✱ ❡♠ t♦r♥♦ ❞❡ x✳
❊①❡♠♣❧♦ ✶✳✸✳✶✳ ❈♦♠♣❛r❡ ♦s ✈❛❧♦r❡s ❞❡∆y ❡dy s❡y=x3
+x2
−2x+ 1 ❡x ✈❛r✐❛r
✭❛✮ ❞❡ 2 ♣❛r❛ 2,05 ❡ ✭❜✮ ❞❡ 2 ♣❛r❛ 2,01✳
❙♦❧✉çã♦✿
✭❛✮ ❚❡♠✲s❡ q✉❡ ∆x= 0,05✱ ❛ss✐♠ ♣♦r ❞❡✜♥✐çã♦✿
∆y =f(x+ ∆x)−f(x)
=f(2 + 0,05)−f(2)
= [(2,05)3
+ (2,05)2
−2(2,05) + 1]−[23
+ 22
−2(2) + 1] ∆y = 0,717625.
P❛r❛ ♦ ❝á❧❝✉❧♦ ❞❡ dy✱ q✉❛♥❞♦ x= 2 ❡∆x= 0,05 t❡♠✲s❡✿
dy =f′(x)dx= (3x2
+ 2x−2)dx
= [3(2)2
+ 2(2)−2]0,05
dy = 0,7.
❖❜s❡r✈❡ q✉❡ ♦ ❡rr♦ ❝♦♠❡t✐❞♦ ❛♦ ✉s❛r ❞✐❢❡r❡♥❝✐❛✐s e = |∆y−dy| é ❞❡
✵✱✵✶✼✻✷✺✳
✭❜✮ ❚❡♠✲s❡ q✉❡ ∆x= 0,01✱ ❛ss✐♠ ♣♦r ❞❡✜♥✐çã♦✿
∆y =f(x+ ∆x)−f(x)
=f(2 + 0,01)−f(2)
= [(2,01)3
+ (2,01)2
−2(2,01) + 1]−[23
+ 22
−2(2) + 1] ∆y = 0,140701.
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✶✳✸✳ ■◆❚❊❘P❘❊❚❆➬➹❖ ●❊❖▼➱❚❘■❈❆
P❛r❛ ♦ ❝á❧❝✉❧♦ ❞❡ dy✱ q✉❛♥❞♦ x= 2 ❡∆x= 0,01 t❡♠✲s❡✿
dy =f′(x)dx= (3x2
+ 2x−2)dx
= [3(2)2
+ 2(2)−2]0,01
dy = 0,14.
❖❜s❡r✈❛çã♦ ✶✳✸✳✶✳ ❖❜s❡r✈❡ ❛ ❢✉♥çã♦ ❞♦ ❊①❡♠♣❧♦ ✶✳✸✳✶✳ ❈♦♠♣❛r❛♥❞♦ ∆y ❝♦♠
dy ♣❡r❝❡❜❡✲s❡ q✉❡ ❛ ❛♣r♦①✐♠❛çã♦ ♣♦r ❞✐❢❡r❡♥❝✐❛✐s dy t♦r♥❛✲s❡ ♠❡❧❤♦r à ♠❡❞✐❞❛ q✉❡
∆x ✜❝❛ ♠❡♥♦r✳
❉❡ ❢❛t♦✱ ♣❛r❛ ♦ ✐t❡♠ ✭❛✮✱ ♦ ❡rr♦ ❝♦♠❡t✐❞♦ ❛♦ ❡♠♣r❡❣❛r ❞✐❢❡r❡♥❝✐❛✐s é
e = |∆y −dy| = |0,717625−0,7| = 0,017625✳ ❊♥q✉❛♥t♦ q✉❡ ♣❛r❛ ♦ ✐t❡♠ ✭❜✮✱
♦♥❞❡ ∆x é ♠❡♥♦r✱ ♦ ❡rr♦ ❝♦♠❡t✐❞♦ ❛♦ ❡♠♣r❡❣❛r ❞✐❢❡r❡♥❝✐❛✐s é e = |∆y −dy| =
|0,140701−0,14|= 0,000701✳
❖❜s❡r✈❛çã♦ ✶✳✸✳✷✳ ❊♠ ❛❧❣✉♥s ❝❛s♦s é ♠❛✐s ❢á❝✐❧ ❝❛❧❝✉❧❛r ♦ dy✱ ♣♦✐s ♣❛r❛ ❢✉♥çõ❡s
♠❛✐s ❝♦♠♣❧✐❝❛❞❛s ♣♦❞❡ s❡r ✐♠♣♦ssí✈❡❧ ❝❛❧❝✉❧❛r ❡①❛t❛♠❡♥t❡ ♦ ✈❛❧♦r ❞❡ ∆y✳ ◆❡ss❡s
❝❛s♦s✱ ❛ ❛♣r♦①✐♠❛çã♦ ♣♦r ❞✐❢❡r❡♥❝✐❛✐s t♦r♥❛✲s❡ ♠✉✐t♦ út✐❧✳
❊①❡♠♣❧♦ ✶✳✸✳✷✳ ❙❡ y = 2x2
−6x+ 5✱ ❝❛❧❝✉❧❡ ♦ ❛❝rés❝✐♠♦ ∆y ♣❛r❛ x = 3 ❡ ∆x= 0,001✳
❙♦❧✉çã♦✿
P❡❧❛ ❞❡✜♥✐çã♦ ❞❡ ∆y✱ ❡s❝r❡✈❡✲s❡✿
∆y = f(x1 + ∆x)−f(x1)
= f(3 + 0,001)−f(3)
= [2(3,001)2
−6(3,001) + 5]−[2(32
)−6(3) + 5]
= 5,006002−5
∆y = 0,006002.
P♦rt❛♥t♦ ♦ ❛❝rés❝✐♠♦ ∆y= 0,006002✳
❊①❡♠♣❧♦ ✶✳✸✳✸✳ ❙❡ y = 6x2
−4✱ ❝❛❧❝✉❧❡ ♦ ❛❝rés❝✐♠♦ ∆y ❡ dy ♣❛r❛ x = 2 ❡ ∆x= 0,001✳
❙♦❧✉çã♦✿
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✶✳✸✳ ■◆❚❊❘P❘❊❚❆➬➹❖ ●❊❖▼➱❚❘■❈❆
❯t✐❧✐③❛♥❞♦ ❛ ❞❡✜♥✐çã♦ ❞❡ ∆y✱ t❡♠✲s❡
∆y = f(x1+ ∆x)−f(x1)
= f(2 + 0,001)−f(2)
= [6·(2,001)2
−4]−[6(22
)−4]
= 20,024006−20
∆y = 0,024006.
P♦rt❛♥t♦✱ ∆y= 0,024006✳
P❡❧❛ ❞❡✜♥✐çã♦ ❞❡ dy ❡ s❛❜❡♥❞♦ q✉❡ f(x) = 6x2
−4✱ t❡♠✲s❡✿
dy = f′(x)dx
= 12x∆x
= 12(2)(0,001)
dy = 0,024.
▲♦❣♦✱ dy = 0,024✳
❖❜s❡r✈❛✲s❡ q✉❡ ❛ ❞✐❢❡r❡♥ç❛|∆y−dy|= 0,000006s❡r✐❛ ♠❡♥♦r✱ ❝❛s♦ ❢♦ss❡
✉s❛❞♦ ✉♠ ✈❛❧♦r ♠❡♥♦r q✉❡ ✵✱✵✵✶ ♣❛r❛ ∆x✳
❊①❡♠♣❧♦ ✶✳✸✳✹✳ ❈❛❧❝✉❧❡ ✉♠ ✈❛❧♦r ❛♣r♦①✐♠❛❞♦ ♣❛r❛ p3
65,5✉s❛♥❞♦ ❞✐❢❡r❡♥❝✐❛✐s✳
❙♦❧✉çã♦✿
❙❡❥❛y=f(x)❛ ❢✉♥çã♦ ❞❡✜♥✐❞❛ ♣♦rf(x) = √3
x✳ ❆♣❧✐❝❛♥❞♦ ❛ ❧✐♥❡❛r✐③❛çã♦
❞❛ ❢✉♥çã♦ f✱ r❡♣r❡s❡♥t❛❞❛ ♣❡❧❛ ❡q✉❛çã♦ ✭✶✳✸✳✶✮✱ ❡s❝r❡✈❡✲s❡✿
y+dy=√3
x+ ∆x
❡
dy= 1
3x23
dx.
❚❡♠✲s❡ x = 64 ❡ ∆x = 1,5✱ ♣♦✐s ✻✹ é ♦ ❝✉❜♦ ♣❡r❢❡✐t♦ ♠❛✐s ♣ró①✐♠♦ ❞❡
✻✺✱✺✳
P♦rt❛♥t♦✱
x+ ∆x= 65,5
dx= ∆x= 1,5
y=√3
64 = 4
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✶✳✸✳ ■◆❚❊❘P❘❊❚❆➬➹❖ ●❊❖▼➱❚❘■❈❆
❡
dy= 1
3(64)23 ·
1,5 = 1,5
3·16 = 0,03125.
▲♦❣♦✱
3
p
65,5 = p3
64 + 1,5≈y+dy.
❋✐♥❛❧♠❡♥t❡✱
3
p
65,5≈y+dy= 4 + 0,03125≈4,03125.
❖❜s❡r✈❡ q✉❡✱ ❛♦ ✉t✐❧✐③❛r ✉♠❛ ❝❛❧❝✉❧❛❞♦r❛✱ ♦❜té♠✲s❡ q✉❡
3
p
65,5≈4,0310089894.
P♦rt❛♥t♦ ♦ ❡rr♦ ❝♦♠❡t✐❞♦ ❛♦ ✉t✐❧✐③❛r ❞✐❢❡r❡♥❝✐❛✐s é ❞❡ ✵✱✵✵✵✷✹✶✵✶✵✻✱ ♦✉ s❡❥❛✱ ❞❡ ✷✱✹✶✵✶✵✻×10−4✳
❊①❡♠♣❧♦ ✶✳✸✳✺✳ ❖❜t❡♥❤❛ ✉♠ ✈❛❧♦r ❛♣r♦①✐♠❛❞♦ ♣❛r❛ ♦ ✈♦❧✉♠❡ ❞❡ ✉♠❛ ✜♥❛ ❝♦r♦❛
❝✐❧í♥❞r✐❝❛ ❞❡ ❛❧t✉r❛ ✶✷ ♠✱ r❛✐♦ ✐♥t❡r✐♦r ✼ ♠ ❡ ❡s♣❡ss✉r❛ ✵✱✵✺ ♠✳ ❉❡t❡r♠✐♥❡ ♦ ❡rr♦ ❞❡❝♦rr❡♥t❡ ❞❛ ✉t✐❧✐③❛çã♦ ❞❡ ❞✐❢❡r❡♥❝✐❛✐s✳
❙♦❧✉çã♦✿
❋✐❣✉r❛ ✶✳✸✿ ❈♦r♦❛ ❝✐❧í♥❞r✐❝❛
❆ ❋✐❣✉r❛ ✶✳✸ r❡♣r❡s❡♥t❛ ♦ só❧✐❞♦ ❞❡ ❛❧t✉r❛ h✱ r❛✐♦ ✐♥t❡r✐♦r r ❡ ❡s♣❡ss✉r❛
∆r✳ ❖ ✈♦❧✉♠❡ ❞♦ ❝✐❧✐♥❞r♦ ✐♥t❡r✐♦r é ❞❛❞♦ ♣♦r✿
V =πr2·h=π(7)2
·12 = 588π♠3.
❍❛✈❡♥❞♦ ✉♠ ❛❝rés❝✐♠♦ ∆r✱ ♦ ✈♦❧✉♠❡ ❞❛ ❝♦r♦❛ s❡rá ✐❣✉❛❧ à ✈❛r✐❛çã♦∆V
❡♠ V✳ ❯s❛♥❞♦ ❞✐❢❡r❡♥❝✐❛✐s✱ t❡♠✲s❡✿
∆V ≈dV
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✶✳✸✳ ■◆❚❊❘P❘❊❚❆➬➹❖ ●❊❖▼➱❚❘■❈❆
❡
dV = 2πr·h·∆r
dV = 2π(7)(12)(0,05) = 8,4π♠3
.
❖ ✈♦❧✉♠❡ ❡①❛t♦ ❞❛ ❝♦r♦❛ ❝✐❧í♥❞r✐❝❛ é✿
∆V = π(r+ ∆r)2
·h−πr2
·h
= π(7,05)2
·12−π·(72
)·12
= 596,43π−588π
∆V = 8,43π♠3
.
P♦rt❛♥t♦✱ ♦ ❡rr♦ ❝♦♠❡t✐❞♦ ♥❛ ❛♣r♦①✐♠❛çã♦ ♣♦r ❞✐❢❡r❡♥❝✐❛✐s é e=|∆V − dV|= 0,03π♠3✳
❊①❡♠♣❧♦ ✶✳✸✳✻✳ ❯♠❛ ♣❧❛❝❛ q✉❛❞r❛❞❛ ❞❡ ❧❛❞♦x✱ ❞❡ ❡s♣❡ss✉r❛ ❞❡s♣r❡③í✈❡❧✱ é ❛q✉❡✲
❝✐❞❛✳ ❖ ♣r♦❝❡ss♦ ❞❡ ❛q✉❡❝✐♠❡♥t♦ ♣r♦✈♦❝❛ ✉♠❛ ❞✐❧❛t❛çã♦ ♥❛ ♣❧❛❝❛✳ ❆❞♠✐t✐♥❞♦ ✉♠❛ ❞✐❧❛t❛çã♦ ✉♥✐❢♦r♠❡✱ ♠❛♥t❡♥❞♦ ❛ ❢♦r♠❛ q✉❛❞r❛❞❛✱ ❝❛❧❝✉❧❡ ❛ ✈❛r✐❛çã♦ ❞❛ ár❡❛ ❡♠ ❢✉♥çã♦ ❞❛ ✈❛r✐❛çã♦ ❞❡ s❡✉ ❧❛❞♦✱ ∆x✱ ♦❝♦rr✐❞❛ ❞❡✈✐❞♦ ❛♦ ♣r♦❝❡ss♦ ❞❡ ❛q✉❡❝✐♠❡♥t♦✳
❊st✐♠❡ ❛ ✈❛r✐❛çã♦ ❞❛ ár❡❛ ✉t✐❧✐③❛♥❞♦ ❞✐❢❡r❡♥❝✐❛✐s✳ ■♥t❡r♣r❡t❡ ♦ r❡s✉❧t❛❞♦✳
❙♦❧✉çã♦✿ ❆ ♣❧❛❝❛ q✉❛❞r❛❞❛ ✐♥✐❝✐❛❧♠❡♥t❡ t❡♠ ❧❛❞♦ ❞❡ ♠❡❞✐❞❛ x✳ P♦rt❛♥t♦✱ s✉❛ ár❡❛
✈❛❧❡ A(x) =x2✳
❆♣ós ♦ ❛q✉❡❝✐♠❡♥t♦✱ ❛ ♠❡❞✐❞❛ ❞♦ s❡✉ ❧❛❞♦ ❛✉♠❡♥t❛ ❡♠ ∆x ✉♥✐❞❛❞❡s✳
P♦rt❛♥t♦✱ ❡ss❛ ♠❡❞✐❞❛ ✈❛r✐❛ ❞❡x♣❛r❛x+ ∆x❡ ❛ ár❡❛ ❞❛ ♣❧❛❝❛✱ ❛♣ós ♦ ❛q✉❡❝✐♠❡♥t♦
é✱
A(x+ ∆x) = (x+ ∆x)2
=x2+ 2x∆x+ (∆x)2
.
❆ ✈❛r✐❛çã♦ ❞❛ ár❡❛ ❞♦ q✉❛❞r❛❞♦ q✉❛♥❞♦ ❛ ♠❡❞✐❞❛ ✈❛r✐❛ ❞❡x♣❛r❛x+ ∆x
é✱
∆A=A(x+ ∆x)−A(x) =x2
+ 2x∆x+ (∆x)2
−x2
= 2x∆x+ (∆x)2
.
P♦r ♦✉tr♦ ❧❛❞♦✱ ❡♠ t❡r♠♦s ❞❡ ❞✐❢❡r❡♥❝✐❛✐s✱ ❛ ✈❛r✐❛çã♦ ❞❛ ár❡❛ ♣♦❞❡ s❡r ❡s❝r✐t❛ ❝♦♠♦✱
dA =A′(x)dx= 2xdx= 2x∆x.
❖❜s❡r✈❡ q✉❡ ♦ ❡rr♦ ❝♦♠❡t✐❞♦ ❛♦ ✉t✐❧✐③❛r ❞✐❢❡r❡♥❝✐❛✐s é e=|∆A−dA|= (∆x)2✱ ♣♦rt❛♥t♦ q✉❛♥❞♦ ♦ ❛❝rés❝✐♠♦
∆x é ♠✉✐t♦ ♣❡q✉❡♥♦✱ ♦ ✈❛❧♦r ❞♦ ❞✐❢❡r❡♥❝✐❛❧ dA
♣♦❞❡ s❡r ❞✐t❛ ❝♦♠♦ ✉♠❛ ❜♦❛ ❛♣r♦①✐♠❛çã♦ ♣❛r❛ ❛ ✈❛r✐❛çã♦ ❞❛ ár❡❛✳
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✶✳✹✳ ❆P▲■❈❆➬➹❖ ❉❊ ❉■❋❊❘❊◆❈■❆■❙ ◆❆ ❋❮❙■❈❆ ✲ P❊❘❮❖❉❖ ❉❊ ❯▼ P✃◆❉❯▲❖ ❙■▼P▲❊❙
✶✳✹ ❆♣❧✐❝❛çã♦ ❞❡ ❉✐❢❡r❡♥❝✐❛✐s ♥❛ ❋ís✐❝❛ ✲ P❡rí♦❞♦ ❞❡
✉♠ Pê♥❞✉❧♦ ❙✐♠♣❧❡s
❯♠❛ ✐♠♣♦rt❛♥t❡ ❛♣❧✐❝❛çã♦ ❞❡ ❞✐❢❡r❡♥❝✐❛✐s ♣♦❞❡ s❡r ❡♥❝♦♥tr❛❞❛ ♥❛ ❋ís✐❝❛✳ ❯♠ ❢ís✐❝♦ ❛♦ ❛♥❛❧✐s❛r ❛s ❝♦♥s❡q✉ê♥❝✐❛s ❞❡ ✉♠❛ ❡q✉❛çã♦✱ ♠✉✐t❛s ✈❡③❡s ♥❡❝❡ss✐t❛ r❡❛✲ ❧✐③❛r s✐♠♣❧✐✜❝❛çõ❡s ♥❛s ❡q✉❛çõ❡s ♠❛t❡♠át✐❝❛s q✉❡ r❡♣r❡s❡♥t❛♠ ♦s ❢❡♥ô♠❡♥♦s ❢ís✐❝♦s✳ ❊♠ ❛❧❣✉♥s ❝❛s♦s✱ ❛♣❧✐❝❛✲s❡ ✉♠❛ ❛♣r♦①✐♠❛çã♦ ❝❤❛♠❛❞❛ ❞❡ ❛♣r♦①✐♠❛çã♦ ❧✐♥❡❛r✳
❯s✉❛❧♠❡♥t❡ ♦s ♣r♦❜❧❡♠❛s ❡♥✈♦❧✈❡♥❞♦ ✉♠ ♣ê♥❞✉❧♦ s✐♠♣❧❡s sã♦ ❛♥❛❧✐s❛❞♦s ❝♦♠♦ s❡♥❞♦ ✉♠ ♦s❝✐❧❛❞♦r ❤❛r♠ô♥✐❝♦ s✐♠♣❧❡s✱ ♦s q✉❛✐s ❣❡r❛♠ ✉♠ ♠♦❞❡❧♦ ♠❛t❡♠át✐❝♦ ♣❛r❛ s✐st❡♠❛s r❡❧❛❝✐♦♥❛❞♦s ❛♦ ♠♦✈✐♠❡♥t♦ ❞❡ ✉♠❛ ♣❛rtí❝✉❧❛ ❡①♣♦st❛ ❛ ✉♠❛ ❢♦rç❛ ❞❡ ❛tr❛çã♦ ❝♦♠ ♠❛❣♥✐t✉❞❡ ♣r♦♣♦r❝✐♦♥❛❧ ❛ ❞✐stâ♥❝✐❛ ❞❡st❛ ♣❛rtí❝✉❧❛ ❡♠ r❡❧❛çã♦ à ♦r✐❣❡♠ ❞♦ s✐st❡♠❛✳ ❉❡ss❛ ❢♦r♠❛ ♦ ♠♦✈✐♠❡♥t♦ ❞❡ ✉♠ ♣ê♥❞✉❧♦ s✐♠♣❧❡s ♣♦❞❡ s❡r ❞❡s❝r✐t♦ ♣♦r ✉♠❛ ❡q✉❛çã♦✱ ❝❤❛♠❛❞❛ ❡q✉❛çã♦ ❞✐❢❡r❡♥❝✐❛❧ ♦r❞✐♥ár✐❛✱
d2
θ dt2 +
g
lsen(θ) = 0, ✭✶✳✹✳✶✮
♦♥❞❡gé ❛ ❛❝❡❧❡r❛çã♦ ❞❛ ❣r❛✈✐❞❛❞❡ ❡l♦ ❝♦♠♣r✐♠❡♥t♦ ❞♦ ♣ê♥❞✉❧♦✳ P❛r❛ ✈❛❧♦r❡s ♠✉✐t♦
♣❡q✉❡♥♦s ❞♦ â♥❣✉❧♦ θ✱ ✉t✐❧✐③❛✲s❡ ❛ ❛♣r♦①✐♠❛çã♦ ❧✐♥❡❛r sen(θ) ≈ θ ❡ r❡❡s❝r❡✈❡✲s❡ ❛
❡q✉❛çã♦ ✭✶✳✹✳✶✮ ❝♦♠♦✱
d2
θ dt2 +
g lθ= 0.
❊st❛ ❡q✉❛çã♦ ✐♥❞✐❝❛ q✉❡✱ ❞❡♥tr♦ ❞❛ ❛♣r♦①✐♠❛çã♦ ❞❡ â♥❣✉❧♦s ♣❡q✉❡♥♦s✱ ♦ ♠♦✈✐♠❡♥t♦ ❞♦ ♣ê♥❞✉❧♦ s✐♠♣❧❡s é ❤❛r♠ô♥✐❝♦ s✐♠♣❧❡s✱ ❡ ♦ ♣❡rí♦❞♦ ❞❡ ♦s❝✐❧❛çã♦ ❞♦ ♣ê♥❞✉❧♦ é ❝❛❧❝✉❧❛❞♦ ❝♦♠♦✱
T = 2π
s
l g.
❊ss❡ ❢❛t♦ ♣♦❞❡ ♦❜s❡r✈❛❞♦ ♥❛ ❋✐❣✉r❛ ✶✳✹ ♦♥❞❡ s❡ ❛♣r❡s❡♥t❛♠ ♦s ❣rá✜❝♦s ❞❡ x ❡ sen(x) ♥❛s ♣r♦①✐♠✐❞❛❞❡s ❞❛ ♦r✐❣❡♠✳ ◆♦t❡ q✉❡ ❛ ❢✉♥çã♦ sen(x) ❡stá ♠✉✐t♦
♣ró①✐♠❛ ❞❛ ❢✉♥çã♦x q✉❛♥❞♦xé s✉✜❝✐❡♥t❡♠❡♥t❡ ♣❡q✉❡♥♦✱ ♦✉ s❡❥❛✱ ♣ró①✐♠♦ ❞❡ ③❡r♦✳
✶✳✺ ❆♣❧✐❝❛çã♦ ❞❡ ❉✐❢❡r❡♥❝✐❛✐s ✲ ❈á❧❝✉❧♦ ❞❡ ❊rr♦s
P♦❞❡✲s❡ ❡st✐♠❛r ♦ ✈❛❧♦r ❞♦ ❡rr♦ ♣r♦♣❛❣❛❞♦ ✲ ❡rr♦ q✉❡ s❡ ❝♦♠❡t❡ q✉❛♥❞♦ s❡ ✉s❛ ✉♠❛ ❡st✐♠❛t✐✈❛ ♣❛r❛ ♦ ❛r❣✉♠❡♥t♦ ❞❛ ❢✉♥çã♦✳
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✶✳✺✳ ❆P▲■❈❆➬➹❖ ❉❊ ❉■❋❊❘❊◆❈■❆■❙ ✲ ❈➪▲❈❯▲❖ ❉❊ ❊❘❘❖❙
❋✐❣✉r❛ ✶✳✹✿ ●rá✜❝♦s ❞❛ ❢✉♥çã♦ s❡♥♦ ❡ ❞❛ ❢✉♥çã♦ ✐❞❡♥t✐❞❛❞❡
✶✳✺✳✶
E
M ax✲ ❊rr♦ ▼á①✐♠♦
❖ EM ax = dy é ❝♦♥❤❡❝✐❞♦ ❝♦♠♦ ❡rr♦ ♠á①✐♠♦✱ ❡rr♦ ♣r♦♣❛❣❛❞♦ ♦✉ ❡rr♦
❛♣r♦①✐♠❛❞♦✳ P♦❞❡ t❛♠❜é♠ s❡r ❞✐t♦ ✈❛❧♦r ❛♣r♦①✐♠❛❞♦✳ ◆♦t❡ q✉❡ EM ax ♣♦ss✉✐ ✉♥✐✲
❞❛❞❡ ❞❡ ♠❡❞✐❞❛✳
✶✳✺✳✷
E
Rel✲ ❊rr♦ ❘❡❧❛t✐✈♦
❖ ERel =
dy
y é ❝♦♥❤❡❝✐❞♦ ❝♦♠♦ ❡rr♦ r❡❧❛t✐✈♦ ❡ ♥ã♦ ♣♦ss✉✐ ✉♥✐❞❛❞❡ ❞❡
♠❡❞✐❞❛✳
✶✳✺✳✸
E
P c✲ ❊rr♦ P❡r❝❡♥t✉❛❧
❖ EP c = 100
dy
y é ❝♦♥❤❡❝✐❞♦ ❝♦♠♦ ❡rr♦ ♣❡r❝❡♥t✉❛❧ ❡ é ❡①♣r❡ss♦ ❝♦♠♦
✉♠❛ ♣♦r❝❡♥t❛❣❡♠✳
❊①❡♠♣❧♦ ✶✳✺✳✶✳ ▼❡❞✐✉✲s❡ ♦ ❞✐â♠❡tr♦ ❞❡ ✉♠ ❝ír❝✉❧♦ ❡ s❡ ❛❝❤♦✉ ✺✱✷ ♣♦❧❡❣❛❞❛s✱ ❝♦♠
✉♠ ❡rr♦ ♠á①✐♠♦ ❞❡ ✵✱✵✺ ♣♦❧❡❣❛❞❛s✳ ❉❡t❡r♠✐♥❡ ♦ ♠á①✐♠♦ ❡rr♦ ❛♣r♦①✐♠❛❞♦ ❞❛ ár❡❛ q✉❛♥❞♦ ❝❛❧❝✉❧❛❞❛ ♣❡❧❛ ❢ór♠✉❧❛✿
A= πD
2
4 .
❉❡t❡r♠✐♥❡ t❛♠❜é♠ ♦s ❡rr♦s r❡❧❛t✐✈♦s ❡ ♣❡r❝❡♥t✉❛❧✳ ❙♦❧✉çã♦✿
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✶✳✺✳ ❆P▲■❈❆➬➹❖ ❉❊ ❉■❋❊❘❊◆❈■❆■❙ ✲ ❈➪▲❈❯▲❖ ❉❊ ❊❘❘❖❙
❖ ✈❛❧♦r ❡①❛t♦ ❞❛ ár❡❛ A = πD
2
4 ♣❛r❛ D = 5,2 ♣♦❧❡❣❛❞❛s é A = 21,23
♣♦❧2 ✭♣♦❧❡❣❛❞❛s2✮✳
❆ ❞❡r✐✈❛❞❛ ❞❡ A ❡♠ r❡❧❛çã♦ ❛ D é
dA
dD =
π
2D.
❆ss✐♠✱ s✉❛ ❞✐❢❡r❡♥❝✐❛❧ dA é✿
dA = π
4 ·2D·dD = π
2 ·5,2·0,05 = 0,41♣♦❧2
.
❖ ❡rr♦ r❡❧❛t✐✈♦ é ❝❛❧❝✉❧❛❞♦ ♣♦r✿
dA
A = 0,0193.
❊ ♦ ❡rr♦ ♣❡r❝❡♥t✉❛❧ é ❝❛❧❝✉❧❛❞♦ ♣♦r✿
EP c = 100ERel
EP c = 1,93%.
❊①❡♠♣❧♦ ✶✳✺✳✷✳ ❆ ♠❡❞✐❞❛ ❞♦ r❛✐♦ ❞❡ ✉♠❛ ❡s❢❡r❛ é 0,7 ❝♠✳ ❙❡ ❡st❛ ♠❡❞✐❞❛ t✐✈❡r
✉♠❛ ♠❛r❣❡♠ ❞❡ ❡rr♦ ❞❡ 0,01❝♠✱ ❡st✐♠❡ ♦ ❡rr♦ ♣r♦♣❛❣❛❞♦ ❛♦ ✈♦❧✉♠❡ V ❞❛ ❡s❢❡r❛✳
❈❛❧❝✉❧❡ ♦ ❡rr♦ r❡❧❛t✐✈♦✳ ❙♦❧✉çã♦✿
❖ ✈♦❧✉♠❡ ❞❛ ❡s❢❡r❛ é ❞❛❞♦ ♣♦r
V = 4π 3 R
3
.
❆ ❡st✐♠❛t✐✈❛ ❞♦ r❛✐♦ ❞❛ ❡s❢❡r❛ é R= 0,7 ❡ ♦ ❡rr♦ ♠á①✐♠♦ ❞❛ ❡st✐♠❛t✐✈❛
é ∆R=dR= 0,01✳
❆ ❞✐❢❡r❡♥❝✐❛❧ ❞♦ ✈♦❧✉♠❡ ❞❛ ❡s❢❡r❛ é dV = 4πR2
dR✳ ◆❡st❡ ❡①❡♠♣❧♦✱ dV = 4π(0,7)2
(0,01) ≈0,06158❝♠3✳
❖ ❡rr♦ r❡❧❛t✐✈♦ é ❞❛❞♦ ♣♦r✿