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Corrections to the paper “Sharp estimates of the growth of the Poisson-Stieltjes integral in the polydisc” by I.E.Chyzhykov, O.A.Zolota

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Математичнi Студiї. Т.37, №2 Matematychni Studii. V.37, No.2

УДК 517.55

I. E. Chyzhykov, O. A. Zolota

Corrections to the paper “Sharp estimates of the growth of the Poisson-Stieltjes integral in the polydisc” by I.E.Chyzhykov, O.A.Zolota

The proof of the sufficiency of the theorem in [1] contains a gap, because the estimate of the Poisson kernel on the set Qk =Ek\Ek−1 (p.194) does not hold. The authors do not

know whether the sufficiency statement is true in the general case, but here we give the proof under the stronger assumption 0< βj <2, j ∈ {1, . . . , n} instead of β11 +· · ·+ β1n > 12 as it

was stated in [1].

Theorem. Let µ be a finite Borel measure on Tn, n N, 0< β

j <2, 1 ≤ j ≤n. In order

that

Z

Tn

P(z, w)dµ(w) ≤Cδ

1−1

β∗, 0< δ <1, |zj|= 1−δ

1

βj, (1)

hold for some positive constant C, it is sufficient, and for nonnegative µit is necessary that µ∈H(β1,...,βn).

Proof. Sufficiency. For fixed δ ∈(0,1) we set rj = 1−δ

1

βj, and let z

j = rjeiϕj, 1≤ j ≤ n.

For1≤j ≤n we denote

Ek=

n

eiθ1

, . . . , eiθn:|θ

j−ϕj| ≤ 2k·δ

βj1

,1≤j ≤no, 0≤k≤Nj,

where Nj =

h

log2πβj δ

i

+ 1, and

Rm1...mn =

(

eiθ1, . . . , eiθnTn : (2mj−1δ) 1 βj ≤ |θ

j−ϕj| ≤(2mjδ)

1

βj, if m

j >0,

|θj −ϕj| ≤δ

1

βj , if m

j = 0,

)

.

Then Tn =

N1

S

m1=0 . . .

Nn

S

mn=0

Rm1...mn. As in [2] (proof of Theorem 3.1) we have for fixed k

that:

Z

Rm1...mn

P(z, w)dµ(w)

≤ |µ|(Rm1...mn)·

n

Y

j=1

P(|z|,w),˜

where z ∈Un, w˜ = ( ˜w

1, . . . ,w˜n), w˜j =ei

˜

θj, θ˜

j = 2k−1·δ

1

βj ,1j n. The following estimates are known ([2])

P0 reiϕ, eiθ

≤ π

2

(ϕ−θ)2 (1−r), P0 re

, e

≤ 2

1−r. (2)

2010Mathematics Subject Classification:31B05, 31B10, 32A22, 32A25, 32A26, 32A35.

c

(2)

224

Applying the first estimate, we get

P0(|zj|,w˜j)≤

π2 ˜

θ2j (1−rj) =

π2

(2k−1·δ)

2 βj

(1−rj), k ≥1.

Using the second inequality in (2), we obtain

Z

R0...0

P(z, w)dµ(w)

≤ |µ|(R0...0)·

2n

(1−r1)·. . .·(1−rn)

.

Using the definition of the class H(β1,...,βn) we have that |µ|(R

0...0) ≤Cδ. The equalities

1−rj =δ

1

βj, 1j n imply

Z

R0...0

P(z, w)dµ(w) ≤Cδ

1−1 β1+...+

1 βn

.

Then we estimate the integral over the setsRm1...mn. Since,Rm1...mn ⊂Emax{m1,...,mn}, we get that |µ|(Rm1...mn)≤C·2

m1+...+mnδ.

Therefore, for N = maxNj, 1≤j ≤n

N

X

m1=1 . . .

N

X

mn=1

Z

Rm1...mn

P(z, w)dµ(w) ≤

N

X

m1=1 . . .

N

X

mn=1

|µ|(Rm1...mn)·

n

Y

j=1

π2(1−rj)

(2mj−1δ) 2 βj

≤C

N

X

m1=1 . . .

N

X

mn=1 2m1

·. . .·2mn·δ·

n

Y

j=1

δ 1 βj

2 2mj

βj ·δ 2 βj

≤Cδ1−

1 β1+...+

1 βn

N

X

m1=1

21− 2 β1

m1 . . .

N

X

mn=1

21−βn2

mn

< Cδ1−β1∗.

REFERENCES

1. Chyzhykov I.E., Zolota O.A. Sharp estimates of the growth of the Poisson-Stieltjes integral in the poly-disc// Mat. Stud. – 2010. – V.34, №2. – P. 193–196.

2. Rudin W. Function theory in polydiscs. – New York-Amsterdam: Math. Lecture Note Series, 1969. – 162p.

Lviv Ivan Franko National University [email protected]

Drohobych Ivan Franko State Pedagogical University [email protected]

Referências

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