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Métodos Quantitativos

Aplicados à Contabilidade

Doutorado em Ciências Contábeis 2019

1 Prof. Otávio R. Medeiros

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The Basics of Matrix

Algebra

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3

Definitions

Matrix: rectangular array of real numbers with m rows and

n columns.

where are matrix elements.

•   11 12 1 21 22 2 1 2

...

...

A

...

n n m m mn

a

a

a

a

a

a

a

a

a

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4

Definitions

Size or dimension of a matrix: number of rows x columns:

m x n

If a matrix has only one row = row vector, with dimension 1 x m

If a matrix has only one column = column vector, with dimension n x 1

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5

Definitions

Sum of elements of leading diagonal = trace.

Diagonal matrix: square matrix with all elements off the leading diagonal equal to zero.

Identity matrix: diagonal matrix with all elements in the leading diagonal equal to one.

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6

Definitions

Rank of a matrix: maximum number of linearly

independent rows or columns contained in the matrix,

e.g.:

3 4

2

7 9

3 6

1

2 4

rank

rank

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The Rank of a Matrix

You can think of an m x n matrix as a set of m row vectors, each

having n elements; or you can think of it as a set of n column vectors, each having m elements.

The rank of a matrix is defined as (a) the maximum number of linearly independent column vectors in the matrix or (b) the maximum number of linearly independent row vectors in the matrix. Both definitions are equivalent.

For an m x n matrix,

If m is less than n, then the maximum rank of the matrix is m.If m is greater than n, then the maximum rank of the matrix is n.The rank of a matrix would be zero only if the matrix had no elements.

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Full Rank Matrices

When all of the vectors in a matrix are linearly

independent, the matrix is said to be full rank. Consider the matrices A and B below.

Notice that row 2 of matrix A is a scalar multiple of row 1; that is, row 2 is equal to twice row 1.

Therefore, rows 1 and 2 are linearly dependent. Matrix A has only one linearly independent row, so its rank is 1. Hence, matrix A is not full rank.

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Full Rank Matrices

Now, look at matrix B. All of its rows are linearly

independent, so the rank of matrix B is 3. Matrix B is full rank.

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Example

Consider the matrix X, shown below.

What is its rank?(A) 0 (B) 1 (C) 2 (D) 3 (E) 4 •  

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Example

Solution

The correct answer is (C). Since the matrix has more than zero elements, its rank must be greater than zero. And

since it has fewer rows than columns, its maximum rank is equal to the maximum number of linearly independent

rows. And because neither row is linearly dependent on the other row, the matrix has 2 linearly independent rows; so its rank is 2.

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Example

Consider the matrix Y, shown below.

What is its rank?(A) 0 (B) 1 (C) 2 (D) 3 (E) 4 •  

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Solution

The correct answer is (C). Since the matrix has more than zero elements, its rank must be greater than zero. And

since it has fewer columns than rows, its maximum rank is equal to the maximum number of linearly independent

columns.

Columns 1 and 2 are independent, because neither can be derived as a scalar multiple of the other. However, column 3 is linearly dependent on columns 1 and 2, because

column 3 is equal to column 1 plus column 2. That leaves the matrix with a maximum of two linearly independent columns; that is., column 1 and column 2. So the matrix rank is 2.

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14

Trace of a matrix:

If A is m x n and B is n x m, then AB and BA are

square matrices and tr(AB) = tr(BA)

Definitions

1

(A)

( A)

( (A))

n ii i

tr

a

tr c

c tr

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15

Matrix Operations

Equality between matrices:

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16

Matrix Operations

Addition of matrices: A+B= C iff A and B have the same size and aij + bij = cij  i, j.

2 4

1 2

1 6

3 5

4

1

7 6

 

 

 

 

 

 

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17

Matrix operations

Multiplication of a scalar k by a matrix A:

k.A = k.[aij], i.e. every element of the matrix is multiplied by the scalar.

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Laws of matrix addition and scalar

multiplication

Let A, B, C be matrices of the same size m x n , 0 the

zero matrix, and c and d scalars. Then:

1. Closure law: A+B is an m x n matrix 2. Associative law: (A+B)+C = A+(B+C) 3. Cummulative law: A+B = B+A

4. Identity law: A+0 = A 5. Inverse law: A+(-A) = 0

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Laws of matrix addition and scalar

multiplication (cont.)

6. Closure law: cA is an m x n matrix 7. Associative law: c(dA) = (cd)A 8. Distributive law: (c+d)A = cA+dA 9. Distributive law: c(A+B) = cA+cB 10. Monoidal law: 1A = A

11. Identity law: AI = A and IB = B

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20

Matrix Multiplication

DEFINITION. Let A = [aij ] be an m x p matrix and B = [bij ] be a

p x n matrix. Then the product of the matrices A and B, denoted

by A.B (or simply AB), is the m x n matrix whose (i, j)th entry, for 1 i  m and 1  j  n, is the entry of the product of the ith row of A and the jth column of B; more specifically, the (i, j)th entry of AB is

1 1 2 2

...

i j i j ip pj

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21

Matrix Multiplication

Example:

In general,

A.B ≠ B.A

2 4

1 2

2 ( 1) 4 4 2 2 4 1

14 8

3 5

4

1

3 ( 1) 5 4 3 2 5 1

17 11

   

  

 

 

 

 

 

   

  

 

 

 

 

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22

Matrix Multiplication

Multiplication of matrices is only possible if they are

conformable, i.e.

A (m x n) x B (n x p) = C (m x p)

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23

Transpose of a matrix

DEFINITION: Let A = [aij] be an m x n matrix. Then the transpose of A is the n x m matrix A’ (or AT) obtained by interchanging the rows and columns of A, so that the (i,

j)th entry of A’ is aji : 11 12 1 11 21 1 21 22 2 12 22 2 1 2 1 2 ... ... ... ... A ; A ' ... ... n m n m m m mn n n mn a a a a a a a a a a a a a a a a a a                                  

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24

Laws of Matrix Transpose

Let A and B be matrices of the appropriate sizes so that the following operations make sense, and c a scalar. Then

1. (A+B)’ = A’+B’ 2. (AB)’ = B’A’ 3. (cA)’ = cA’ 4. (A’)’ = A

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Some Matrices with Simple Structure

DEFINITION: Let A = [aij ] be a square n x n matrix. Then A is:

Scalar if aij = 0 and aii = ajj  i  j. (Equivalently: A = cIn for some scalar c, which explains the term “scalar.”)

Diagonal if aij = 0  i  j (Equivalently: the off-diagonal entries of A are 0).

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26

Square matrices

Diagonal matrix: 1 2

0 ... 0

0

... 0

0

0 ...

n

 

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27

Square matrices:

Scalar matrix = diagonal matrix, when

1 = 2 = ... =n .

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28

Square matrices

Identity matrix I:

Note: A.I = I.A = A, where A has the same size as I.

1 0 0 0

0 1 0 0

I

0 0 1 0

0 0 0 1

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Matrix Inverses

DEFINITION 2.5.1. Let A be a square matrix. Then a

(two-sided) inverse for A is a square matrix B of the same size as A such that AB = I = BA. If such a B exists, then the matrix A is said to be invertible.

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30

Determinants

DEFINITION: The determinant of a square matrix n x n matrix A = [aij ] is the scalar quantity det A (or |A|) defined recursively as follows: if n = 1 then det A = a11; otherwise, we suppose that determinants are defined for all square

matrices of size less than n and specified as:

This method is known as the Laplace expansion (d’après Pierre-Simon

Laplace*) or the cofactor expansion. It can be use recursively for matrices of

any size. * https://en.wikipedia.org/wiki/Pierre-Simon_Laplace 1 1 1 1 11 11 21 21 1 1 1 det ( 1) ( ) ( ) ( ) ... ( 1) ( )

where M ( ) is the determinant of the ( -1) ( -1) matrix obtained from A by deleting the ith row and jth column of A.

n k n k k n n k ij A a M A a M A a M A a M A A n n           

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31

Determinant of 2

rd

order: the Laplace expansion method

Example: matrix 2 x 2:

3 1

3 2 2 1 6 2 4

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32

Determinant of 3

rd

order: the Laplace expansion method

Example: 3 x 3 matrix

Consider the matrix

• For the Laplace expansion, we can start by choosing any row or column. Assume we chose the 1st row:

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Determinant of 3

rd

order: Sarrus’*

rule

Sarrus’ rule can be used for 3 x 3 matrices only.

See Harjrizaj (2009). * D’ après Pierre Frédéric Sarrus:

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34

Determinant of 3

rd

order: Sarrus’

rule

Example: matrix 3 x 3

2 3 2

2 3 2 2 3

1 1 2

1 1 2 1 1

3 2 2

3 2 2 3 2

2 1 2 3 2 3 2 1 2 2 1 3 2 2 2 3 1 2

4 18 4 6 8 6 6

 

                 

      

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35

Inverse matrix

The inverse of a square matrix A, named A-1, is the matrix which pre or post multiplied by A gives the identity matrix.

B = A-1 if and only if BA = AB = I

• Matrix A has an inverse if and only if det A  0 (i.e. A is non singular).

(A.B)-1 = B-1.A-1

(A-1)’=(A’)-1  if A é symmetrical and non singular, then A-1 is symmetrical.

If det A ≠ 0 and A is a square matrix of size n, then A has rank

n, i.e. A is a full rank square matrix.

If a square matrix of size n has rank < n, then its determinant is zero and so the matrix is not invertible, i.e. the matrix is

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36

Steps for finding an inverse matrix

1) Compute the determinant

2) Find the minors of the elements aij, which are the determinants of the submatrix obtained after exclusion of the i-th row and j-th column.

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37

Steps for finding an inverse matrix

Determinant: (Laplace expansion) take any row or column and get the determinant by multiplying the products of each element of row or column by its respective cofactor. • Cofactor matrix: matrix where each element is substituted

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Steps for finding an inverse matrix

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39

Example

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40

Example

3 x 3 matrix : 1 1 2 1 2 1 1 2 2 3 2 3 2 2 3 2 2 4 1 3 2 2 2 2 3

1 1 2 det 6 cofactor matrix 2 2 5 2 2 3 2 3 2 3 2 2 4 2 1 3 2 2 2 2 3 1 2 1 2 1 1 2 2 4 6 6 6 2 2 4 4 Adj 4 2 2 6 1 5 1                                                             A A A A 1 2 2 3 3 3 2 2 2 1 1 6 6 3 3 3 1 5 1 1 5 1 6 6 6 6 6 6                                    

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Properties of Inverse Matrices

41 1

(

)

'

'

-1 -1 -1 -1 -1 -1 -1 -1

AA = A A = I

(A ) = A

AB

B A

(A ) = (A )

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42

Matrix differentiation (1)

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Example (1)

•  

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44 Matrix differentiation (2)

Let 

� be a column vector �=

(

1

2

)

 and 

� a column vector �=

(

1

2

)

. Then we can write:

�´�=�

1

1

+

2

2

+

⋯+�

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45 Example (2)

Let 

� be a column vector �=

(

2

3

4

−1

)

 and 

� a column vector �=

(

1

2

)

. Then we can write:

�´�=2�

1

+3

2

+4

3

4

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46 Matrix differentiation (3) 11 12 1 1 12 22 2 2 1 2 2 2 11 1 12 1 2 13 1 3 1 1 22 2 23 2 3 2 2

Let A be a symmetric matrix and x a column vector . Hence: ´ 2 2 2 2 2 n n n n nn n n n n n a a a x a a a x a a a x a x a x x a x x a x x a x a x x a x x                                     A x x Ax            2 1 11 1 12 2 1 12 1 22 2 2 2 1 1 2 2

The derivative of ´ w.r.t. vector will be: ( ´ ) 2( ) ( ´ ) 2( ) ( ) 2 2( ) ( ´ ) nn n n n n n n n nn n n a x x a x a x a x a x a x a x x a x a x a x x                                  x Ax x x Ax x Ax x´Ax x x Ax      11 12 1 1 21 22 2 2 1 2 2 ´ n n n n nn n a a a x a a a x a a a x                       Ax 2x A        

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Example (3)

•  

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REFERENCES

Harjrizaj, Dardan. New Method to Compute the Determinant of a 3x3 Matrix. International Journal of Algebra, Vol. 3, 2009, no. 5, 211 – 219. Available in:

http://m-hikari.com/ija/ija-password-2009/ija-password5-8-2009/hajriza jIJA5-8-2009.pdf

Theory and exercises about matrices can be found in :

Shores, T.S. (2000) Applied linear algebra and matrix analysis. McGraw Hill College. With exercises!

Brooks, C. Introductory Econometric for Finance, 3rd ed.

Cambridge University Press, 2014. Exercises chapter 2!

Heij et al. Econometric methods with applications in business and economics, Oxford UP, 2004, Appendix A: Matrix Methods (with exercises!).

Kutner et al. Applied linear statistical models, 5th Ed. : Chapter 5 -

Matrix Approach to Simple Linear Regression Analysis (with

Referências

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