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An explicit high order method for fractional advection diffusion equations

Ercília Sousa

PII: S0021-9991(14)00604-4 DOI: 10.1016/j.jcp.2014.08.036 Reference: YJCPH 5446

To appear in: Journal of Computational Physics Received date: 27 March 2014

Revised date: 29 July 2014 Accepted date: 18 August 2014

Please cite this article in press as: E. Sousa, An explicit high order method for fractional advection diffusion equations, J. Comput. Phys. (2014),

http://dx.doi.org/10.1016/j.jcp.2014.08.036

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An explicit high order method for fractional advection di ff usion equations

Erc´ılia Sousa

CMUC, Department of Mathematics, Universityof Coimbra, 3001-501 Coimbra,Portugal

Abstract

We propose a high order explicit finite difference method for fractional advection diffusion equations. These equations can be obtained from the standard advection diffusion equations by replacing the second order spatial derivative by a fractional operator of order αwith 1 < α ≤ 2. This operator is defined by a combination of the left and right Riemann–Liouville fractional derivatives. We study the convergence of the numerical method through consistency and stability. The order of convergence varies between two and three and for advection dominated flows is close to three. Although the method is conditionally stable, the restrictions allow wide stability regions. The analysis is confirmed by numerical examples.

Keywords: higher order methods, fractional differential equations, finite differences, advection diffusion equations

1. Fractional advection diusion equation

Fractional derivatives have been used to model anomalous dispersion or diffusion and recently the fractional advection diffusion equation has been presented as a more suitable model for many problems that appear in different fields, such as engineering, physics, chemistry and hydrology. The fractional advection diffusion equation involves a parameter 1< α <2 representingthe order of the fractional operator in space and whenα=2 we obtain the classical advection diffusion equation. Therefore in experiments, an additional parameterαneeds to be adjusted, that helps to characterize the flow.

Some of the works that present experimental results with parameter estimation involving fractional advection diffusion (or dispersion) problems are for instance [5, 7, 8, 11, 33]. In [7] the most frequently occurringvalue ofαto adjust the experimental results varies in the range of 1.4 to 2.0 as in [8]. In [11] the average estimate of the parameter αis also around 1.7 and 1.8. However, there are some estimates in [5, 33], that concerns small parameters ofα, less than 1.5.

Similar problems to the one presented here have also been studied from different perspectives and not only from the numerical point of view. The study of analytical approaches, namely discussions about the well-posedness of such problems, that is, on the existence,uniqueness and regularity of the solutions are also a very active research field [2, 6, 15].

Regardingfinite difference methods for fractional advection diffusion problems, in the last years many approaches have been appearing, mostly with convergence of first and second order, some for only pure diffusive problems [4, 19, 20, 29, 34] and others for the advection-diffusion models [3, 12, 13, 14, 23, 26, 28]. Many of the second order approaches rely on implicit methods which are inadequate for advection dominated flows. However, advection often dominates the evolution of transport flows.

Our purpose is to introduce a numerical method that is also suitable for primarily advective flows, that is, with small diffusion. We derive a numerical method which is explicit and it has the particularity that forα=2 matches the numerical method introduced in [16] and called QUICKEST. Although this method was introducedalongtime ago it has been very popularuntil today, since it has thegoal of providingan accurate solution without strongoscillations presented in some higher order methods. It has also beenshownto be more efficient than other schemes for highly

Emailaddress:[email protected](Erc´ılia Sousa)

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advective flows, since it makes a reasonable compromise between improved performance and computational cost [1, 9, 10, 25, 31, 32]. The numerical method we proposekeepsthese properties but now for moregeneral models, described by the fractional operator.

The fractional advection diffusion equation can be expressed asfollows

u

∂t +Vu

∂x =D 1

2+β 2

αu

∂xα+D 1

2−β 2

αu

∂(−x)α+S, (1)

whereurepresents a concentration,Vis the velocity,xis the spatial coordinate,tis the time,Dis the diffusion (or dispersion) coefficient,αis the order of the fractional differentiation with 1< α≤2 andS is the source or sink term.

The parameterβis a skewness parameter with−1≤β≤1.

We define the fractional operator

αβu= 1

2(1+β)∂αu

xα +1

2(1−β) ∂αu

∂(−x)α. (2)

The equation (1) can be rewritten in the simpler form

u

t +Vu

x=D∇αβu+S. (3)

We consider the problem defined inx∈IR with an initial condition u(x,0)= f(x), x∈IR, andboundary conditions

x→−∞lim u(x,t)=0 and lim

x→∞u(x,t)=0.

In the analysis of the numerical method that follows, we assume our problem has aunique and sufficiently smooth solution.

Remark 1. The type of problems we are studyingincludesthe cases for which the solutionuis non-zero in a bounded interval [a,b], for allt, that can be seen as beingzero otherwise, and by assumingthe boundary conditions

u(a,t)=0 and u(b,t)=0.

For the particular cases,β=1 andβ=−1, we can assume respectively the moregeneral boundary conditions u(a,t)=0 and u(b,t)=gb(t)

and

u(a,t)=ga(t) and u(b,t)=0, wherega(t) andgb(t) aregiven functions.

The fractional derivatives can be represented by the Riemann-Liouville formula. The left and right Riemann- Liouville fractional derivatives of orderα, forx∈[a,b],−∞ ≤a<b≤ ∞, are respectively defined by

αu

xα(x,t)= 1 Γ(n−α)

n

xn x

a

u(ξ,t)(x−ξ)n−α−1dξ, (n−1< α <n) (4)

αu

∂(−x)α(x,t)= (−1)n Γ(n−α)

n

xn b

x

u(ξ,t)(ξx)n−α−1dξ, (n−1< α <n) (5) whereΓ(·) is the Gamma function andn=[α]+1, with [α] denotingthe integer part ofα.

2

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Remark 2. Forn−1 < α < n, sufficient conditions for the existence of the Riemann-Liouville derivatives is thatu(·,t)AC(n)([a,b]) [22]. This space represents the space of functionsufor which the space derivatives are continuousuntil ordern−1 and the derivative of ordern−1 is absolutely continuous.

The application of fractional calculus to scientific and engineeringproblems presents difficulties that arise from the basic calculus properties, such as, the composition property with derivatives. To preserve composition the function and some of its derivatives should be identically zero at the initial point. For the Riemann-Liouville derivatives, we have the followingproperties, that can be found, for instance, in [17, 21, 22].

Proposition 1. Letα >0, if the left Riemann-Liouville derivative (4) of orderαandα+mexist, form=1,2, . . ., we have

m

∂xmαu

∂xα(x,t)

= ∂α+mu

∂xα+m(x,t), (6)

α

∂xαmu

∂xm(x,t)

= ∂α+mu

∂xα+m(x,t)

m−1

j=0

ju

∂xj(a,t) (x−a)j−α−m

Γ(1+ j−α−m). (7) Proposition 2. Letα >0, if the right Riemann-Liouville derivative (5) of orderαandα+mexist, form=1,2, . . ., wehave

m

xmαu

∂(−x)α(x,t)

= (−1)mα+mu

∂(−x)α+m(x,t), (8)

α

∂(−x)αmu

∂xm(x,t)

= (−1)mα+mu

∂(−x)α+m(x,t)

m1

j=0

ju

xj(b,t)(−1)j+m(b−x)j−α−m

Γ(1+j−α−m) . (9) From the previous properties, we infer that the interchange of the Riemann-Liouville differentiation operators is allowedunder certain conditions. Note that, since we are consideringhomogeneous boundary conditions, similar results toProposition 1 andProposition 2, for the real line case, becomes

∂x ∂αu

∂xα(x,t)

= ∂α

∂xα ∂u

∂x(x,t)

= ∂α+1u

∂xα+1(x,t) (10)

and

∂x ∂αu

∂(−x)α(x,t)

= ∂α

∂(−x)α ∂u

∂x(x,t)

=(−1)mα+1u

∂(−x)α+1(x,t). (11)

2. Finite dierence approximations

In this section we derive the numerical method that determines the approximate solution for the fractional ad- vection diffusion equation. We start to describe how we discretize in time toget an explicit method and then how to discretize the classical spatial derivatives. The last section discusses how we approximate the fractional operators involved.

2.1. Time discretisation

We start to derive the finite difference schemeusingTaylor expansions, that is, we expanduabout time leveln, that is,tn=nΔtand whereΔtdenotes the time step, to obtain

u(x,tn+1)−u(x,tn) = Δt∂u

∂t(x,tn)+Δt2 2

2u

t2(x,tn)+Δt3 6

3u

t3(x,tn)

+O(Δt4). (12)

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Then, from (3), we can write

2u

t2 = −V2u

∂t∂x+D

∂t ∇αβu

+∂S

∂t, (13)

2u

∂x∂t = −V2u

∂x2+D

∂x ∇αβu

+∂S

∂x, (14)

αβ ∂u

∂t

= −Vαβ ∂u

∂x

+Dαβ(∇αβu)+∇αβS. (15) Letus assume that

∂t ∇αβu

=∇αβu

∂t

.

It can be noted that this equality holds, if we assume tu(·,t)AC(2)(IR) (see Remark 2).Therefore, from (13)–(15), weget

2u

∂t2 = V22u

∂x2V D

∂x ∇αβu

VS

∂x −V D∇αβu

∂x

+D2αβ(∇αβu) +DαβS +∂S

∂t. (16)

FromProposition 1 andProposition 2 and since we assume homogeneous boundary conditions, we obtain

αβ ∂u

∂x(x,t)

= ∇α+β 1u(x,t), (17)

x

αβu(x,t)

= ∇α+1β u(x,t), (18) where

α+β 1u=1

2(1+β)∂α+1u

∂xα+1−1

2(1−β) ∂α+1u

∂(−x)α+1, (19)

and hence from (16)–(19) we obtain

2u

∂t2 =V22u

∂x2 −2V D∇α+β 1u+D2αβ(∇αβu)+D∇αβS+∂S

∂t −VS

∂x. (20)

From (20), we have

3u

∂t3 = V2

∂t ∂2u

∂x2

−2V D∂

∂t ∇α+β 1u

+D2

∂t

αβ(∇αβu)

+Dαβ ∂S

∂t

+∂2S

t2V2S

∂t∂x. (21)

Note that, from (3), we can write

t2u

∂x2

=−V∂3u

∂x3+D∇αβ2u

∂x2

+∂2S

∂x2. (22)

Henceforth, inserting(22) in (21) we obtain

3u

∂t3 = −V33u

∂x3+V2D∇αβ2u

∂x2

+V22S

∂x2 −2V D∂

tα+1β u

+D2

t

αβ(∇αβu) +Dαβ

∂S

∂t

+∂2S

∂t2V2S

∂t∂x. (23)

4

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Next, we derive the finite-difference approximations, by droppinghigher-spatial-derivative terms from (20) and(23), that is,

2u

∂t2V22u

∂x2−2V D∇α+β 1u+DαβS+∂S

∂t −V∂S

∂x, (24)

3u

∂t3 ≈ −V33u

∂x3+Dαβ ∂S

∂t

+∂2S

∂t2V2S

∂t∂x+V22S

∂x2, (25)

Inserting(3), (24) and (25) into (12)gives, u(x,tn+1) ≈ u(x,tn)+ Δt

V∂u

x+Dαβu

(x,tn)+1 2Δt2

V22u

x2 −2V D∇α+1β u

(x,tn) +1

6Δt3

−V33u

x3

(x,tn)+ ΔtS(x,tn)+Δt2 2

D∇αβS +∂S

tVS

x

(x,tn) +Δt3

6

D∇αβS

t

+∂2S

∂t2V2S

tx +V22S

∂x2

(x,tn). (26)

2.2. Spatial discretisation

To derive a finite difference scheme we suppose there are approximationsUn:={Unj}to the valuesu(xj,tn) at the mesh points

xj= jΔx, j∈ZZ and tn=nΔt,n≥0, whereΔxdenotes theuniform space step andΔttheuniform time step. Let

ν= VΔt

Δx and μα= DΔt Δxα.

The quantityνis called the Courant (or CFL) number andμαis associated with the diffusion coefficient.

Spatial discretization about agrid point jcan be accomplished by first fittinga quadratic acrossgrid pointsj−1, jand j+1, and then integratingto obtain the average value ofuwithin the jth mesh cell. This average value is determined at time levelsnandn+1, thus yieldingunandun+1. The difference (un+1un) becomes

u(x,tn+1)−u(x,tn) ≈ Unj+1Unj+ 1

24[(Unj++11−2Unj+1+Unj+11)

−(Unj+1−2Unj+Unj1)]. (27) The last two terms of (27) can be interpreted as

1

24ΔtΔx22

x2 ∂u

∂t

≈ −1

24VΔtΔx23u

x3 (28)

from (3). Hence, takingin consideration (28) weuse (27) to approximate the termu(x,tn+1)−u(x,tn) appearingin (26).

We now describe how we approximate the spatial derivatives appearing in (26) and (28) to finally obtain the numerical method.Letus define the difference operators

Δ0Unj = 1

2(Unj+1Unj−1), δ2Unj =Unj+1−2Unj+Unj−1,

δ2ΔUnj = Unj+1−3Unj+3Unj−1Unj−2. (29) A common alternativeused to avoid the shortcomings of discretizingthe spatial first derivative withupwinding differencingand central differencingis theuse of the discretization presented in [16] involved in the derivation of the QUICKEST scheme. The interpolation formula for positive velocity is

u

x≈ Δ0Unj Δx −1

8 δ2ΔUnj

Δx . (30)

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Hence, we discretize the spatial first order derivative in (26) in this manner.

We denote the fractional difference operators byδαβu(xj,tn) andδα+1β u(xj,tn) and such that, Δαβu(xj,tn)≈ δαβu(xj,tn)

Δxα Δα+1β u(xj,tn)≈δα+1β u(xj,tn) Δxα+1 . These operators will be defined in detail in the next section.

If in (26) we discretize the spatial first order derivative as (30), the second order derivative with second order difference operator and the third-order derivative with third-order difference operator, both defined in (29), and the fractional derivatives with the respective fractional difference operators, to be discussed in the next section, we have the numerical method

Un+1j = Unj−νΔ0UnjαδαβUnj+1

2δ2Unj−νμαδα+1β Unj +1

6(ν−ν32ΔUnj+ ΔtS˜nj(xj,tn), (31) where ˜Snj=S˜(xj,tn) and ˜S isgiven by

S˜ =S+Δt 2

DαβS+∂S

∂t −V∂S

∂x

+Δt2 6

Dαβ

∂S

∂t

+∂2S

∂t2V2S

∂t∂x+V22S

∂x2

.

2.3. Derivationof the fractional dierence operators

In this section we describe how to approximate the fractional operatorsΔαβuandΔα+β 1udefined by (2) and (19) respectively. These approximations have been already denoted by δαβuxα and δα+β 1uxα+1 respectively, in the previous section, to write the numerical method (31).

We begin by derivingthe approximation for the operatorΔαβu, defined by (2), (4) and (5), whichuses the approxi- mations for the left and right fractional derivatives derived in [27, 28].It consists of approximatingthe function inside the integral by a linear spline in order to obtain a second order approximation for the fractional operator.More details on this discretization can be seen in [27, 28] and they will be alsogiven in the next section duringthe discussion on the truncation error of our numerical method (31). Afterwards, we derive the approximation for the operatorΔα+β 1u.

Set

am=⎧⎪⎪⎪⎨

⎪⎪⎪⎩

(m+1)3−α−2m3−α+(m−1)3−α, m≥1

1, m=0

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qm=⎧⎪⎪⎪⎨

⎪⎪⎪⎩

am1−2am+am+1, m≥1

−2a0+a1, m=0 a0, m=−1.

(33) The approximation of the left and right fractional derivatives, defined in (4) and (5) are respectivelygiven by

δαlu(xj,t)

Δxα , δαru(xj,t) Δxα , where the discrete operators are defined by

δαlu(xj,t) = 1 Γ(4−α)

m=−1

qmu(xjm,t), (34)

δαru(xj,t) = 1 Γ(4−α)

m=−1

qmu(xj+m,t). (35)

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Hence, we define the discrete operatorδαβu, that approximatesΔαβuas δαβu(xj,t)=1

2(1+β)δαlu(xj,t)+1

2(1−β)δαru(xj,t). (36) We now turn to the operator∇α+β 1u, that is, we describe how we approximate this operator. First, note that

α+β 1u(x,t)= ∂

∂x

αβu(x,t) . Therefore an approximation to the operator∇α+β 1u(xj,t) can begiven by

δα+β 1u(xj,t) Δxα+1 = 1

Δx

⎛⎜⎜⎜⎜⎝δαβunj

Δxα −δαβunj−1 Δxα

⎞⎟⎟⎟⎟⎠.

Next, we define

δα+1l unjαlunj−δαlunj1, δα+1r unjαrunj−δαrunj1, in order to rewrite the discrete operator as

δα+β 1unj Δxα+1 = 1

Δxα+1 1

2(1+β)δα+1l unj+1

2(1−β)δα+1r unj

.

Note that the discrete operatorsδα+l 1unjandδα+r 1unjare respectively defined by δα+1l unjαlunj−δαlunj−1= 1

Γ(4−α)

⎡⎢⎢⎢⎢⎢

q−1unj+1+

m=0

(qmqm−1)unjm

⎤⎥⎥⎥⎥⎥

⎦ (37)

and

δα+r 1unjαrunj−δαrunj1=− 1 Γ(4−α)

⎡⎢⎢⎢⎢⎢

q1unj2+ m=0

(qmqm1)unj1+m

⎤⎥⎥⎥⎥⎥

⎦. (38)

Moreover, the numerical method (31), withα=2 and without the source term, is the well known QUICKEST scheme presented in [16].

3. Global error

In this section we discuss theoretically theglobal error of the numerical method (31). The method can be written in the form

Un+1j =PUnj, (39)

withPan operator defined byP =

k=−∞

ckSk, where the coefficientsck depend onνandμαand Srepresents the forward and backward shift operators, that is,SkUnj=Unj+k.

For the exact solution, and denotingu(jΔx,nΔt) byunj, we have

unj+1=Punj+ ΔtTnj, (40) whereTnj is the local truncation error.

Therefore, theglobal error defined byEnj =unjUnj isgiven by

En+1j =PEnj+ ΔtTnj. (41) Hence, aglobal bound for the error depends on the truncation error and the boundedness of the operatorP, which will be discussed in the next subsections.We begin by analyzingthe truncation error and then discuss the boundedness of the operator, which is related to the stability analysis.

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3.1. Leading terms of the truncationerror

To derive the truncation error, we consider without loss ofgenerality, the source term zero anduse techniques similar to the modified equation [30]. To obtain the results in this section, we assumeuis a function with sufficiently many continuous derivatives in time and space. Since our domain is the real line, it is enough to assume the functionu and its spatial derivatives vanish at infinity in an appropriate manner, to allow the interchange of differential operators, fractional and integer. We start to present results regardingthe leadingterms of the truncation error of the fractional difference operators.

Lemma 3. Supposeuisafunctionwithsufficiently manycontinuous spatial derivatives that vanish at infinityin an appropriatemanner. Then unj=u(xj,tn)satisfies

δαβunj

Δxα =∇αβunj+α(xj) and δα+1β unj

Δxα+1 =∇α+β 1unj+α+1(xj), (42) whereα(xj)andα+1(xj)are local truncationerrorsapproximatelygivenby

α(xj) ≈ Δx2

12 +C2Δx2

α+β 2unj+C3Δx3α+β 3unj+O(Δx4) (43) α+1(xj) ≈ −Δx

2 ∇α+β 2unj+ Δx2

6 −C2Δx2

α+β 3unj+O(Δx3), (44) for Ci,i=2,3constants.

Proof. Duringthis proof we omit the variablet, for the sake of clarity, and for an arbitrary and fixedtnwe denote u(xj) :=u(xj,tn). We derive only the truncation error to the left fractional derivative since for the right derivative it can be obtained in a similar manner. The left derivative can be written as

αu

∂xα(xj)= ∂2

∂x2I2−αu(xj), where

I2−αu(xj)= 1 Γ(2−α)

xj

−∞u(ξ)(xj−ξ)1−αdξ.

The approximation under consideration was obtained first bydoinga central approximation of the second order derivative, assumingI2−αuis sufficiently smooth. Therefore, we have

αu

∂xα(xj)= 1 Δx2

I2−αu(xj+1)−2I2−αu(xj)+I2−αu(xj1)

+a(xj), where

a(xj)=−Δx2 12

4

∂x4I2−αu(xj)+O(Δx4).

Then,I2−αu(xj) is approximated by ˜I2−αu(xj), obtained by doinga linear spline approximation ofu(ξ) (see [27] for more details). Weget

αu

∂xα(xj)= 1 Δx2

I˜2−αu(xj+1)−2 ˜I2−αu(xj)+I˜2−αu(xj1)+s(xj)

+a(xj), (45) wheres(xj) is the error associated with the spline approximation. We have

s(xj) = 1 Γ(2−α)

⎧⎪⎪⎨

⎪⎪⎩

j−1 k=−∞

xk xk1

(u(ξ)−sj−1(ξ))(xj−1−ξ)1−α

−2 j k=−∞

xk xk1

(u(ξ)−sj(ξ))(xj−ξ)1−α +

j+1 k=−∞

xk xk−1

(u(ξ)−sj+1(ξ))(xj+1−ξ)1−α⎫⎪⎪⎬

⎪⎪⎭

8

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wheresj(ξ) denotes the spline that interpolatesxk=kΔx,kj. Forxk1xxk

u(ξ)s(ξ)=−1

2u (ξ)lk,2(ξ)−1

6u (ξ)lk,3(ξ)−. . . , where

lk,r(ξ)= xk−ξ

Δx (xk−ξ−Δx)r−ξ−xk−1

Δx (xk−ξ)r. We obtain

s(xj)=− 3

r=2

1

r!r(xj)+. . . , (46)

with

r(xj) = 1 Γ(2−α)⎧⎪⎪⎨

⎪⎪⎩

j1

k=−∞

xk xk−1

lk,r(ξ)u(r)(ξ)(xj1−ξ)1−α

−2 j k=−∞

xk xk−1

lk,r(ξ)u(r)(ξ)(xj−ξ)1−αdξ +

j+1 k=−∞

xk xk1

lk,r(ξ)u(r)(ξ)(xj+1−ξ)1−α⎫⎪⎪⎬

⎪⎪⎭. By changingvariables, forr=2,3, weget

r(xj)= 1 Γ(2−α)

j k=−∞

xk

xk−1

lk,r(ξ)

u(r)(ξ+ Δx)−2u(r)(ξ)+u(r)(ξ−Δx)

(xj−ξ)1−αdξ.

Now, sincelk,r(ξ)=O(Δxr), forxk1≤ξ≤xk, and by Taylor expansions we have u(r)(ξ+ Δx)−2u(r)(ξ)+u(r)(ξ−Δx)= Δx2u(r+2)(ξ)+Δx4

12 u(r+3)(ξ)+O(Δx6), we can obtain an estimation for the errorgiven by, forr=2,3,

r(xj) ≈ CrΔxr 1 Γ(2−α)

j k=−∞

xk

xk−1

Δx2u(r+2)(ξ)(xj−ξ)1−α+. . .

= CrΔxr+2 1 Γ(2−α)

xj

−∞u(r+2)(ξ)(xj−ξ)1−α+. . .

= CrΔxr+2I2−αr+2u

∂xr+2+. . . . (47)

Note that because we are assuminguhas sufficiently many continuous derivatives and that they vanish in an appropri- ate manner at infinity, we have [21]

α+ru

∂xα+r(xj)=I2−αr+2

xr+2(xj)= ∂r+2

xr+2I2−αu(xj), r=2,3. Then

r(xj) ≈ CrΔxr+2α+ru

∂xα+r(xj)+O(Δx4+r). (48)

Therefore, from (46) and (48) weget, for the errors(xj)/Δx2appearingin (45), 1

Δx2s(xj) ≈ −1 2C2Δx4

Δx2

α+2u

xα+2(xj)−1 6C3Δx5

Δx2

α+3u

xα+3(xj)+. . .

= −1

2C2Δx2α+2u

xα+2(xj)−1

6C3Δx3α+3u

xα+3(xj)+O(Δx4).

(11)

Now letus turn to the fractional operator of orderα+1. The operator∇α+β 1uisfirstgiven by

α+1β u(xj)= 1 Δx

αβu(xj)− ∇αβu(xj1)

+b(xj), where

b(xj)=Δx 2

2

x2αβu(xj)−Δx2 6

3

x3αβu(xj)+O(Δx3). ByProposition 1 andProposition 2 andunder the lemma assumptions, we can write

b(xj)=Δx

2 ∇α+β 2u(xj)−Δx2

6 ∇α+β 3u(xj)+O(Δx3), (49) where

α+2β u(xj) = 1

2(1+β)∂α+2u

xα+2(xj)+1

2(1−β) ∂α+2u

∂(−x)α+2(xj) (50)

α+3β u(xj) = 1

2(1+β)∂α+3u

∂xα+3(xj)−1

2(1−β) ∂α+3u

∂(−x)α+3(xj). (51)

Secondly, the operator∇αβuis approximated as previously and therefore

α+1β u(xj) = 1 Δx

δαβu(xj)+α(xj)−δαβu(xj−1)−α(xj−1) +b(xj)

= δα+β 1u(xj)+ 1 Δx

α(xj)−α(xj1)

+b(xj).

Then, it follows 1 Δx

α(xj)−α(xj1)

= 1 Δx

Δx2

12 +C2Δx2

α+β 2u(xj)+C3Δx3α+β 3u(xj)

− Δx2

12 +C2Δx2

α+β 2u(xj1)−C3Δx3α+β 3u(xj1)

= Δx2

12 +C2Δx2

xα+2β u(xj)+O(Δx3)

= Δx2

12 +C2Δx2

α+3β u(xj)+O(Δx3).

From this equality and (49) we finally obtain (44).

In the next result, we present the truncation error for the numerical method (31) obtained through the modified equation, which consists of substitutingthe exact solution in the numerical method and then after Taylor expansions and some additional calculations weget the local truncation error.

Theorem 4. For thenumericalmethod (31), the local truncationerroratun(xj)=u(xj,tn),appearing inthe global error (41), is givenby

ΔtTnj = Δxα+2 12

−μα−12C2μα−6νμα+6ν2μα

α+β 2un(xj)

+Δx4 24

2ν−2ν3−ν244un

x4 (xj)+Δx

2 μ2ααβ(∇αβun)(xj) +Δxα+3

6

−6C3μα−12C2νμα−3ν2μα+2ν3μα

α+β 3un(xj)+. . . , (52)

forμα=DΔtxαandν=VΔtx.

10

(12)

Proof. Substitutingthe exact solution in the numerical method, we obtain un+1junj

Δt +VΔt

x(unj+1unj−1)−1 2V2 Δt

Δx2(unj+1−2unj+unj−1)−Dδαβunj Δxα +V DΔtδα+1β unj

Δxα+1 −1 6

V

Δx−V3Δt2 Δx3

(unj+1−3unj+3unj1unj2)=0.

After Taylor expansions, the application of the results of Lemma 3 and some additional small simplifications, we can write

∂unj

tt 2

2unj

∂t2t2 6

3unj

∂t3t3 24

4unj

∂t4 +O(Δt4) + V

2Δx

⎛⎜⎜⎜⎜⎜

⎝2Δxunj

∂x +1 3Δx33unj

∂x3

⎞⎟⎟⎟⎟⎟

⎠+O(Δx4)

V2Δt 2Δx2

⎛⎜⎜⎜⎜⎜

⎝Δx22unj

∂x2 +Δx4 12

4unj

∂x4

⎞⎟⎟⎟⎟⎟

⎠+O(Δx4Δt)

−D∇αβunjD Δx2

12 +C2Δx2

α+2β unjDC3Δx3α+3β unj+O(Δx4) +V DΔt∇α+β 1unjV DΔtΔx

2 ∇α+β 2unj+V DΔt Δx2

6 −C2Δx2

α+β 3unj+O(ΔtΔx3)

−1 6

V

ΔxV3Δt2 Δx3

⎛⎜⎜⎜⎜⎜⎝Δx33unj

x3 −Δx4 2

4unj

x4

⎞⎟⎟⎟⎟⎟

⎠+O(Δt2Δx2)+O(Δx4)=0. Therefore, the modified equation isgiven by

∂unj

t +V∂unj

xD∇αβunjt 2

2unj

t2V2Δt 2

2unj

x2 +V DΔt∇α+1β unjt2

6

3unj

∂t3 +1

6V3Δt23unj

∂x3D Δx2

12 +C2Δx2+VΔtΔx 2

α+β 2unj +Δt3

24

4unj

t4 + VΔx3

12 −V3Δt2Δx

12 −V2ΔtΔx2 24

4unj

x4

−DC3Δx3α+3β unj+V DΔt Δx2

6 −C2Δx2

α+3β unj+

p+q=4

O(ΔxpΔtq)=0.

The modified equation presents an expression for the truncation error. However this is not the desired form since we do not want the truncation error in terms of the derivatives in time. Therefore, similarly to what is done in [30], weuse the modified equation itself to eliminate the time derivatives. After some extensive and direct calculations we obtain

unj

∂t +Vunj

∂x −Dαβunj+Tnj =0, (53)

where the modificationTnj satisfies Tnj = 1

12

DΔx2−12C2DΔx2−6V DΔtΔx+6V2DΔt2Δx

α+β 2unj +1

24

2VΔx3−2V3ΔxΔt2V2ΔtΔx2+V4Δt34u

∂x4unj+1

2D2Δt∇αβ(∇αβunj) +1

6

−6DC3Δx3−12C2V DΔtΔx2−3V2DΔt2Δx+2V3DΔt3

α+3β unj

+. . . (54)

Referências

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