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Lista 2. Distribui¸ c˜ oes condicionais: Caso cont´ınuo.

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Lista 2. Distribui¸ c˜ oes condicionais: Caso cont´ınuo.

Exerc´ıcio 1. A distribui¸c˜ao (densidade) conjunta deX eY ´e:

f(x, y) =aye−yxe−y, 0< x <∞,0< y <∞.

Para que f(x, y) seja realmente a densidade achar o valor num´erico do coeficientea. CalculeE[X|Y =y].

Exerc´ıcio 2. SejamX eY vari´aveis cont´ınuas com distribui¸c˜ao conjunta f(x, y) f(x, y) =e−(x+y), 0< x <∞, 0< y <∞.

1. AcharP(0≤X≤2).

2. AcharP(0≤X+Y ≤2).

3. Qual ´e a distribui¸c˜ao deE(X|Y)? (X eY s˜ao independentes?)

Exerc´ıcio 3. A densidade conjunta deX eY ´e:

f(x, y) =c(x+y), x, y∈[0,1].

1. Acharc.

2. Achar densidades marginaisfX(x) efY(y).

3. Vari´aveisX, Y s˜ao independentes? Justifique.

4. Achar queE[X|Y =y].

Exerc´ıcio 4. Um ponto ´e escolhido aleatoriamente no quadrado Q = {(x, y) : |x|+|y| ≤ 1}. Sejam (X, Y) as coordenadas desse ponto. Isso significa que a densidade conjunta ´e

f(x, y) =

c se (x, y)∈Q;

0 se (x, y)∈/ Q.

1. Achar valuec.

2. Achar distribui¸c˜oes marginais fX efY.

3. Usando item anterior reponder: as vari´aveis aleat´oriasX eY s˜ao independentes?

4. Encontre a densidade deX dado queY = 1/2.

5. Encontre a densidade deX dado que X+Y = 1/2.

Exerc´ıcio 5. (Wiki: “In applied statistics, the Marshall–Olkin exponential distribution is any member of a certain family of continuous multivariate probability distributions with positive-valued components. It was introduced by Albert W. Marshall and Ingram Olkin. One of its main uses is in reliability theory, where the Marshall–Olkin copula models the dependence between random variables subjected to external shocks.”)

SejamX, Y independentes e tem distribui¸c˜ao exponencial com taxaλ. SejaT = min(X, Y). AcharE(T |X =x).

isso para outros casos: ´E verdade, queE(T |X =x) = 1λ(1−e−λa)? e depois conformando, que isso ´e verdade, achar a m´edia de E(T), usando E(E(T | X)). Isso vai dar exatamente 1/(2λ) – a m´edia de minimum of duas exponenciais independentes com taxa λ

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