Geometric Measure Theory
Gláucio Terra
Departamento de Matemática IME - USP
August 12, 2019
Vitali’s Covering Theorem
5–times covering lemma
Definition (2.12)
LetX be a metric space,Fa collection of balls inX andA⊂X. We say thatFis afine cover A, or thatFcovers A finely, ifFis a cover ofA such that,∀x ∈A, inf{diam B|x ∈B∈F}=0.
Corollary (2.13)
Let X be a metric space, A⊂X ,F⊂2X a family of nondegenerate closed balls of X which covers A finely. Then there exists a disjoint subfamilyG⊂Fsuch that, for all F ⊂Ffinite, A\ ∪B∈FB⊂ ∪B∈G\F5B.
5–times covering lemma
Definition (2.12)
LetX be a metric space,Fa collection of balls inX andA⊂X. We say thatFis afine cover A, or thatFcovers A finely, ifFis a cover ofA such that,∀x ∈A, inf{diam B|x ∈B∈F}=0.
Corollary (2.13)
Let X be a metric space, A⊂X ,F⊂2X a family of nondegenerate closed balls of X which covers A finely. Then there exists a disjoint subfamilyG⊂Fsuch that, for all F ⊂Ffinite, A\ ∪B∈FB⊂ ∪B∈G\F5B.
Vitali’s Covering Theorem
5–times covering lemma
Proof.
Since the coverFis fine, we may assume that
sup{diam B|B∈F} ≤1; otherwise, discard the balls inFwith diameter>1, so that the remaining balls still coverAfinely.
TakeG⊂Fas in the previous remark. Letx ∈A\ ∪B∈FB. SinceF is finite,∪B∈FBis closed, hence there existsr >0 such that U(x,r)∩ ∪B∈FB=∅.
SinceFcoversAfinely, there existsB∈Fsuch thatx ∈Band diam B<r, so thatB⊂U(x,r), thusB∩ ∪B∈FB=∅. TakeB0∈G such thatB0∩B6=∅(henceB0 ∈/ F) and diamB <2 diam B0, so thatx ∈B⊂5B0. ThenA\ ∪B∈FB⊂ ∪B∈G\F5B, as asserted.
5–times covering lemma
Proof.
Since the coverFis fine, we may assume that
sup{diam B|B∈F} ≤1; otherwise, discard the balls inFwith diameter>1, so that the remaining balls still coverAfinely.
TakeG⊂Fas in the previous remark. Letx ∈A\ ∪B∈FB. SinceF is finite,∪B∈FBis closed, hence there existsr >0 such that U(x,r)∩ ∪B∈FB=∅.
SinceFcoversAfinely, there existsB∈Fsuch thatx ∈Band diam B<r, so thatB⊂U(x,r), thusB∩ ∪B∈FB=∅. TakeB0∈G such thatB0∩B6=∅(henceB0 ∈/ F) and diamB <2 diam B0, so thatx ∈B⊂5B0. ThenA\ ∪B∈FB⊂ ∪B∈G\F5B, as asserted.
Vitali’s Covering Theorem
5–times covering lemma
Proof.
Since the coverFis fine, we may assume that
sup{diam B|B∈F} ≤1; otherwise, discard the balls inFwith diameter>1, so that the remaining balls still coverAfinely.
TakeG⊂Fas in the previous remark. Letx ∈A\ ∪B∈FB. SinceF is finite,∪B∈FBis closed, hence there existsr >0 such that U(x,r)∩ ∪B∈FB=∅.
SinceFcoversAfinely, there existsB∈Fsuch thatx ∈Band diam B<r, so thatB⊂U(x,r), thusB∩ ∪B∈FB=∅. TakeB0∈G such thatB0∩B6=∅(henceB0 ∈/ F) and diamB <2 diam B0, so thatx ∈B⊂5B0. ThenA\ ∪B∈FB⊂ ∪B∈G\F5B, as asserted.
5–times covering lemma
Proof.
Since the coverFis fine, we may assume that
sup{diam B|B∈F} ≤1; otherwise, discard the balls inFwith diameter>1, so that the remaining balls still coverAfinely.
TakeG⊂Fas in the previous remark. Letx ∈A\ ∪B∈FB. SinceF is finite,∪B∈FBis closed, hence there existsr >0 such that U(x,r)∩ ∪B∈FB=∅.
SinceFcoversAfinely, there existsB∈Fsuch thatx ∈Band diam B<r, so thatB⊂U(x,r), thusB∩ ∪B∈FB=∅. TakeB0∈G such thatB0∩B6=∅(henceB0 ∈/ F) and diamB <2 diam B0, so thatx ∈B⊂5B0. ThenA\ ∪B∈FB⊂ ∪B∈G\F5B, as asserted.
Vitali’s Covering Theorem
Vitali’s covering theorem
Corollary (Vitali’s covering theorem for the Lebesgue measure;2.14) Let A⊂RnandFa collection of nondegenerate closed balls inRn which covers A finely. Then, for every >0, there exists a disjoint subfamilyG⊂Fsuch thatLn(∪G)≤Ln(A) +andLn(A\ ∪G) =0.
Corollary (filling open sets with balls with respect to Lebesgue measure; 2.15)
Let U ⊂Rnbe an open set andFa family of nondegenerate closed balls contained in U which covers U finely (for instance, ifFis the family of all nondegenerate closed balls contained in U, or the family of all such balls with diameters bounded by a fixedδ >0). Then there exists a disjoint subfamilyG⊂Fsuch thatLn(U\ ∪G) =0.
Vitali’s covering theorem
Corollary (Vitali’s covering theorem for the Lebesgue measure;2.14) Let A⊂RnandFa collection of nondegenerate closed balls inRn which covers A finely. Then, for every >0, there exists a disjoint subfamilyG⊂Fsuch thatLn(∪G)≤Ln(A) +andLn(A\ ∪G) =0.
Corollary (filling open sets with balls with respect to Lebesgue measure; 2.15)
Let U ⊂Rnbe an open set andFa family of nondegenerate closed balls contained in U which covers U finely (for instance, ifFis the family of all nondegenerate closed balls contained in U, or the family of all such balls with diameters bounded by a fixedδ >0). Then there exists a disjoint subfamilyG⊂Fsuch thatLn(U\ ∪G) =0.
Steiner Symmetrization
Notation
Notation for sections
ForE ⊂X ×Y and(x0,y0)∈X×Y,
Ex0 :={y ∈Y |(x0,y)∈E}(thex0-sectionofE);
Ey0 :={x ∈X |(x,y0)∈E}(they0-sectionofE).
Steiner Symmetrization
Definition (2.16)
Let(e1, . . . ,en)be the standard basis ofRn and identify
Rn−1≡ he1, . . . ,en−1i,R≡ heni, so thatRn≡Rn−1×R. We define the Steiner symmetrizationwith respect toRn−1to be the map
Sen :2Rn →2Rn defined by (see figure 1):
Sen(A) := [
{x0∈Rn−1|Ax06=∅}
{(x0,xn)| |xn| ≤ 1
2L1(Ax0)}.
Givena∈Sn−1⊂Rn, we define similarly the Steiner symmetrization Sawith respect to the(n−1)-dimensional subspacehai⊥: take any orthogonal mapφ∈O(n)such thatφ(a) =en(henceφ(hai⊥) =Rn−1) and put Sa:=φ−1◦Sen◦φ.
Steiner Symmetrization
Steiner Symmetrization
Definition (2.16)
Let(e1, . . . ,en)be the standard basis ofRn and identify
Rn−1≡ he1, . . . ,en−1i,R≡ heni, so thatRn≡Rn−1×R. We define the Steiner symmetrizationwith respect toRn−1to be the map
Sen :2Rn →2Rn defined by (see figure 1):
Sen(A) := [
{x0∈Rn−1|Ax06=∅}
{(x0,xn)| |xn| ≤ 1
2L1(Ax0)}.
Givena∈Sn−1⊂Rn, we define similarly the Steiner symmetrization Sawith respect to the(n−1)-dimensional subspacehai⊥: take any orthogonal mapφ∈O(n)such thatφ(a) =en(henceφ(hai⊥) =Rn−1) and put Sa:=φ−1◦Sen◦φ.
Steiner Symmetrization
Figure:Steiner Symmetrization
Steiner Symmetrization
Steiner Symmetrization
Proposition (properties of Steiner symmetrization; 2.17)
Let a∈Sn−1.
i) ∀A⊂Rn,diam Sa(A)≤diam A.
ii) If A⊂RnisLn-measurable, then so isSa(A)and Ln(A) =Ln Sa(A)
.
Steiner Symmetrization
Lemma (2.18)
Let f :Rn→[0,∞]beLn-measurable. Then
hyp f :={(x,t)∈Rn×[0,∞)|t≤f(x)} ⊂Rn+1isLn+1-measurable.
The isodiametric inequality;Ln=Hn
The isodiametric inequality
Theorem (isodiametric inequality; 2.19)
The Lebesgue measure of any subset ofRn is at most the measure of an euclidean ball with the same diameter. That is, for all A⊂Rn,
Ln(A)≤α(n)diam A 2
n
.
Exercise (2.20)
Show an example of a set A⊂Rnwhich is not contained in any ball with diameterdiam A.
The isodiametric inequality
Theorem (isodiametric inequality; 2.19)
The Lebesgue measure of any subset ofRn is at most the measure of an euclidean ball with the same diameter. That is, for all A⊂Rn,
Ln(A)≤α(n)diam A 2
n
.
Exercise (2.20)
Show an example of a set A⊂Rnwhich is not contained in any ball with diameterdiam A.
The isodiametric inequality;Ln=Hn
L
n= H
nTheorem (2.21)
For allδ∈(0,∞]and n∈N,Hn=Hnδ =LninRn.
Corollary (2.22) H-dimRn=n.
Proof.
Apply the stability with respect to countable unions of the Hausdorff dimension toRn =∪k∈NCk, where eachCk is a nondegenerate cube with finite Lebesgue measure, i.e. 0<Hn(Ck)<∞, so that∀k ∈N, H-dimCk =n.
L
n= H
nTheorem (2.21)
For allδ∈(0,∞]and n∈N,Hn=Hnδ =LninRn.
Corollary (2.22) H-dimRn=n.
Proof.
Apply the stability with respect to countable unions of the Hausdorff dimension toRn =∪k∈NCk, where eachCk is a nondegenerate cube with finite Lebesgue measure, i.e. 0<Hn(Ck)<∞, so that∀k ∈N, H-dimCk =n.
The isodiametric inequality;Ln=Hn
L
n= H
nExercise (2.23)
If E is a k -dimensional subspace of a normed space X , then H-dimE =k .